E to the log of 2 though doesn’t equal 2 on my calculator I’m so confused?
@christophernguyen175051 минут бұрын
I get that every 2 pi just gives the same angle but mathematically, it doesn’t make sense to me how you can just create a whole new solution by putting 2 pi, or something close to 6.28… at the bottom. I mean if n was 1000, then you’re basically ending up with a solution that tends to 0 and somehow that’s the same as if n was 1
@AchmadEuroWinrasaputraСағат бұрын
isn't it?????
@user-id3wn6nr7kСағат бұрын
Chat GPT recommends wolfram alpha lol
@iliabarani6766Сағат бұрын
Nice content man, it really helped
@FanisBartzisСағат бұрын
The whole difference could just be resolved if mathematicians just decided that we could do this f(x)^-1 = 1/f(x) f(x^-1) = f(1/x) f^-1(x) = invf(x)
@Tntaxolotl2 сағат бұрын
Imprieal College London, not Oxford.
@user-tn1kw6dc2g3 сағат бұрын
I dare you to put t=I do it
@formallogic17625 сағат бұрын
Thank you so much! This is a great video and helped me a lot!
@Adrian-zz2ut7 сағат бұрын
Can this be used for any integration problem?
@zachansen82939 сағат бұрын
You create a lot of confusion for people when you write "1" when you don't actually mean 1. When you actually mean either 1+ or 1-. Actual 1^inf is 1
@donlowell10 сағат бұрын
No. 92 should be x+1, not x-1.
@arkae2410 сағат бұрын
damn i thought i could do try this but i didn't learn integration by parts yet
@mattsains11 сағат бұрын
I think C is the worst because it’s the only one for which a different convention wouldn’t “fix” the wrong answer. 0.99… is always equal to one. But PEMDAS for example is a notational convention so you could invent RTL and say the answer to D is 1
@tommyle80613 сағат бұрын
Why can you use lnx to replace logx?
@pianoplayer123able14 сағат бұрын
I actually eliminated the x in the second example with (also I was curious what happens) making delta samller then 1. |x-5|<1 The follows -1<x-5<1. The comes 4<x<6 then 8<2x<12 then √14+4<√(2x+6)+4<√18+4 Then reverse: 1/(√14+4)>1/(√(2x+6)+4)>1/(√18+4). So I got 2*δ/√14+4 Wich led to δ= (ε/2)*√14+4 Then defining δ=min(1, (ε/2)*√14+4))
@MartinUnterhofer15 сағат бұрын
Can the "diagonal trick" in question 40. be used legitimately? From my understanding, it uses the commutative property which is not always true for infinite sums.
@boofe643116 сағат бұрын
I’m a math newbie but how would i^4 turn into the e^i2npi stuff ?
@TheTriviaGuy017 сағат бұрын
I would say d because it's just simple order of operations. B isn't really stupid but it's very easy when you just think of the problems or not overthinking it. B is +and- 1 because if you multiply the same numbers it still equals 1 (1x1=1, -1 x -1=1) D is more stupid because it is only hard for people who really don't see through the parenthesis as an alternative multiplication sign (it's 16 if the 3 was next to the 4 inside the parenthesis) so it would be 16.
@thetaomegatheta15 сағат бұрын
'B is +and- 1 because if you multiply the same numbers it still equals 1 (1x1=1, -1 x -1=1)' The radical sign usually refers to the principal root.
@TheTriviaGuy011 сағат бұрын
@@thetaomegatheta ik but thanks
@thetaomegatheta4 сағат бұрын
If you know that, then why did you claim that sqrt(1) is '+and- 1'?
@mio952517 сағат бұрын
1/3 = 0.333333... multiply both sides by 3 1 = 0.9999999...
@TazPessle17 сағат бұрын
@5:50. That graph becomes so hard to draw without losing meaning without context, could you just draw the y=x^2 graph, but have the first mark on the x axis at 1/[infinity] and placed wide.
@PFnove18 сағат бұрын
0^0 is 1 and 0 at the same time so it's undefined (x=1 and x=0 can't be satisfied at the same time) √1 is ±1 because (+1)(+1) is 1 and (-1)(-1) is 1 0.9999999 ... is 1 because you can find that its fraction is 9/9 which is equal to 1 12÷3(4) is bad notation but I'd solve it as 12÷12=1 (implicit multiplication first) None of these are debates since there are clear answers to the questions, it's like considering flat earth a debate
@thetaomegatheta18 сағат бұрын
'0^0 is 1 and 0 at the same time' Obviously not 'at the same time'. 'so it's undefined' When it is defined as 0 or as 1, it is obviously not undefined. '√1 is ±1 because (+1)(+1) is 1 and (-1)(-1) is 1' Usually, the radical sign will refer to the principal root.
@PFnove18 сағат бұрын
@@thetaomegatheta does that not make sense? You have x=0^n which is x=0 and x=n^0 which is x=1, put them in a system of equations and you need to find a single value of x that is equal to 0 and 1 at the same time (there isn't one)
@thetaomegatheta17 сағат бұрын
'You have x=0^n which is x=0 and x=n^0 which is x=1, put them in a system of equations and you need to find a single value of x that is equal to 0 and 1' There are obviously no solutions there for n > 0, and we give a special definition to 0^0. Usually it is defined as 1. It is obviously not defined in multiple non-equivalent ways at the same time.
@PFnove17 сағат бұрын
@@thetaomegatheta 0^0 is undefined, and replying to the other thing you said earlier, if √ only had the positive value as it's result you could prove that 2+2=0 Why is 0⁰ undefined? Well find me a value that is equal to 1 and 0 at the same time and we'll settle on that being the solution
@thetaomegatheta17 сағат бұрын
'0^0 is undefined' Unless it is given a definition in the relevant context. 'if √ only had the positive value as it's result you could prove that 2+2=0' Where's this proof of yours, then? 'Why is 0⁰ undefined?' It seems to usually be defined as 1. 'Well find me a value that is equal to 1 and 0 at the same time' Why should I? We specifically define 0^0 as 1 or we leave it undefined. We all know that it is impossible to define the functions f(x) = x^0 and g(x) = 0^x at x = 0 in a way that both of them are continuous. That doesn't prevent us from defining 0^0.
@denisnyantori366118 сағат бұрын
Thanx
@user-qg5lz1my1q19 сағат бұрын
And we have to remember it as result for mains 😂
@omololalove345319 сағат бұрын
Thanks
@paramrituraj129321 сағат бұрын
@blackpenredpen Hello sir, can you explain how to solve y'' + ky = 0 w/o trial and error? Some solutions i found online use laplace transform but i dont really get it! An explanation would really help of the solution and if required, what laplace transform is! Thank you!
@pigna_calda_official205823 сағат бұрын
Could someone tell me how to solve x+ln(x)=2 ? I keep getting x=W(e^2) but when i put it in WolframAlpha it says it's wrong :/
@Rikitaskar123 сағат бұрын
Personally i think 0/0 is undefined but i saw what wheel algebra says and "for me" if we should define 0/0 it should be the nullity, but i think it should remain undefined, at least if we talk about normal arithmetic, if we talk about limits, wheel algebra or anything else 0/0 changes
@Maths_WonderlandКүн бұрын
Calculate the integral of *log₂₇ 9 + log₈ 4* from *−(log₂ √6 + log₂ √⅔)* to *log₅ 50 − log₅ 2* . Please upload this sum’s solution. I have specially made it for you to solve.
@samhess78Күн бұрын
Math is my last resort of science. If math goes, science goes.
@samhess78Күн бұрын
A is clearly the worst. Mathematicians accept a contradiction while it is known, that anomalies are poison for math. B is also quite bad, but I can accept a little bit the distinguishment between functions and equasions. C is not a big deal and D is not even an issue.
@thetaomegatheta23 сағат бұрын
'Mathematicians accept a contradiction while it is known' This is nonsense. What 'contradictions' are you even talking about?
@samhess7818 сағат бұрын
0^0 being 1 and undefined at the same time. But let's check with Euler's formula assuming 0 is a complex number. But zero has no real and no imaginary part. Is it a number?
@thetaomegatheta18 сағат бұрын
'0^0 being 1 and undefined at the same time' This is nonsense. If, in a particular context, 0^0 is defined as 1, then it is not undefined. 'But zero has no real and no imaginary part' It does. Re(0) = 0 Im(0) = 0. 'Is it a number?' Yes. In particular, it is the additive identity of the field of integers.
@samhess787 сағат бұрын
@@thetaomegatheta OK, it seems zero to the power of zero is undefined. But why is it undefined? If zero is an ordinary number, why can we not apply the usual arithmetic rules and calculate the result of zero to the power of zero? In other words, why is the result of this calculation undefined? And is undefined a number? I think 0 might not be a number, at least it would be a very speciall one. The brother of infinity. Is infinity a number? I would say no. There are several types of infinity, hence it is not clearly defined. To qualify as a (complex) number, in my opinion an object under test has to have a finite real part and a finite imaginary part and the absolute value has to be greater than zero. The absolute value of 0*r +0*i is still 0. Therefore, it is not a number acoording the above definition. The reason for that is, that like infinity, zero is not clearly defined. Zero has indefinitly many instances, because the direction of the zero vector is not defined. Therfore we must sadly exclude 0 from the natural numbers. In order to avoid more conflicts in the future, any number should be defined as a*x + b*y + c*z. Integers: a*x, x can be omitted to it falls back to a Complex: a*x+b*y Spheric: a*x + b*y + c*z
@thetaomegatheta4 сағат бұрын
'OK, it seems zero to the power of zero is undefined' Unless it is defined in the relevant context. Usually it seems to be defined as 1. It's like you don't understand what the word 'undefined' means. 'But why is it undefined?' The primary motivation for leaving it undefined is that a bunch of relevant functions can't all be continuously extended to that point at the same time. 'If zero is an ordinary number, why can we not apply the usual arithmetic rules and calculate the result of zero to the power of zero?' How many times do you need to be explained that we can and do define 0^0? The motivation for leaving it undefined is that a bunch of functions can't be continuously defined at that point at the same time. 'I think 0 might not be a number' Well, you think wrong. It is the additive identity (I might have misspoken previously and called it the 'multiplicative identity' previously - will fix that if I did) of the field of integers. Integers are numbers. 0 is a number. 'The brother of infinity. Is infinity a number? I would say no. There are several types of infinity, hence it is not clearly defined' This is just nonsense. There is no element of any number field called 'infinity'. There are points that are called that or something similar in various extensions of number fields as topological spaces. When people say that there are 'different sizes of infinity', what they mean is that there is more than one infinite cardinal. None of the cardinals are called 'infinity'. All of this stuff is very clearly defined. 'To qualify as a (complex) number, in my opinion an object under test has to have a finite real part and a finite imaginary part and the absolute value has to be greater than zero' That's not what a complex number is, and you are just pulling the last requirement out of your ass. A complex number is a formal sum a+i*b, where a and b are real numbers and i is the imaginary unit with all the associated properties. 'The absolute value of 0*r +0*i is still 0' And? 'Therefore, it is not a number acoording the above definition' And nobody uses that definition, so this is ignorable. 'The reason for that is, that like infinity, zero is not clearly defined' This is nonsense. 0 is the additive identity of the field of integers. Nothing unclear about this. 'Zero has indefinitly many instances' This is just gibberish. You didn't even bother defining what an 'instance of zero' is. 'Therfore we must sadly exclude 0 from the natural numbers' 0 is often excluded from the set of natural numbers, but you provided no actual motivation or proof of the fact. That 'therefore' is misplaced. 'In order to avoid more conflicts in the future' What 'conflicts'? 'any number should be defined as a*x + b*y + c*z' This is nonsense. What are a, x, b, y, c, and z? 'Integers: a*x, x can be omitted to it falls back to a Complex: a*x+b*y Spheric: a*x + b*y + c*z' 'Spheric'? And where are quaternions, octonions, and other number algebras?
@jpcurley25Күн бұрын
Big fan but a boring conclusion considering what a high school algebra student should know about what a does to a quadratic
@Agus-of6rhКүн бұрын
Thanks for this easy videos. They help building confedence for the more difficult parts.
@kev-othegamerКүн бұрын
Thank you.
@maths_classes683Күн бұрын
Sir wonderful explanation Thank u sir
@lilisecretworldКүн бұрын
Is a² + b² = (a+b)² - 2ab not a commonly known formula?? Why derive it?
@mrrich1887Күн бұрын
DAAABLUE
@gibbogleКүн бұрын
L'Hospital's rule works fine - gives the right answer.
@Badhit2_noili_scotishgmarКүн бұрын
Solve this 3̸̛͉̰̟͔̱̌̔̂͆̃̈͆͗̀̿̀̋͆͌̍͐͆̑͗͜͝7̴̧̡̡̠͙̤̦̫͇̣̦͚̖̫͉͍͔̖̜͓̟͔̹̱̲̝̗͖̲͔̗̟͙̫̞̣̤̤̣̭̮̬͓̟̪̯̘̿̑͆͊͒́̿́̽̐͋̃͝2̷̢͎̹̗͕̜̘͙̪̃͐̔͒̇͑̑̒̉6̷͕̩̮͍̘͖͇̖͈͔̇̐̉̽̚̕2̵̡̬̝̝̫̼͙͙̰̟̣̗͕̘͚͉̦̱̙̹̣͉̙̖͈͈͎͙͔͓͖̹̖͍̗̿͋͑͐̓̔̑͋̋̽̈͑͌̎̓́͘͝ͅ+̶̡̧͕̬̗̝̘͎̟͉̳̳̩̪͚̗̰̳͉̥̲͙̭̾͌̑̌͌̄͌͋̀͌̿̅̀͆̈́̄̾͂̿̎̓́̓̏̃̎̽͘͝͝͝͝͝ͅ3̷̨̡̛͕̦̻̙̩̺̻̖͖̳͎͇̤͔̲̰̫̀̽̎̽̏͋͌̊̉͛̽͋̅̈́͆̕̕͝6̴̧̞̯͔̞͖̯̘͍̙̹͕̟̤̪̪̲͑͗͂̏̇͌̔͑̋̈́͊́͐̓̌͗̏͗̀̂̂̃̍͗̂̀̐̄͊̋̓̕̕̚͜͠͝͠͝7̵̢̡̛͈͔͚͓̖̪̯͖͚̳̳̖̰͓̳̬̭͙͓͉͎̞̯̘̰̝͔͈͙̹̙͚̥̟̝͚͍̦̏̾̿͑͌̈̇̆͗͆͗̓͋̑͜͜3̴̨̨͕͈͈̖̺̙̘͍̱̠̩͖̹͓͎͓͚̫̠̝̤͙̈́͒̽̎̿͗̾̈̎̎̀͛̽̂̓̂́̏̑̂͑͗̕͜͜͠͝7̵̥̯̳̙̥̩̖̝̲̙͙̠̈́͛̿̿̂͂͂̂̎̍̏̅͐͜2̴̛̰̥̰̥̮͛̽̆͛̈́͛̾͆̏̆̈́́͂̓̈́̇̃́̀̏͌̾̇͋͂̈́̈́̓͋̿̐̕͘͝͝x̶̢̢͇̭̬̱͚̱͇̘͙͔̜̼͇͎̳͉̬̩̳̟͇̳̦̭̲̪̦̙̙̻̲̩̳́̐͒͒̐7̶̢̢̢̧̛͖̣͓̬̠͎̟̦̰̤̰̟̖̙̹͉̥͍̖̳̬̦̣̠̼̳̳̃͗̑̏̈́̇̊͋̔̆͂̀̑́͆́̉̊͐̈̂͂̚͜͠͝ͅ2̸̥͍̝̪̬͓͓͗̊͐̈̅7̴̢̨̡̢̡̡̢̢͔͚̳͚̮̟̼̜̤̹̼̜̩̯̻̮̣̼͎̯͚̳̩͙̦̘͓̣̘͎̬̙͇̐̋͜2̷̧̡̛̦͍̗̥̺̖̠͚̩̥̠̼̰͚̟̼̼̟̤̼͇̺͖̭̤̜̳̬̖͍̝̣̹͎̎̾̎̈͑̅̀̓͂̕͝ͅ8̸̢̧̛̛̱̺̙͚͙̙͙̹͇̫̭̫̥͉̰͈̺̮̺̝̫̫͙͍͎̺̘̅͋̂̆̌͒̑̈́́̃̐̈́͂̓̊͌͊̉͗̇́̿͒̏̄̇̑̉̈́̚̚̚͠2̷͍͎̖̘̿̅̽̋̈̉̌̒̇͐́̋̍̓͐̔̿̒̎̐̆͆̑͋̽͐̈́̾͑͂̌͘̕͘̚*̴̨̧̗̯͉̖̫̖̈́͂̎̀̂̅̂̐́̊̈́̉̃͋͐͒̃̀̀͊̈͐̇͊̓́̓̍̚͘[̴̡̧̡̧̡͈̬͍̠͕̤͕̜͍̦̠̣̮̭̝̻̫̤͈̯̗̗̹̜̱̹̗͓͕̩͉̪̩̝͉͔̻͙͇̯̬̼́̐̈́̊͌̏̃̃̑̆̒̀͐̉͊̄̐̾̈̈̏̀̌̑͐̒̿̈̑́̈́͒̃̄̐̓̄̎̀̚̕͘̕͘̚͜͜͠͠͝͠ͅ1̴̡̰̱͚͉̰̱̳͙̜̱̜̬̼̹̮̆͐͛̀̽̉̊̃͜ͅͅ2̷̨̡̢̗͍̰̭̩̞̺̗̪͖̬͚̹̠̩̱̙̫̥̘̭͖̻̫̟̱̖̙̝͖͈̩̗̱̑͒̐̿̄̂̀̾͂̌̀͑͛̚͜3̶̛̼̝̳̞̭̜͔̼̤̻̲̟̻̥̖͇͉͕͉̙͍̜͖̯̞̠̯͓͓̯̻̫̬͖̯͔̮̇͒̑̍̌̓̽̿̓̒̇͐̂̍̎́͊͂̊͑̍͗̐̂͐̚̕̚͠͝͝ͅ4̶̢̧̡̨̛̛̲͓̬͇̳͓̼̰̫̯͖̬̮̟͎̩͉̞̤̝͉̼̙̰͓̗̼̪̖̞͈̟̗͓̺͖̱͎͊̒̈́̎̀̃̒̀̆̏̑̄̋͛̋̔́̐̒͆̃̔̀̾͗̊̍̓́͘̕̕͝͝͠͝͝3̴̰͇̝̙̯͉͓̹̳͕̂͋̄̇̏̑̆̊͂̒̔͂̈́͌̆̃̃̽̅͊̊̌̐̉͗̌̋̈́̇̚]̵̨̢̡̢̡͕̤͓̬̝̳͔͓̙̬̖̫̳͙̺̯̣͕̩͖̯͓̞͔̖̫̲̭͖̼͂̆̐̏̊͂̿̓̆́̆̐̔̈̋̽̑͒̅́͛̓͌̑̔̌͛͌́̉̑͋̒̔̾͘̕̚̕͘͘͜͜͝͝͝͝ͅ ̴̧̼̦̲̰͚̞͙̬̆̄̈́̍̈͆̂̏̓͐̅͐͝͝͠=̷̧̢̢̡͈̹͉̤̫̗̳̭͇͔̼̫͍͍̙̜̞̣̬͉̟͎͔̆̈́͊̂̋̀̔͑́̒̊́̃̽̾̇͐̃̍̓͆̉̚̕͜
@BrandenWang-hp7etКүн бұрын
I'm a fifth grader watching this. WTF is going on?
@BrandenWang-hp7etКүн бұрын
:)
@gibbogleКүн бұрын
But l'Hospital's rule gives the right answer. Why?
@b4594Күн бұрын
Circular reasoning. You need to know this limit to find the derivative of sinx
@heythere9380Күн бұрын
If one is good in calculus, then your gift is from Santa; if one is not good, then this came from Satan!
@rachidtanan3229Күн бұрын
ab>0
@soyezegamingКүн бұрын
b: i'm only constant after all, i'm only constant after alo don't put the blame on me
@justpotatoitКүн бұрын
Hey, can anyone give an intuitive answer to why this is cost+isint at pi/4+npi for n is an integer?
@vericubemveu5721Күн бұрын
The trigonometric way: write i as i=1(cos90⁰+i*sin90⁰) The 2nd root of that is r=sqrt(1)(cos(k*90/2)+i*sin(k*90/2)) =cos(k*45°)+i*sin(k*45°), where k=0 and 1
@maxleague4809Күн бұрын
Holy moly! All I have to do is use formulas!!
@GrassmplКүн бұрын
Limit DNE. The domain of the quadratic formula in a is bounded above.
@user-cq8jd8yc6bКүн бұрын
That was somethigh amazing and ridiculous and interesting