Calculus 6.08m - Examples 16 - 17
5:01
Calculus 6.08l - Examples 13 - 15
3:53
Calculus 1.2b - Interpreting a Graph
8:56
Calculus 1.1d - The word `Calculus`
3:20
Calculus 1.0a - Introduction
1:20
7 жыл бұрын
Calculus 6.08h - Examples 7 - 9
6:29
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@HaloWolf102
@HaloWolf102 19 сағат бұрын
Imagine missing, or not understanding this concept(how to use reciprocals), and trying to stack the rest of your public education in math on top of this incomplete foundation. Well, it crumbles. I barely made it through High School. I am 25, and I am finally going back through the basics. I had no idea.
@derekowens
@derekowens 14 сағат бұрын
Taking the initiative to go back and learn on your own what the schools failed to impart to you is time well spent. Respect.
@HaloWolf102
@HaloWolf102 11 сағат бұрын
@derekowens Well, it helps whenever you have passionate people that care about their teaching methods, and give that away for basically free. Kudos my man, you're amazing.
@سجاداحمد-م3ن
@سجاداحمد-م3ن Күн бұрын
Wow in 2009 I was in 3 years of my life and my bro born in the 2009 … ! That is very creazy and now I study from this video 😮
@MarioVladutTino
@MarioVladutTino 4 күн бұрын
I know in practice is not useful, but does this mean that when you are doing a limit of the divsion of two polynomials and there is the same numerator and denominator, you can still apply hopital even though is not indetermination? I repeat, I know this is not practical since the straight away answer would be one, I am just saying that Hopital could be applied too. I say this beacause what you explained in the video happens will always happen as long as the functions cross paths
@Johnweely
@Johnweely 9 күн бұрын
Can there be a problem where the remainder is not a quadratic, if so, what do you do instead of factoring to find the remaining x.
@florentinosanchez3969
@florentinosanchez3969 9 күн бұрын
GREAT VIDEO IT HELPED ME A LOT
@martian.07unfiltered
@martian.07unfiltered 9 күн бұрын
Great video, here again watching after 6 years
@linstrafamily
@linstrafamily 12 күн бұрын
First comment in 3 years
@sachinrath219
@sachinrath219 20 күн бұрын
at 10 secs, the graph seems to be non differentiable, so hope velocity is indeterminate
@sachinrath219
@sachinrath219 20 күн бұрын
will the area function always start from the origin
@Lawh
@Lawh 20 күн бұрын
Still relevant
@massoomaalrshim2244
@massoomaalrshim2244 23 күн бұрын
Thank you so much, you've made so clear to me. I truly appreciate it
@jamesleerssen1089
@jamesleerssen1089 25 күн бұрын
Incredible
@silencecreeping
@silencecreeping 27 күн бұрын
You, sir, have a lovely channel organization.
@Roba-b1n
@Roba-b1n 28 күн бұрын
🎉
@glasssmirror2314
@glasssmirror2314 28 күн бұрын
With all respect sir I did not understand this lecture as things were mixed up though I know diff is the opp of interg
@Shonade_Malik
@Shonade_Malik Ай бұрын
For a video almost as old as me, this was pretty easy to understand. Thanks!!
@ElectraBard-h3d
@ElectraBard-h3d Ай бұрын
Gonzalez George Davis George Garcia Mary
@derekowens
@derekowens Ай бұрын
Hi, folks!
@anniemonroe9285
@anniemonroe9285 Ай бұрын
I'm so lucky I stumbled upon your channel. Nothing, (and I mean nothing) was clicking until I watched your videos. You have a gift, Derek.
@successquotes3143
@successquotes3143 Ай бұрын
Great explanation sir
@Jannatu.Al.Firdaouse
@Jannatu.Al.Firdaouse Ай бұрын
Thank you so much ❤❤
@joevelte4252
@joevelte4252 Ай бұрын
very nice
@danmike2305
@danmike2305 Ай бұрын
Derek Owens is a top-notch instructor
@Kidshappiness2022
@Kidshappiness2022 Ай бұрын
It does not make sense
@AngelReyna-wd5kg
@AngelReyna-wd5kg Ай бұрын
you deserve more attention this is the best man
@Endless-hopee
@Endless-hopee Ай бұрын
Thank you ❤
@voteforhamsandwich1112
@voteforhamsandwich1112 Ай бұрын
hey man, do you still read comments?
@derekowens
@derekowens Ай бұрын
Yes!
@voteforhamsandwich1112
@voteforhamsandwich1112 Ай бұрын
​@@derekowens i wanted to thank you for helping me with a question i had 10 - 15 years ago. It was back when KZbin had an inbox. I asked you how to find a point of intersection given a point (x, y) and a line (x1, y1) and (x2, y2). When the point drops a "shadow" under 90 degrees on the line. Not sure if you understand my explanation. But i vaguely remember KZbin had an ability to show drawings. So you understood my poor English back then. Nothing special came out of that formula. i used it to make a silly game. But its the memory that i really value. Thank you for helping me back then xD
@derekowens
@derekowens Ай бұрын
@@voteforhamsandwich1112 Wow, thanks for that encouraging note. It's very nice to be remembered, even after all this time, and I'm glad I was able to help some. Hope you're doing very well!
@josephpicano1692
@josephpicano1692 Ай бұрын
I'm seeing this the other way around. energy level is higher the closer it gets to nucleus it's caused by how it's interacting with each other
@michaelmalgioglio1532
@michaelmalgioglio1532 Ай бұрын
thank you
@Holl4w
@Holl4w Ай бұрын
This helped me so much 😅 Wasnt understanding anything in Honors Algebra 2 but this helped me understand! Thank you so much!!
@Maritakira
@Maritakira Ай бұрын
Thank you, this was very helpful 💯
@SomeGuyOfYT
@SomeGuyOfYT Ай бұрын
erm wattesigma
@refreey
@refreey 2 ай бұрын
How does this tie in with indicators in chemistry?
@MugishaDerek
@MugishaDerek 2 ай бұрын
Thank u
@gabrielrojas8718
@gabrielrojas8718 2 ай бұрын
Bravooo!
@seancheah6923
@seancheah6923 2 ай бұрын
Very cool stuff even in 2024. Your explanation was FRICTIONLESS, to say the least!
@darcy4522
@darcy4522 2 ай бұрын
I did it a bit differently. I started by finding the time for half at peak height and then multiplied that by two to use for the horizontal distance and got 49m. Then, I worked out the peak height which I got as 12.3 m. Should we always approach these questions starting the way u did and working out the time for the distance asked?
@Robert-d5l
@Robert-d5l 2 ай бұрын
Bernoullis principle does not state that as the velocity of a gas Increases the pressure decreases. Rather the pressure decreases perpendicular to flow and opposite to flow, but Increases in the direction of flow, ending up with the same net pressure energy. You have use this caviot that bernoulli included in his principle.
@Robert-d5l
@Robert-d5l 2 ай бұрын
The difference is pressure doesn't cause a force. Rather the difference is pressure is a force. You don't cause a pressure difference and get lift. A pressure difference is lift. Also, the airfoil shape does not cause a lift force. The shape causes efficient use of the force, but is not it's cause. Further, the most efficient shape changes with airspeed. A shape that is more efficient at one speed is less efficient at a different speed. To get a lift force upward, you accelerate air downward.
@NahBruh1232
@NahBruh1232 2 ай бұрын
How tf yall know which laws to use bruh
@nd_adam19
@nd_adam19 2 ай бұрын
W video
@danmike2305
@danmike2305 2 ай бұрын
Always enjoy your mathematical knowledge.
@mscovers8789
@mscovers8789 2 ай бұрын
🙏🙏
@MuhammedSillah-d1h
@MuhammedSillah-d1h 2 ай бұрын
Thank you
@MRiaz-sv2ee
@MRiaz-sv2ee 2 ай бұрын
Aslamo alaikum sir iss ka along x axis answer kua ata ha
@savoylunsford3023
@savoylunsford3023 2 ай бұрын
But why what real world purpose does this have
@harmindersingh-rv5wb
@harmindersingh-rv5wb 3 ай бұрын
sorry bro u didn't help at all
@HebaKanfosa
@HebaKanfosa 3 ай бұрын
Thank you so much . Now i just have understood calculus.. a gain thank you till tomorrow morning.. Mohammed from Libya 🇱🇾🇱🇾
@doctari1061
@doctari1061 3 ай бұрын
Good explanation
@vynneve
@vynneve 3 ай бұрын
bad proof. that's wayyyy too "hand wavy". "dividing" by the infinitesimal dx to get the derivatives in there is just terrible form for a proof. technically does work (if you took some extra steps within that) but there is a much better way, just start with the derivative side, and apply the definition of derivative. (wont write various limits, should be implied) f'(x)/g'(x) = (f(x+h) - f(x))/(g(x+h) - g(x)) (the two denominator h cancel out) We can now evaluate the second terms at a (the lim to be calculated, h is also going to zero remember). But since we are assuming form of 0/0, f(a)=g(a)=0 so, = (f(x+h) - f(a))/(g(x+h) - g(a)) = f(x+h)/g(x+h) = we can now put 0 for h = lim x->a f(x)/g(x) as expected. Much easier imo, and objectively less messy of a proof.
@derekowens
@derekowens 3 ай бұрын
It is worth noting how rapidly these ideas took hold. The writings of Newton and Leibniz were adopted by the academic community almost in real time as they were developed. Newton was still alive and had not yet even moved to London when Bernoulli was writing about this rule, less than a decade after the publication of the Principia. And all of this was well over century before Cauchy began to formalize the theory of limits, and a full century and a half before Weierstrass. The point here is that a formal proof involving limits is actually unnecessary. History actually demonstrates this, as neither Newton nor Leibniz, nor anyone else at that time, used limits. Yet they *understood* these ideas and what these infinitesimal quantities represented. And if one understands this, then one understands when one can or cannot divide by dx. It was a conscious choice to approach the theorem this way, without the use of limits. The deliberate aim here is an *intuitive* proof, which I believe can make the concepts more clear and the understanding deeper. For another example, consider what Leibniz wrote to Wallace: "It is useful to consider quantities infinitely small such that when their ratio is sought, they may not be considered zero, but which are rejected as often as they occur with quantities incomparably greater. Thus if we have x + dx, then dx is rejected. Similarly we cannot have x dx and dx dx standing together as x dx is incomparably greater than dx dx. Hence if we are to differentiate uv, we write d(uv) = (u+dv)(v+dv) - uv = uv + vdu + udv + du dv - uv = v du + u dv" Where did the du dv go in this "proof"? If you understand the nature of these infinitesimal quantities, it makes complete sense. And then you can divide by dx on both sides and you have what we call the Product Rule.
@EvanLoper-tl9qj
@EvanLoper-tl9qj 3 ай бұрын
Does this apply to space? And light with distances so massive.
@derekowens
@derekowens 3 ай бұрын
Yes, it certainly does. You can think about the amount of light per square meter landing on earth and compare that the light per square meter landing on Mars, farther away. And on out to the more distant planets and beyond.