Ewald's sphere
12:38
3 жыл бұрын
Reciprocal of FCC lattice
8:16
3 жыл бұрын
Reciprocal of a BCC lattice
8:25
3 жыл бұрын
Primitive Unit Cell of a BCC Lattice
11:05
Bragg's law in Reciprocal Space
15:09
Properties of G*HKL
18:53
3 жыл бұрын
Reciprocal Lattice Definition
17:20
3 жыл бұрын
Liquid Nitrogen Experiment
6:11
3 жыл бұрын
Пікірлер
@apurba005
@apurba005 13 күн бұрын
It is was wonderful lecture/talk with real examples of plane group.
@Dr_Semalti
@Dr_Semalti 21 күн бұрын
Sir, can you explain why the pattern are in circle when we see selected area electron diffraction pattern
@soumyadeeppradhan
@soumyadeeppradhan 23 күн бұрын
NICE
@Dr_Semalti
@Dr_Semalti 24 күн бұрын
Extremely happy with this. Thankyou so much. I have been searching this for soo long
@soumyadeeppradhan
@soumyadeeppradhan 29 күн бұрын
awesome lecture
@vanshikasingh2631
@vanshikasingh2631 Ай бұрын
Really easy explanation....🙏
@shubhamingale
@shubhamingale Ай бұрын
Why do we just take a section and say that it's the diffraction pattern? Don't we have to construct an Ewald's sphere and then find kd for the direction of the diffracted beam? Can someone please help?
@scientificnature
@scientificnature Ай бұрын
Sir please also make a video on unit cell of a structure with ball to visualize
@1800llccll
@1800llccll 2 ай бұрын
My professors are so bad at explaining... They always skip the explanation... But you sir... Bravo... You make even a plebian like me understand perfectly!!
@RokyDas-i9f
@RokyDas-i9f 2 ай бұрын
He made materials science easier. Thnk u professor
@lutfunnahar8249
@lutfunnahar8249 2 ай бұрын
Nice :)
@ice11281
@ice11281 2 ай бұрын
just fantastic, Ewald sphere remained elusive in my physics course, until now that you explained it in a couple of minutes! But I think there is 1 mistake: the length of G*hkl vector should be 2pi/dhkl instead of just 1/dhkl, in order for the scattering condition G*T = 2 pi m, where m is integer and T is lattice vector, to hold. Correspondingly the length of CO or any other of those scattering vectors has to be 2 pi / lambda instead of just 1/lambda
@rajeshprasadlectures
@rajeshprasadlectures 2 ай бұрын
Actually there are two different conventions which are used. I am using he convention most commonly used in crystallography text. Here the reciprocal lattice vectors and the wave vectors are defined without the factor 2 Pi. Thus reciprocal basis vector a*=bXc/V, b*=cXa/V, c*=aXb/V and k=1/lambda. Correspondingly, G*_hkl = 1/d_hkl. The other convention is used most commonly in physics texts where the factor 2 Pi is introduced in the reciprocal lattice vectors and the wave vectors. Thus a*= 2 Pi bXc/V, b*= 2 Pi cXa/V, c*= 2 Pi aXb/V and k=2 Pi/lambda. Correspondingly G*_hkl = 2 Pi/d_hk. So physicist's reciprocal lattice vectors, wave vectors and the radius of Ewald sphere are all linearly expanded by 2 Pi in comparison to the corresponding quantities of the crystallographer. However, if a crystallographers reciprocal lattice vector lies on the his/her Ewald sphere then a physicist's reciprocal lattice vector will also lie on his/her Ewald sphere. Thus both will agree whether in a given experimental setting diffraction happens or not.
@ice11281
@ice11281 2 ай бұрын
@@rajeshprasadlectures okkay, good
@anthonycarlossalazarbs4671
@anthonycarlossalazarbs4671 2 ай бұрын
excellent video!
@avigyanbose5197
@avigyanbose5197 3 ай бұрын
Keep up the good work Sir We need more academicians like you
@lagrangegreen8256
@lagrangegreen8256 3 ай бұрын
3:07 Sir, is there a typo for a2*=a1xa3/Vp? The cross product calculated I get in this way is the opposite number of a2*. Should it be a2*=a3xa1/Vp?
@rajeshprasadlectures
@rajeshprasadlectures 3 ай бұрын
Yes, I made a typo here. You are right. Thanks for pointing this out.
@afafsgdchdhdg
@afafsgdchdhdg 3 ай бұрын
Very very good explanation.
@mohdzaki4194
@mohdzaki4194 3 ай бұрын
A complete assignment could be created around each monument! What a way to learn! Professor you are awesome!
@nazishahmad1337
@nazishahmad1337 3 ай бұрын
Can anyone tell how this type of simple videos can be made ?
@rajeshprasadlectures
@rajeshprasadlectures 3 ай бұрын
For this one I have just used powerpoint.
@ashantinicas
@ashantinicas 3 ай бұрын
when you want study materials go to prof prasad
@expnl
@expnl 4 ай бұрын
determine the angle between the primitive vectors in bcc structure
@rajeshprasadlectures
@rajeshprasadlectures 3 ай бұрын
Since the primitive vectors of a BCC are along the body diagonal of a cube, these angles can be easily calculated as cos^-1 (-1/3) =109.5 Degrees.
@ashantinicas
@ashantinicas 4 ай бұрын
materials engineering by prof.rajesh prasad is amazing
@smilecreation78
@smilecreation78 4 ай бұрын
Sir in what special case we can make bct unit cell as fcc ?
@rajeshprasadlectures
@rajeshprasadlectures 3 ай бұрын
BCT with c/a = Sqrt [2] will actually be an FCC. This is another example of why crystal systems should not be defined simply by their lattice parameters. So, to avoid this case you will have to say that for tetragonal system is one with a=b.NE.c as well as for BCT c.NE. Sqrt [2]. This sort of conditions will soon make definitions based on lattice parameters very messy.
@smilecreation78
@smilecreation78 3 ай бұрын
@@rajeshprasadlectures thank you sir
@ashantinicas
@ashantinicas 4 ай бұрын
if you need to understand materials go to prof .rajesh prasad
@JK-kh1co
@JK-kh1co 6 ай бұрын
Dear Professor, I have a simple question: The Kroneker's delta is defined based on the cubic system? I don't get 1 from dot product of the vector a and the vector a* in parallelopiped and in any other lattice systrm not having the angle of 90 degree between the basis vectors in real space.
@rajeshprasadlectures
@rajeshprasadlectures 6 ай бұрын
Kronecker's delta is just another name for the unit matrix. In the unit matrix only the diagonal terms are unity and all off-diagonal terms are zero. Similarly for kronecker's delta delta_11=delta_22=delta_33=1 and delta_12=delta_21=delta_13=delta_31=delta_23=delta_32=0. Thus ai. a*j=delta_ij is just a short way of writing nine dot products a1.a*1=1; a1.a*2=0; a1.a*3=0; a2.a*1=0; a2.a*2=1; a2.a*3=0; a3.a*1=0; a3.a*2=1; a3.a*3=1; The above relations are true for all systems and not only for cubic system. Note that we are not requiring a1.a2=0 which is true for orthogonal system (cubic, tetragonal and orthorhombic) but not for a general parallelopiped. We are requiring a1.a*2=0 where a*2 is a basis vector of reciprocal lattice and is not the same as a2. So by the relation a1.a*2=0 we are requiring that the second basis vector (a*2) of the reciprocal basis is orthogonal to the first basis vector (a1) of the real lattice. Hope this clarifies.
@sollyismail1909
@sollyismail1909 6 ай бұрын
Brilliant! You an excellent teacher! Congratulations!!
@me0wAnna
@me0wAnna 7 ай бұрын
thankyou you saved my life
@mkrish1977
@mkrish1977 7 ай бұрын
Thanks for your time and effort for making such wonderful videos for young and old minds. We can only request you to keep doing more such videos.
@dariuschong4574
@dariuschong4574 7 ай бұрын
You handwriting is beautiful 😍
@iandvaag
@iandvaag 7 ай бұрын
Fantastic explanation, very clarifying. Thank you!
@Taramonmerion
@Taramonmerion 8 ай бұрын
Bite me ... literally can't understand anything
@rajeshprasadlectures
@rajeshprasadlectures 3 ай бұрын
Sorry indeed. I fail.
@RBadrinathrao
@RBadrinathrao 8 ай бұрын
Thank you Sir for this interesting video
@rhymz2049
@rhymz2049 8 ай бұрын
I dont comment very often, but damn. This channel is an absolute gem! Neither books nor lectures, nor other videos have explained matters this clear
@stazpozarnastrup5522
@stazpozarnastrup5522 8 ай бұрын
Shouldn't the product of ai* and aj vectors be delta(ij) times 2pi?
@rajeshprasadlectures
@rajeshprasadlectures 8 ай бұрын
This is purely a question of convention. The convention used by me is preferred by crystallographers where ai*aj=delta_ij. The convention often used by physicists is ai*aj*=2pi delta_ij. One can use either convention.
@stazpozarnastrup5522
@stazpozarnastrup5522 8 ай бұрын
@@rajeshprasadlectures thank you a lot, now everything is clear
@supriyakalindi9669
@supriyakalindi9669 9 ай бұрын
Thank you sir.
@jahanvichaudhary81
@jahanvichaudhary81 9 ай бұрын
Thank you
@nibeshnandi2822
@nibeshnandi2822 9 ай бұрын
sir your lectures are so great. In india this is the best course ever on material science . once I want to meet you sir. Sir if possible I am eager to do some internship/project with you sir . Now it has become dream to meet you Rajesh sir. Love from students community teachers like are the best ❤.
@keshavbuliaiit-b3772
@keshavbuliaiit-b3772 9 ай бұрын
only if our professor could have been like you :/
@qmtv5772
@qmtv5772 10 ай бұрын
amazing
@roydcc
@roydcc 10 ай бұрын
Awesome🤩
@sheelatkalkandha4890
@sheelatkalkandha4890 10 ай бұрын
Nice explanation
@knightarora
@knightarora 10 ай бұрын
Interesting...
@सागरबड़थ्वाल
@सागरबड़थ्वाल 10 ай бұрын
hi sir
@Yashhh02
@Yashhh02 10 ай бұрын
Hello dear Sir, I really loved your introductory lecture on Material Science Branch at IITD, I'm really certain that I would Choose material science only its so interesting !! I have my JEE Advanced in a few months, I will work really hard to be able to meet you in person. please bless me, I'll be there soon. Dhanyawaad 🙏
@SFYN..
@SFYN.. 10 ай бұрын
Very much looking forward to this
@rupamghosh2020
@rupamghosh2020 10 ай бұрын
Very interesting
@ParasKaushik-r9k
@ParasKaushik-r9k 10 ай бұрын
sir please continue this series
@019_showkatrashid4
@019_showkatrashid4 11 ай бұрын
exceptional and unique way of teaching ❤❤
@moumitapaul2345
@moumitapaul2345 11 ай бұрын
sir , I have seen some videos where 32 crystallographic point groups are mentioned, but in this video you have explained 7 point group symmetries .what are the differences between these two?
@rajeshprasadlectures
@rajeshprasadlectures 11 ай бұрын
Crystals (lattice+motif) can have 32 point groups. Lattice alone can have only 7 point groups.
@Pkshah420
@Pkshah420 Жыл бұрын
Sir truly speaking I am a big fan of yours. Without you I could not have learnt crystallography so well. These lectures silently helping students. For your information I asked the same question to chat GPT. And it says,yes hcp is a Bravais lattice😂 So we should not believe chat GPT😂