15.1: Double Integrals over Rectangles

Objective:
1. Define the double integral of a function of two variables.

[@1999Joseph1]

thank you so much, your channel has helped me through this whole semester and I genuinely really appreciate you !

[@miguelzavala1757]

Much much better than my current calculus 3 class, should've watched since the beginning already took my first midterm :/

[@danieljohns1318]

I just found u and I'm sending all my friends to u now! Our profs this semester just can't get the online stuff to work and so the teaching has been....anyways, thank you!

[@johnklemmensen1803]

I've been quarantined for 2 weeks without notes given to me and this channel has saved my life i swear

[@charliebases7516]

i take this in hs and i don’t learn it from my teacher. I heavily rely on this lady

[@sohamsantra7548]

You having 10.1K subscribers is too criminally low. You deserve at least 3M subscribers!!

[@stasanstasaynovich23]

10/10 lectures

[@Howzernn]

I think you're a good teacher! And your class seems to like and respect you, even though I cannot see them.

[@alyssajewell720]

at 13:41 did you mean to make the x coords 1 0 . if so could you explain why

[@alexandraniedden5337]

Nope, I definitely meant 1 and 2. Good catch!

[@crisantogarcia6646]

how did you get 4 for h on 20:45

[@iced751]

For real, I'm so lost with this one

[@MelpeCavales]

@@iced751 y is between -2 and 2

[@vivekvardhanmaharana7248]

It really helps. Yhank you soooooooo much for this. I really hope i get to meet u someday

[@danielhernandez-vo9zc]

You're amazing, thank you so much for this

[@GULLAPUDILIKITHBCE]

19:41 I didn't understand that graph can you plz explain?

[@sakshitodkar]

thank you soo much for your video, it did really help me a lot

[@humayratuba6251]

Where did 1/3 go in ex #4?

[@iced751]

20:52 where did you get a height of 4?

[@humayratuba6251]

I didn’t get that too.

[@MelpeCavales]

y is between -2 and 2, a length of 4, height of the solid which is half of a cylinder

[@kyleparsotan6799]

15.8?

[@rijultandon728]

Legend 🤍

[@MuhammadAwais-br3ji]

Mam plz solve exercise

[@varnasuthansrirangan]

Thanks ❤️

[@joenardprime3662]

at 20:45, how did you get that the radius is 1?

[@alexandraniedden5337]

x^2 + z^2 = 1 is a circle with center at (0, 0) for (x, z) and r = 1. Remember that in the standard equation of a circle, we have (x - h)^2 + (z - k)^2 = r^2 (so that 1 in the equation is r^2).

[@danieljohns1318]

What is the name of the book you are using?

[@dheemianch8050]

Stewart calculus

[@Salamanca-joro]

Thomas calculus 13 edition

[@muhdameerulameen604]

Thankyouu :')

[@benjaminandrew7940]

35:05 I don't understand how it is not { y^2(cos(xy)) dy

[@benjaminandrew7940]

just realized thats the derivative

[@iced751]

I'm wondering why it's not -xycos(xy). Cause we're focusing on dx, so shouldn't the anti-derivative of y should be x? Cause don't we treat y as a constant?

[@spacebutterflies2456]

23:40 isnt the anti derivative of x^2 = x^3/3 ?

[@spacebutterflies2456]

Where did we get the half from?? 1/2

[@spacebutterflies2456]

oooh nvm its y^2/2 so we took out the half and put it at the back front gotcha

[@kfjfkeofitorhf9520]

X^2===X^3/3== 3X^2===X^3 X=3 9====27/3 9======9

[@sozamb]

While the lecture is generally nice, the professor is profoundly egotistical. Clearly she cannot stand if students are not engaged with her monotone lecture and does not have the capacity to understand that students have been taught different semantics with different notations in the past and refuses to accomidate this or at least understand the differences in notation and blatently disregards her students complaint against using different notation that might further confuse them.