15.5: Surface Area

[@daniloenriquealvaradoherna403]

Hello, can you explain, why did you put down x when you are in dy, the exercise number 1 of the video.

[@alexandraniedden5337]

I put a few steps together rather than showing my work. When you complete the first integration, you should end up with y*sqrt(4x^2 + 5). Then using those limits of integration from 0 to x for y, this substitution gives x*sqrt(4x^2 + 5).

[@muzzammilyousuf2265]

Which book do you use to find the questions or from where? it'll be a great help to practice more

[@alexandraniedden5337]

I use Stewart's Multivariable Calculus (8th edition) :) I have previously used Anton-Bivens-Davis Multivariable Calculus, which is a great resource as well.

[@muzzammilyousuf2265]

ok thanks alot

[@danishdar2718]

Vector normal to the surface z=1-x^2-y^2, Z>=0 will be

[@RAJ_IITIAN1]

Excellent explanation ❤

[@hidayatsiddiqui3074]

You...did in very shortcut madam..., Where all those steps gone

[@jamesgersbach1223]

Stop complaining

[@mmq6525]

The steps she skips are trivial and already understood by her students

[@joshuageorge7997]

For the definite integral with U-Sub, wouldn't you have to change the bounds for the integral?

[@greensparkles6796]

You could and keep the value as u^3/2 from 5 - 9, or keep the expression in terms of X and keep the bounds 0 - 1. You will ultimately end up with the same thing.

[@ruwaqatmash8543]

for example two of surface area why is the boud of the polar intergral not from -3 to 3 instead of 0 to 3 at 8:54

[@alexandraniedden5337]

We consider r to be positive, hence our radius extends from 0 (the origin) to 3.

[@ahmedmagdyelmedany1678]

Can we find the surface area for ellipsoid X2/a2+Y2/b2+Z2/c2=1

[@minguyen6743]

your examples are excellent. i have a question to ask though. i don't know how to present a point in the three coordinate planes. so when you draw the figure for z=9 i get confused. i know i need to know how to draw the objects to find the interval of r as well as theta angle - yet i have no clue to draw when it relates to z-plane. can you please give me some sources (youtuve video, pdf files,...) that teach how to do that? i have searched in the internet ever since last year but still don't get the answer. since you draw it so smoothly i would like to ask you for a favour. thank you

[@alexandraniedden5337]

Hello! Here is a video where I teach graphing quadric surfaces: kzbin.info/www/bejne/foWWY5yZfayfbM0. This may help with graphing the complicated figures. Good luck!

[@عطاالدهامشة-ع8ح]

Find the surface area due to the rotation of the area between f(x)=x^3 and g(x)=x

[@kshitijmehta3959]

Regards mam, i really love your videos and explanation. Can you please also make a video for 15.8

[@johnsears5350]

Is it possible to analytically solve the surface area of a elliptic paraboloid? An example would be z=x^2+4y^2, or does a have to equal b in the formula for the shape to be solved by hand.

[@alexandraniedden5337]

a does not have to equal b. You can still use the formula.

[@bruceallenbieren5138]

is your formula applicable to all surface area for parabolloid?

[@alexandraniedden5337]

Yes!

[@Swish-Stories]

I dont understand how you got 4pi/3 in the end. After integrating 2 dtheta from 0 to 1, I got 2. Then integrating that I ended up with 8. What am I doing wrong?

[@alexandraniedden5337]

We need to change the limits of integration - the 0 to 1 are the limits for x, not theta. Substituting 0 and 1 into x = 2sin(theta) and solving for theta, we get theta = 0 and pi/6. The outer limits of integration are okay, but the inner should be 0 to pi/6. I apologize for the poor notation!

[@Swish-Stories]

@@alexandraniedden5337 Thank You!

[@Swish-Stories]

@@alexandraniedden5337 Also do you have a video of 15.8 or if you know of a video that has the same content?

[@danavanesa9630]

Why do you use 3 as the limit?

[@alexandraniedden5337]

Are you referring to example 2? Around 8:40? Assuming so, I switched from rectangular to polar coordinates. The inner limits of integration refer to the radius, r, of the circle. The upper circle is x^2 + y^2 = 9, so the radius ranges from 0 (at the origin) to 3 (at z = 9).

[@danavanesa9630]

@@alexandraniedden5337 So instead if the height of the paraboloid was b and the radius was a, then the limit would be a or root square of b?

[@danavanesa9630]

this meaning z=b and the radius = a

[@alexandraniedden5337]

@@danavanesa9630 In the case you are describing, a = sqrt(b), so the upper limit of integration could be a or sqrt(b).

[@hessahalamhouj5588]

how did you get y=x in ex#1?

[@mmq6525]

point 0,0 to 1,1. you can do slope formula to get m and just y-y1 = m(x-x1) to get the formula, but it's pretty obvious because it goes from 0,0 to 1,1 and is a straight line that the equation is y=x

[@gouthamyadav3021]

hi at last two steps explain ones video time is 6:00

[@mominazhar7275]

Which book youre following ?

[@alexandraniedden5337]

We use Stewart's Calculus - 8th edition.

[@mominazhar7275]

@@alexandraniedden5337 you're great thanks, i wonder if i can ask a question too

[@alexandraniedden5337]

@@mominazhar7275 You can definitely ask a question. I do not promise that I'll know the answer though.

[@mominazhar7275]

@@alexandraniedden5337 i just concerned that how did you conclude to (4r^2 + 1)^(1/2)

[@alexandraniedden5337]

@@mominazhar7275 I switched from rectangular to polar coordinates. Remember that x^2 + y^2 = r^2.

[@shivamsharma-wm1ob]

nectar to deceased