2 to the x = 12, many don’t know where to start

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[@shanoxyshanoxy1230]

You have no idea how much you help me with math. Im fourteen and learning math everyday because of you. Thank you 😊

[@chrisdissanayake6979]

How sweet and humble you are to appreciate Mr John’s hard work! (I needed to add more to this message) You are only 14 years old! I am 73 and I should be old enough to be your grandmother. I may share some wisdom gained over the years. Humbleness is a worthwhile wholesome quality to have. I think all babies are born with humility, but they tend to lose it as they grow up, because they get influenced by the corrupted society around them. So, please try not to lose your humbleness as you go through life. Life is much more than learning Mathematics. However, when you focus your mind on Mathematics, it helps your mind to keep away from trouble! 😇 I think, overall, this math channel gives us opportunities to observe how we all behave when we can’t do a math problem correctly. Some people’s ego gets hurt and they blame others! So, we get a chance to notice those shortcomings in the real world, learn how to remain humble with compassion and become better humans!

[@Kualinar]

If those videos ONLY help you, he have achieved his goal.

[@shanoxyshanoxy1230]

@@chrisdissanayake6979 Thank you❤️

[@shanoxyshanoxy1230]

@@Kualinar yes he has☺️

[@chrisdissanayake6979]

@@shanoxyshanoxy1230🙏🏽♥️

[@thomasharding1838]

Good Class! Thanks, I had forgotten this since 1963.

[@freedomhawk772]

Great class!

[@Poult100]

That stretched my 64 Yr old brain! Thanks for the exercise 👍

[@forrestgreen9369]

X = log(12)/log(2) = 3.58496...

[@prollysine]

2^(ln12/ln2)=12 , -> x=ln12/ln2 ,

[@raya.pawley3563]

Thank you

[@lamper2]

This lesson was a LOT more complex than the problem looked.

[@robertstuart6645]

The property of logarithms one needs to know for solving these problems is the log of a number to an exponent is the same as the exponent times the log of the number. This is a good practice problem for this property.

[@johnholme783]

Log 6 with base 2. Eg: Log₂ 6 = x

[@KUS-2024]

log(2^X)=log(12) X×log(2)=log(4)+log(3) X=(log(4)+log(3))/log(2) X=log(4)/log(2)+log(3)/log(2) X=2+log(3)/log(2)

[@robertdeland3390]

3.5849625 X = log(12) / log(2) used calculator for the logs. Did this before watching the video. Logarithms are a frequent "go to" if unknown is in the exponent.

[@rgrinnell]

2 to 3.5

[@russelllomando8460]

got it kinda solved mentally logic gave me 3.6 good explanation thanks for the fun

[@freedomhawk772]

x = 2 + ln(3) / ln(2) OR ln(12)/ln(2)

[@freedomhawk772]

The natural logarithm of 12 divided by the natural logarithm of 2 equals 2 plus the natural logarithm of 3 divided by the natural logarithm of 2.

[@shemiahwalker]

6 maybe unsure, thank you I learned something new.

[@tomtke7351]

THIS IS A GREAT VIDEO TO PLAY MULTIPLE TIMES TO ASSURE YOU GET EVERYTHING PRESENTED... A L S O you MUST hardcore memorize about logs, exponents and bases.... This is possibly NEW notation.... so spend 10 minutes and commit it to memory. Repeat this lesson tomorrow.... Then search out other KZbins on logarithms. 2^2 + 2^3 = 12 I.E. 4 + 8 = 12✔️ 2^2+2^3 = 2^2(1+2) = 2^2(3) So 2^x = 2^2(3) Xlog2= log(2^2(3)) X= log((2^2)(3))/log(2) = ((2log2)+log(3)/(log2) = (2(0.301)+(0.477))/(0.301) = (2 + (0.477/0.301)) = (2+ 1.585) = 3.585 Alternate Xlog2=log12 X= log12/log2 = 3.585

[@charles401]

If "we're gonna type this into our calculator ", why wouldn't we just type into our calculator log12/log2?

[@sk3ffingtonai]

If I didn't want to understand logarithms, I'd watch this video.

[@johnnyragadoo2414]

I never remember how to do this, but it’s easy to derive on the fly. Another way to express the value 2 is 10^log(2). 12 is then 10^log(2)^x, or 10^(log(2)*x). In other words, the base ten log of 12 is log(2)*x. The base 2 log is log(12)/log(2), which gives you the answer.

[@brucewellman]

this is a question about ASU vs meteric when is 32'=to 9 meters?? gravity acieration or is the meteric number wrong and should be 9.81meters per sec per sec

[@christianlohmann8577]

Still remembered: ln(12)/ln(2)

[@Kualinar]

Easy. X= log 12 ÷ log 2 ≈ 3.585 (3.5849625....) You can also use ln(12) ÷ ln 2 ≈ 3.585 Liking and posting a comment also help getting a video proposed to more peoples.

[@vespa2860]

I would love to see a video explaining your rounding technique😉 Kinda like the brutal butchering, but......

[@jimwhalen5675]

To involved lets similfy the explanation.KISS principle

[@elessarstrider5210]

Next, do fractional tetration.

[@taharwackers6373]

X=log12 à la base 2

[@BMF6889]

I used logic to solve this problem meaning that we are actually solving for the sq root of 12 so the exponent needs to be the sq root of 12 which is 3.46410161513775. Plug that into the x value and you get 12. This seems to work only when dealing with base 2 so the log solution is the better way to go.

[@Kualinar]

2^(✓12)= 11.035665... That's smaller than 12. 2^(ln12/ln2) = 12. 2^(log12/log2) = 12. ln12/ln2 = 3.2849625... log12/log2 = 3.2849625... The only way to get the correct answer is to use logarithm, not a square root.

[@Joe-pb3lx]

5

[@Darisiabgal7573]

3.58496 Log-e 12/Log-e 2

[@MSHStructuralDesignLtd]

Its actually closer to 3.585.

[@defan2105]

So what I'm hearing is, if you don't have the proper calculator, there is little hope for this old man to figure this out? How did they do it before calculators?

[@stevewthespider]

x is aprox 3.58

[@LarsV62]

My calculator came up with a similar solution, too, using natural logarithms. That answer is ln(3) / ln(2) +2. It also gave a solution called "root of the equation" with the solution using not base 10 log, but base 2 (aiming from value x?) That answer was x = log2(3) + 2

[@freedomhawk772]

Fantastic! That's what I got.

[@thaerthaer1120]

Its more than easy 12/ln2

[@haroldkaufman74]

2 to the 4th

[@stphinkle]

This is the answer: 3.5849625007211561814537389439478

[@louf7178]

LOL

[@gavindeane3670]

That is an approximation of the answer.

[@williamjames305]

X=3.5

[@chrisdissanayake6979]

I am sorry I didn’t have a calculator. I tried to do x log 2 = 12 So, it should be Log 2 12 = x

[@richardl6751]

Your computer or smart phone probably has a calculator.

[@chrisdissanayake6979]

@@richardl6751 Thank you 🙏🏽 But, I did it wrong.

[@barrychoi606]

x log 2 = log 12😊

[@chrisdissanayake6979]

@@barrychoi606 Thank You 🙏🏽

[@louf7178]

I'm surprised it wasn't a linear power (3.5).

[@user-lq6lg2tp2j]

X=log12/log2～=3.584962500721156

[@roskapostit2609]

log(12) / log(2) = 3,5849625007211561814537389439

[@Ca_milo_G]

no idea here....42 yrs old

[@chrissullivan40]

So basically just use a calculator. :)

[@soshakobyan3123]

Is this a joke?

[@mushtaqkaukab2698]

Your teaching method is very poor

[@lwh7301]

Useless. If you are going to rely on your calculator, why bother with the manual stuff?

[@louf7178]

It is the method to solve exponential equations, which could then reference logarithmic tables or a calculator to get a decimal number.

[@redblack8414]

So that you understand what you are doing.

[@Mr._Fit_Atheist]

I guesstimated using the calculator and found it to be ALMOST 2^3.58499 which my calculator gave me the answer of 12.0002287347, so I figured it was close enough. ... I'm not weighing atoms here. (^_^)