29 Examples Of Aromaticity | General Organic Chemistry-1 | JEE Main, IIT Adv. By NS Sir

[@neilbeats4945]

Best TEACHER for GOC on KZbin

[@Akshit___Rana]

Organic chemistry GOD🛐🗿

[@superheroiconics]

to all those who are confused about example number 35 aka HAPTALENE see since the rings have more than 8 pi electrons doesn't mean its going to be an non aromatic here the TWO rings are fused and though 12 pi electrons make them anti-aromatic they can not change their planarity coz there is no FREE ROTATION between the TWO rings..so they have to be ANTI-AROMATIC

[@abhi8055.]

Sir in reference to example 35, Heptalene is not planar, so it should be non aromatic, right? It has 7 membered rings which can lose planarity if the ring has 4n pi electrons, in order to become stable (according to what you told at 25:18 in Lecture 28 )

[@yashovardhansingh9289]

that rule is not valid for fused rings as well as bicyclic compounds

[@darthvader4633]

@@yashovardhansingh9289 i checked on pubchem, structure is not planar

[@vishwajeetchoudhary8264]

Bicyclic compound can be non planar but how fused rings ?

[@shaandutta3541]

ik its been 2 years but basically it is non planar, think youre broke, and you cant get a job but you need to hustle, so you take a loan, thats what this molecule does, its antiaromatic, but to relieve some strain it switches to non planar to recover some stablity however this said angle is not small enough for the antiaromaticity to not count, hence is a non planar antiaromatic compound

[@justanotherguy625]

Your analogy is even more confusing ​@@shaandutta3541

[@hemantdabhade704]

what an lecture sir!!!!!!! super

[@apexxvinit2201]

No.

[@NeerajSharma-pf6eh]

@@apexxvinit2201 kyu bhai no?

[@vinitnannaware]

what "an" lecture.. i felt that

[@vinitnannaware]

@@apexxvinit2201 ayo vinit

[@cookiemonster69699]

2:56 6:47 8:43 10:47

[@Yaswanth_kothuru]

Sir can tell me correct answer for my doubt cycloheptatrienyl anion is anti or non aromatic plz give reply sir

[@hardikjain1700]

sir but in example 24 S is sp3 hybd

[@beast05]

Sir example 33 mein 2 pie electron jo ki c pe hai wo kyun count hua ?

[@anubhabmondal5601]

Sir frost circle and craigs rule important hai kya ??????

[@vinitnannaware]

competitshun dekho aur pw ko chato damn

[@moneybeast_awa]

sir please reply IN QUESTION 35 IS THE ANSWER IS NON AROMATIC AS YOU SAID IF A RING HAS MORE OR EQUAL TO 7 CARBONS AND ALSO IF IT HAS 4n PIE ELECTRONS IT SHOULD BE CONSIDERED AS NON AROMATIC. SIR PLEASE EXPLAIN . HO[PE YOU REPLY. THANKYOU SIR 🙏

[@AayushKumar_12224]

Bhai wo single ring ke liye tha fused ring ke liye nahi

[@aviralomar3760]

4:25 ye 26 wale me jo upar wala N h wo bhi to left wale double bond ke sath conjugation kar sakta h na???? Please btao koi

[@DSSrijith]

Yes but it is not in complete conjugation (as the other double bond is not in conjugation with lone pair).

[@ashu-mb2zw]

it wont participate as then N will be sp hybridised which would be unstable in ring

[@Paramangenic]

​@@ashu-mb2zwThanks for that

[@mistere4148]

Sir, if fused ring has 8 or more carbons in the outer ring, then can it become Non-aromatic despite having (4n)pi electrons? Or does it stay in it's planar state? In reference to example 27.

[@pranavpendyala5632]

Fused ring will not lose its planarity.

[@shreyarora4739]

Same doubt , also will Bredt rule be followed it states that planarity is not in bicycling compounds

[@icnic6346]

same doubt

[@Niu_guy]

​@@shreyarora4739will stay planar cause of fused ring fixing sigma bond and leaving no possibility of rotation. Yes bredts rule is followed but in this example we have fused ring, no bridge atom so there is no bredts rule here.

[@shaandutta3541]

basically it is non planar, think youre broke, and you cant get a job but you need to hustle, so you take a loan, thats what this molecule does, its antiaromatic, but to relieve some strain it switches to non planar to recover some stablity however this said angle is not small enough for the antiaromaticity to not count, hence is a non planar antiaromatic compound

[@chillicheetos121]

q 34 and 35

[@newhi7559]

sir example 35 me total 12pie e he par individual rings me 6pie e he toh usse toh ham aromatic count kare ge Puri ring ko ?

[@rekhamishra2000]

Mujhe lagta hai total ka kare ge kyoki sirf ring ko lenge to vo conjugation nhi shiw kar rha .

[@Dev-i8r]

puri ring conjugated nhi h na bro

[@Jatinsaini423]

Same

[@harshgugale6182]

Sir, in example 27 there are 8pi electrons Will it be planar or non planar?

[@letsevolve9441]

Planar

[@shaandutta3541]

aah its a good question, it would switch to non planar if it had 7 or more carbon cyclic compounds, if it did it would bend and relieve the strain a bit, but since its 5 carbon, it stays planar, thus is planar antiaromatic

[@ojosshiroy8544]

Ex 33 mein resonance kar ne se do negative charge paas paas nhi ho jayenge? Resonance hoga?

[@hardiklalla1965]

if ex 30 had 4npi e- would it lose planarity? (6:50)

[@vinitnannaware]

#askcompetishun

[@sohanrai3850]

No , as it only has 6π electrons. :: The condition to lose planarity is to have 8π electrons.

[@sanyammishrasm07]

Thank you sir🙏🏻

[@satviksachdeva3289]

35 is non aromatic according to wikipedia

[@Ganesh2168Xvjti]

Jee 2024 aspirant?

[@sohanrai3850]

@@Ganesh2168Xvjti yup

[@ashu-mb2zw]

​@@sohanrai3850hi

[@okokok.56]

pls don't trust wikipidea for studies.

[@rekhamishra2000]

Even i think so because it have 7+ atoms

[@fawangvalorant]

Thank you sir.

[@shivamp8]

Nice video sir

[@moneybeast_awa]

thank you sir

[@rajkumar_05]

28 will be non arometic , N will be sp3

[@AJ-bj2ou]

Nitogren is sp2. Sir has explained it in the lectures of resonance that while doing resonance the lone pair doesnt participate in hybridisation, there fore sp2

[@hyp3842]

Bhai Shai hai tera

[@JayantKSingh-qu9ix]

#askcompetishun sir last example mai 7 membered rings planarity lose nahi karte?

[@shaandutta3541]

basically it is non planar, think youre broke, and you cant get a job but you need to hustle, so you take a loan, thats what this molecule does, its antiaromatic, but to relieve some strain it switches to non planar to recover some stablity however this said angle is not small enough for the antiaromaticity to not count, hence is a non planar antiaromatic compound

[@Pavithran-fo6gg]

​@@shaandutta3541bro how is ur preparation going..!? Im jee 2025 aspirant Mine is not very good as my school didnt show me the real competition and ive realised it recently only and i found this channel. If i wouldve seen this in 11th surely my rank would've been a lot better

[@SteveRogers...]

Sir g sp waala example to bata dete jo conditions me btaya tha

[@monothiest]

Is it sufficient for jee advanced level

[@arunabhadhal3662]

For sure

[@dipangshu3877]

@@kingpatil2882 not needed

[@abmondol971]

More than sufficient

[@educationlover274]

No

[@amaanahmed1309]

Sufficient for getting In top 10

[@sujitmehta9236]

Very nice video sir

[@alphaiitd1]

Thanks sir

[@generaltony5824]

ss 6:48 10:50

[@AJ-bj2ou]

Sir last question 35 one ring is aromatic and other is non aromatic, how will it be anti?

[@apexxvinit2201]

12 pie electrons 4(n)=12->n=12/4=>n=3 Thus anti aromatic

[@apexxvinit2201]

Btw no ring is aromatic

[@iit9220]

Yr doubts aa rhe h kya sir ka telegram channel he

[@apexxvinit2201]

Comment me puch liya kro Koi bhi bta dega

[@ayu5h_Kumar]

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[@Atlas-1233]

cool

[@aarushpriyankaj3105]

28 me agar resonce krege tonitrogen ka 5 bond banraha pls help🥺

[@manoharsinghyadav6916]

5 nhi 4 ban rha hai N pe positive charge aa Jaega aur 3 sigma bond aur ek pi bond banaega

[@rajkumar_05]

Bro resonance nhi hoga , N will be sp3 , which will make system non aromatic , and hence compound will become stable

[@ashu-mb2zw]

​@@rajkumar_05system doesnt have choice to change its hybridisation to avoid anit aromaticity

[@unstoppablerunner1836]

Lecture 29

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