3.9 Practice questions on Minimal Cover or Canonical Cover or Irreducible set

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KnowledgeGATE by Sanchit Sir

KnowledgeGATE by Sanchit Sir

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@KNOWLEDGEGATE_kg
@KNOWLEDGEGATE_kg Жыл бұрын
For complete DBMS, check out this video: kzbin.info/www/bejne/j4PRm3qbhsemfrM
@estableadentertainment5715
@estableadentertainment5715 5 жыл бұрын
Guys!at 13:00 sir clearly mentioned that in AC->D if closure of AC and A is same then C becomes redundant. And also if we solve taking W->X it then holds transitivity with V->W , making the actual result V->X. Which directly comes by eliminating W rather than V.
@sohamaditya4957
@sohamaditya4957 5 ай бұрын
whats up bro
@kusumjoshi8140
@kusumjoshi8140 4 жыл бұрын
No one can teach like you sir...you teach in a very easy way...its great
@AshisRaj
@AshisRaj 4 жыл бұрын
Sir you are not less than Saint whose selfless efforts is for us
@aaa_1711
@aaa_1711 Жыл бұрын
Hello everyone, what is the correct procedure of finding redundancy on the LHS??? Actually in older video(3.8) and present video sir has taken different steps, in previous video: while checking if there's any redundancy on LHS at 11:35, sir has ignored one functional dependency which was "wz=>y"... But in the present video in the same method, at 19:45, sir has not ignored "vw=>x". And if we do not ignore "vw=>x", we get a different result.. What is the correct way!!!
@abhijithkannan643
@abhijithkannan643 Жыл бұрын
if you have got the answer for this question, kindly share with me also
@aaa_1711
@aaa_1711 Жыл бұрын
@@abhijithkannan643 no reply from anyone yet bro🙁
@ANUSHKAVARPE-v6q
@ANUSHKAVARPE-v6q Жыл бұрын
Any solution??
@pastelteaaniiii
@pastelteaaniiii Жыл бұрын
According to what I understood and answer is turning to be correct: We check the LHS only after checking all the RHS so if an FD has survived the RHS round only then it can go for LHS round. In LHS round we check those FDs which have multiple attributes instead of single ones for redundancy. So in LHS we do not need to "ignore" the whole FD since we already did that in RHS. In short don't follow "ignore" method in RHS. In RHS just find closure vw with new set of FDS(means without y-->x since that got crossed in RHS round) that will be v,w,x Then find closure of v without any ignoring and same with w. Since v can give all the attributes same as vw so w is not needed.
@anushka_varpe
@anushka_varpe Жыл бұрын
​@@pastelteaaniiiiOkk.. Thanks!
@developersfeed
@developersfeed 4 жыл бұрын
In the second numerical you have told wrong while finding the redundancy in VW->X. When you were finding the closure of V u considered the Functional dependency VW->X so the answer is wrong. The correct answer is V->W, VW->X and Y->VZ.
@KNOWLEDGEGATE_kg
@KNOWLEDGEGATE_kg 4 жыл бұрын
Please post your questions on our Official discussion forum t.me/KnowledgeGATE_forum
@rishikumarvirenkumarmehta9635
@rishikumarvirenkumarmehta9635 3 жыл бұрын
Yes.....same ans
@krishan.barnwal
@krishan.barnwal 3 жыл бұрын
I am noticed same problem please confirmed is your answer correct or not?
@hermionegranger7849
@hermionegranger7849 Жыл бұрын
Confidently incorrect
@PrashantSharma-cc9nb
@PrashantSharma-cc9nb Ай бұрын
this is correct, sir ne second numerical wrong solve kiya hain, woh bhul gye ki pehle wale numerical main unhone dependency ko ignore karke closure calcualte karna btaya hain.
@sivakrishnanj9544
@sivakrishnanj9544 6 жыл бұрын
There is problem sir, y+=yvxzw is right, Not y+=yvxzx
@prof_as
@prof_as 6 жыл бұрын
yes i also observe the same
@tanaybalraj2999
@tanaybalraj2999 5 жыл бұрын
Correct sir
@saumyojitdas4212
@saumyojitdas4212 5 жыл бұрын
Y>x should not be removed??
@ashaykamdar4653
@ashaykamdar4653 5 жыл бұрын
Yes sir ..he is right there is a mistake
@Himanshu-jx9kw
@Himanshu-jx9kw 4 жыл бұрын
Yes there is mistake there
@bhanupratapshishodia3027
@bhanupratapshishodia3027 2 жыл бұрын
Thanks sir aap bhot achcha pdate ho
@KNOWLEDGEGATE_kg
@KNOWLEDGEGATE_kg 2 жыл бұрын
Most welcome dear student, keep learning & supporting !! Do visit our website www.knowledgegate.in for more courses & contents !!
@md.yasinali5959
@md.yasinali5959 2 жыл бұрын
wish if we could have these videos in our student life or in our 30's .
@shikshitkumarverma4298
@shikshitkumarverma4298 5 жыл бұрын
Thankkuu so much sir maza a gaya jis tarika s aap hame padhate ho and practice krba t ho 👏👏🖒
@shivangsaini3940
@shivangsaini3940 Жыл бұрын
Thank you sir, You are 5th sem saviour for me. ❣️❣️ Even after 4 years your teching technique is so unique.....
@KNOWLEDGEGATE_kg
@KNOWLEDGEGATE_kg Жыл бұрын
Thank you so much for your valuable feedback ❤Keep learning & supporting! Do visit our website www.knowledgegate.in for more amazing courses & contents 👍😊
@akashmittal7795
@akashmittal7795 5 жыл бұрын
sir, devta ho aap 🙏🙏
@muhammadkamran4255
@muhammadkamran4255 3 жыл бұрын
lot of respect from Gilgit Baltistan
@KNOWLEDGEGATE_kg
@KNOWLEDGEGATE_kg 3 жыл бұрын
Thank you.. keep learning !!
@sonalsharma7297
@sonalsharma7297 6 жыл бұрын
Please upload video on this topic Lossless Join and Dependency Preserving Decomposition
@samlee4146
@samlee4146 5 жыл бұрын
in last lecture u said while calculating u ignore the term,here in 2nd question u didnt do tht...due to which v+=vwx,if u ignore the relation u wiill get v+=vw...making it non reduntant...
@arshanjada2985
@arshanjada2985 5 жыл бұрын
Same doubt
@preetyparamanick
@preetyparamanick 2 жыл бұрын
when you calculate the redundancy of left sight you do not need to ignore anything, sir said it in previous video
@ThePRINCEBARPAGA
@ThePRINCEBARPAGA 5 жыл бұрын
I think correct answer should be: V->W, W->X (because we removed V as it was redundant), Y->VZ
@TwaritWaikar
@TwaritWaikar 5 жыл бұрын
Yes, this is also what I am getting. Thanks
@killadakalyanilakshmiprasa835
@killadakalyanilakshmiprasa835 4 жыл бұрын
While finding redundancy in left-hand side do we need to ignore or not....I mean, while checking for redundancy in (VW)--->X while finding V+ and W+ should we ignore (VW)--->X or not
@arinjain25
@arinjain25 Жыл бұрын
I also have the same doubt tomorrow is my exam, can u please tel weather we have to ignore it or not while checking?
@abhijithkannan643
@abhijithkannan643 Жыл бұрын
if you had received the correct answer for this doubt kindly share
@Sankalp-sd6fm
@Sankalp-sd6fm Ай бұрын
sir has taught this part wrong in both the videos
@nikhilnaudiyal7082
@nikhilnaudiyal7082 3 жыл бұрын
Apse acha koi ni
@rupeshshete6162
@rupeshshete6162 3 жыл бұрын
Minimal set of fd is affected by an order in which you are checking redundancy
@monisuvais4
@monisuvais4 6 жыл бұрын
while checking rhs in second ques while checking v closure you have also checked with vw->x but in previous video of canonical cover you said to ignore that fd in which we are checking....it's creating confusion
@ashishpajapati8032
@ashishpajapati8032 6 жыл бұрын
yes same question
@kirtideshmukh5219
@kirtideshmukh5219 6 жыл бұрын
Same question
@devashishpawar166
@devashishpawar166 6 жыл бұрын
same ques
@NitinSingh-cs6lp
@NitinSingh-cs6lp 6 жыл бұрын
Yes...how?
@addictedtosuccess01
@addictedtosuccess01 6 жыл бұрын
I also believe there is some confusion. The correct answer should be V->W, VW->X, Y->VZ
@kartickchandramanna267
@kartickchandramanna267 2 жыл бұрын
Awesome lecture 👍 Thank you sir 🙏❤️
@KNOWLEDGEGATE_kg
@KNOWLEDGEGATE_kg 2 жыл бұрын
Most welcome dear 😍Keep learning & supporting ! Do visit our website www.knowledgegate.in for more amazing courses & contents 👍😊
@rhaegal7749
@rhaegal7749 3 жыл бұрын
A->BC , B->AC ,C->AB will not work by this method . or we need to find specific sequence to implement this method . correct me if i am wrong.
@nishchaymohan2083
@nishchaymohan2083 7 ай бұрын
love you sir , kya padhaya
@rajatgupta6043
@rajatgupta6043 6 жыл бұрын
Amazing....,sir plz upload videos on locking protocols as soon as possible
@272_abhishekkumar7
@272_abhishekkumar7 4 жыл бұрын
In the first example we get D-AC & AC-D , so by using transitivity can we write D-D, If we can write that does D-D signifies anything or it is just said to be trivial functional dependency?
@anubhav1020
@anubhav1020 3 жыл бұрын
It would be just trivial and wont make any sense.
@wasifansari647
@wasifansari647 6 жыл бұрын
your videos helped me a lot sir 😊😊
@chandrakalat8178
@chandrakalat8178 5 жыл бұрын
Canonical cover for A-C,AC-D,E-AD,E-H
@PANKAJKUMAR-fe8zn
@PANKAJKUMAR-fe8zn 6 жыл бұрын
your teaching method and example clicks very well but my college professors not.....
@NishaSharma-nd1dk
@NishaSharma-nd1dk 3 жыл бұрын
Thanks sir g
@deepshikharajput5069
@deepshikharajput5069 6 жыл бұрын
sir ur videos are really awesome . can u plz make lectures on relational algebra.
@jellyfish1772
@jellyfish1772 2 жыл бұрын
13:15 why didnt you ignore AC->D sir? Whats the reason? In the past video for a similar case you ignored WZ->Y. But why not now?
@lalchandyogi1177
@lalchandyogi1177 4 ай бұрын
did you got the answer??
@jellyfish1772
@jellyfish1772 4 ай бұрын
@@lalchandyogi1177 2 years man. I Don't remember now😂
@Palatard
@Palatard Жыл бұрын
Please tag the English videos. The ones where you at least explain in English as well as Hindi are very clear but it's hard to find them.
@sscknight
@sscknight 5 жыл бұрын
Great sir thank you so much
@ranjeetkumarrana4759
@ranjeetkumarrana4759 6 жыл бұрын
Thanks sir ...you are great
@prof_as
@prof_as 6 жыл бұрын
sir there is a problem at 18:07 y⁺=vxzw not y⁺=yvxzx and yₓ⁺=yvzwx and by this what is the correct answer
@prof_as
@prof_as 6 жыл бұрын
plz reply
@swetarani8426
@swetarani8426 3 жыл бұрын
same ans
@Ankit-we8ym
@Ankit-we8ym 6 жыл бұрын
b and b+ trees sir
@utkarshshrivastav5478
@utkarshshrivastav5478 3 жыл бұрын
Sir, if we cannot decompose lhs. Then why are we computing the closure of lhs and eliminating it? Indirectly we are decomposing itself right?
@vanshikagarg6768
@vanshikagarg6768 3 жыл бұрын
sir last q me aapne v closure nikala h at 19:52 usme x ni ayega therefore both v and x are essential
@vanshikagarg6768
@vanshikagarg6768 3 жыл бұрын
why u didn't ignore vw at the time of finding closure of v
@askariaziz4163
@askariaziz4163 4 жыл бұрын
very useful videos
@CodeWithKal
@CodeWithKal 6 жыл бұрын
namaskaar donston mein hun sanchittt.........My favourite lineeeeee
@cybercopashu
@cybercopashu 4 жыл бұрын
Too good sir...👌👌👍👍
@nitinmodi7199
@nitinmodi7199 4 жыл бұрын
If to remove the redundancy on the LHS with five terms ABCDE->X,do we need to have 2^5-1 iteration
@RohitKumar-qt2nm
@RohitKumar-qt2nm 6 жыл бұрын
plzz upload B+ tree and locking protocols
@rachnagoyal3853
@rachnagoyal3853 6 жыл бұрын
Sir how to find out the number of different minimal cover possible..plz make a video related to this...
@viharcontractor1679
@viharcontractor1679 6 жыл бұрын
You're a savior!
@VikashKumar-bh5yh
@VikashKumar-bh5yh 5 жыл бұрын
The answer of the last discussed question will be v->wx and y->v ....
@sakshirathoree2908
@sakshirathoree2908 4 жыл бұрын
sir in last question redundancy is due to 'v' not 'w'.... please checkk
@madhurmungra5362
@madhurmungra5362 3 жыл бұрын
i think you are right. but i am still confused
@abhishekhirve4608
@abhishekhirve4608 4 жыл бұрын
Hi can you please explain R(ABCDEFG) A--> B , ABCD-->EG,ACDF-->E ?
@pintulakra1992
@pintulakra1992 4 жыл бұрын
A-->B ABCD-->EG
@The.Jaynish
@The.Jaynish 3 жыл бұрын
Thanks lot sir, This helped a lot in exam
@MrSunnychadha
@MrSunnychadha 3 жыл бұрын
Plz help me getting the minimal functional dependency F = {A -> BCE, AB -> DE, BI -> J}.
@sangramjitchakraborty7845
@sangramjitchakraborty7845 3 жыл бұрын
I think {A -> BCDE, BI -> J}
@lovefrommars7468
@lovefrommars7468 4 жыл бұрын
Thank you sir
@suchitrapathak7391
@suchitrapathak7391 6 жыл бұрын
C to b will also be redundant na cozzz we could derive d to b at that time
@narendraparmar1631
@narendraparmar1631 6 жыл бұрын
Thanks very much sir😆
@vedkerkar4593
@vedkerkar4593 Жыл бұрын
just an hour left for my exam and watching this at 2x. Thankyou ❤
@KNOWLEDGEGATE_kg
@KNOWLEDGEGATE_kg Жыл бұрын
You're welcome 😊 All the best👍😊
@surajitkundu1205
@surajitkundu1205 Жыл бұрын
Sir, can I use vw->x rules in the closer of v+ 19:48 ? Please reply me ASAP..
@KNOWLEDGEGATE_kg
@KNOWLEDGEGATE_kg Жыл бұрын
Dear @Surajit, we're already using vw->x rule in the closer of v+. That's how we derived x.
@maheshbhairi7513
@maheshbhairi7513 2 жыл бұрын
iam getting ans : V-->W, W-->X, Y-->VZ
@prashantrana1892
@prashantrana1892 5 жыл бұрын
What is minimal set of functional dependencies
@samyakkumarsahoo8706
@samyakkumarsahoo8706 4 жыл бұрын
In closure of VW=VWX , what will be the the outcome if V=VWX AND W=VWX?
@ankithanaik3327
@ankithanaik3327 4 жыл бұрын
W
@anshshrivastava9107
@anshshrivastava9107 3 жыл бұрын
2:51 X ke hone na hone se kuch fark nahi pda, X extra hi thi. Hence proved XD
@ayushiydvKG
@ayushiydvKG 5 ай бұрын
21:25 why we eliminated W? not V?? did'nt get this point.
@shahbajkhan555
@shahbajkhan555 2 жыл бұрын
LHS me kya krna hai smjh me nhi aya hai sir redundancy kaise hategi usme confusion horhi hai
@KNOWLEDGEGATE_kg
@KNOWLEDGEGATE_kg 2 жыл бұрын
🔥Complete DBMS by Sanchit Sir: tiny.cc/DBMS_Sanchitsir_kg 🔥🔥All Computer Science Subjects by Sanchit Sir: tiny.cc/CSbundle_dbms_kg
@RaviSingh-yf6jd
@RaviSingh-yf6jd 5 жыл бұрын
Thanks sir but also upload software engineering artificial intelligence as UGC net point of view thanks again sir
@amanchouhan2802
@amanchouhan2802 4 жыл бұрын
wrong in second step...it should be y+->yxvwz
@MeraAllah3124
@MeraAllah3124 6 жыл бұрын
Sir apne previous video me kaha tha ki closure same nikle par first wali f.d ko remove krte h... Or es video me apne bad wali f.d ko remove kia... Confusion... Please make me correct
@debagnikroy9450
@debagnikroy9450 5 жыл бұрын
as per this question agar previous vdo ka technique use kare toh answer me 'w' reh ja raha hai... thats wrong So ye wala method hi sahi hoga i guess... and this method works in the previous example too.
@faiqariaz8098
@faiqariaz8098 6 жыл бұрын
Sir, Can we apply other inference rules in the last step other than union rule if applicable?
@ParthVikani
@ParthVikani 6 жыл бұрын
@Knowledge gate:. Sir, Did you upload videos for relational algebra?
@DeepakChauhan-gb3tf
@DeepakChauhan-gb3tf 6 жыл бұрын
I guess No
@Coolnaruto212
@Coolnaruto212 10 ай бұрын
Thank you sir
@KNOWLEDGEGATE_kg
@KNOWLEDGEGATE_kg 10 ай бұрын
You are welcome Rohit! Keep learning & supporting! Do visit our website www.knowledgegate.in for more amazing videos & contents👍😊
@good114
@good114 2 жыл бұрын
💕❤️❤️💕
@jitendrakumar-lh9xu
@jitendrakumar-lh9xu 4 жыл бұрын
Board se thoda hatke khade hua kijiye sir
@pratikmodi1838
@pratikmodi1838 6 жыл бұрын
in the last step of the 2nd question v closure is same as vx closure and w ka closure is different . Then v should be redundant as it is same and should not be part of solution . Can u please clarify this ??. Thanks
@rajnigupta8436
@rajnigupta8436 6 жыл бұрын
Pratik Modi actually I have this doubt too, but then I understand it carefully than I found that the clousre of vw and v is same which is vwx. So w does not play any role there, because with w, we have the same clousre and without w , we also have the same clousre.
@dakujaisingh
@dakujaisingh 6 жыл бұрын
Pratik Modi what happened here is that for reducing the left hand side of dependency we find if any of the attribute among the given set of attribute can have same closure . Agar same hota hai then dusra wala attribute jo hai it is of no use kyuki mereko toh pehle attribute se hi mil jaa rha hai same value
@rajnigupta8436
@rajnigupta8436 6 жыл бұрын
Ab's la comedia see, A batsman took 2 balls to hit a 6, and a batsman took 1 ball to hit a six, then whom will you prefer to reduce the energy and time, offcourse the batsman with 1 ball. In the same way, VW and V has same clousre , but to reduce the redundancy we consider only V , not VW. Also, in Fxn Dependency, Logics in LHS and RHS are different , which you already learnt from that we can apply the Decomposition rule in RHS but not in LHS
@dakujaisingh
@dakujaisingh 6 жыл бұрын
Rajni Gupta I guess virtually we said same 😊
@PrashantSingh-oj5ez
@PrashantSingh-oj5ez 5 жыл бұрын
thnks alot both of uh😊
@manish2684
@manish2684 5 жыл бұрын
Sir either Complete us leave us....
@pawanjakke7392
@pawanjakke7392 4 жыл бұрын
Y+ is written wrong sir
@tirtheshpawar9614
@tirtheshpawar9614 6 жыл бұрын
Mistake at 18:01 pls check and correct
@demmogorgonx
@demmogorgonx 5 жыл бұрын
so at 14:32 ? AC--> D, and D --> AC, Can we not make one of them redundant? as they are basically the same dependencies but flipped the other way ?
@antarbasu5342
@antarbasu5342 4 жыл бұрын
18:13 sir you are doing wrong.
@utkarshdevgan6199
@utkarshdevgan6199 5 жыл бұрын
watch on 1.5x playback speed thank me later!
@mk677hd
@mk677hd 5 жыл бұрын
2X is even better
@abhishekvanenooru2869
@abhishekvanenooru2869 6 ай бұрын
while removing redundant function the only thing important was you
@KOTHAMASUKARTHIKBCI
@KOTHAMASUKARTHIKBCI 4 жыл бұрын
sir please explain in english
@zzxoto4186
@zzxoto4186 5 жыл бұрын
your method would not work for finding minimal cover set of the following f.d.s {B -> A , D -> A, AB -> D}.
@dharmikdave6826
@dharmikdave6826 5 жыл бұрын
The answer should be B -> AD and D -> A
@abhishekjain8869
@abhishekjain8869 5 жыл бұрын
Atleast try to reply your viewers . You made a point in last step of second question which contradicts what you said in previous video
@adityalahiri4529
@adityalahiri4529 5 жыл бұрын
be grateful that he even makes the videos. he is a teacher. I suggest you be more respectful.
@lintaolu8202
@lintaolu8202 6 жыл бұрын
Did he speak English?
@adityalahiri4529
@adityalahiri4529 5 жыл бұрын
no, he spoke in hindi.
@krupalshah8526
@krupalshah8526 6 жыл бұрын
Bot sala
@TimePass-dn1rd
@TimePass-dn1rd 4 жыл бұрын
Sir can we combine ac to bd ?
@ektabansal5332
@ektabansal5332 Жыл бұрын
thank you sir
@KNOWLEDGEGATE_kg
@KNOWLEDGEGATE_kg Жыл бұрын
You're welcome dear @Ekta😍Keep learning & supporting! Do visit our website www.knowledgegate.in for more amazing videos & contents👍
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