539. Minimum Time Difference | Leetcode POTD Explained

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Jeevesh Rai

Jeevesh Rai

Күн бұрын

🎥 Welcome to Our Coding Channel! 🚀
In this video, we dive deep into an intriguing coding challenge: Minimum Time Difference ! 🎯
⏱ TIMESTAMPS
🎯 Objective:
In this video, we explore how to return the minimum minutes difference between any two time points given in a 24-hour clock format ("HH
"). 🕰️ Whether you’re looking to sharpen your C++ skills or crack that tricky problem, this tutorial has you covered!
💡 Concepts Covered:
- String manipulation in C++
- Sorting vectors efficiently
- Time conversion to minutes
- Handling edge cases with wrap-around logic
📈 What You'll Learn:
- Practical use of sorting for time-based problems
- Clever ways to handle time differences across a 24-hour cycle
- Writing clean and efficient C++ code
🔗 Problem Statement: leetcode.com/p...
🚀 Watch Now and Level Up Your Algorithm Skills!
💻 About Our Channel
Welcome to our channel! Here, We offer solutions to coding problems and teach programming concepts daily, covering everything from data structures and algorithms (DSA) to full-stack development. Dive into our content for in-depth tutorials on frontend and backend development, alongside practical examples and problem-solving techniques. Join us to enhance your coding skills and stay updated on the latest in app development!
Check out our channel here:
/ @codeby_naruto
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Portfolio: jeeveshportfol...
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Leetcode: leetcode.com/u...
#539 #potd #leetcodepotd #leetcodesolution #leetcodeblind75 #string #time #sorting

Пікірлер: 3
@codeby_naruto
@codeby_naruto 3 күн бұрын
Code :- class Solution { public: int findMinDifference(vector& T) { vector ans; for (auto time : T) { string hour = time.substr(0, 2), minute = time.substr(3); int TotalMin = stoi(hour) * 60 + stoi(minute); ans.push_back(TotalMin); } sort(ans.begin(), ans.end()); // Adding the difference between the first and last times accounting for // wrap-around ans.push_back(ans[0] + 24 * 60); int minDiff = INT_MAX; for (int i = 1; i < ans.size(); ++i) { minDiff = min(minDiff, ans[i] - ans[i - 1]); } return minDiff; } };
@shubhamjaiswal7645
@shubhamjaiswal7645 3 күн бұрын
very nice explanation
@codeby_naruto
@codeby_naruto 3 күн бұрын
Thank you ❤️❤️
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