8.1 Polar Coordinates

[@genuinelifematters8819]

I'm glad I do understand to this point. Doing 2nd year in far distant point from MIT, anything written MIT scares me. It's my dream university.

[@prakharchaudhary272]

Watching this video exactly four years after it was uploaded.

[@albertyeung5787]

excellent explanation

[@changtillend5718]

Thank you so much... This is Very Very Helpful Who need this...

[@zack_120]

Holistically, is the statement true that polar coordinates are more complicated than the Cartesian ones? Always stunned by this type of 'partial' logic that causes lots of troubles in this world. Wish all think, speak and act holistically to make world better.

[@giack6235]

Hello, thank you for the video, I want to ask something about it: To say: r = | r | vers(r), we would need a vers(r) centered in the origin so as we can travel a | r | amount radially in the r direction and get the radial coordinate (just as we do with cartesian coordinates when writing e.g. 3 i + 2 j). Why at 1:50 do we have the reference frame on the tip of r vector? Shouldn't be centered at point P? (and the same also for vers(tetha))

[@gomanaabdelnaser6384]

A popular explanation i hope you add the translation in Arabic later ❤️

[@markkennedy9767]

If we use a polar coordinate system whose origin is either 1) moving with uniform velocity or 2) accelerating or 3) itself moving around another fixed point, can we use Newton's second law in the r hat and theta hat directions. I suspect we can still do so in case 1) but not if it's accelerating in 2) and 3). If not, how would we deal with such a system with an accelerating origin: I'm thinking something like a spinning ride which is itself on a spinning carousel. Hopefully you can comment on this. Thanks.

[@gauravmanwani9148]

Nice lecture professor! But at 0:56 don't you think that the bound at 2π should be open because here 0 and 2π mean the same.

[@skrrutadu4824]

If theta is not bound from 0 to 2pi, then for 2pi limit won't exist( limit of 2pi-h will but not for 2pi + h) , thus at there won't be any velocity

[@hussiendaeeh]

Thank you very much

[@orgestbeqiri2076]

2pi is congruent to 0

[@camilotello3296]

Nice!

[@louislacroix7387]

How are videos like this made? It looks like he's writing on a mirror or is standing behind a transparent glass used as writing board.

[@mitocw]

See lightboard.info to see how it was done.