99% STILL Don't Understand Continuity.

[@NumberNinjaDave]

QUIZ QUESTION 👀👇 True or False? For the limit to exist at x=0, f(x) MUST have a defined value for x=0🤔

[@AbdulalimAWAD]

False. For example f(x)=x^x as no defined point for 0 but the lim as x->0 of x^x=1

[@AbdulalimAWAD]

Btw how did you comment 3 days ago and the video came out 1 hour ago??

[@NumberNinjaDave]

@@AbdulalimAWAD because I’m the author and a ninja hahaha

[@NumberNinjaDave]

@@AbdulalimAWAD nice answer, ninja

[@VladimirHarold]

But the limit from the left-hand side does indeed exist, it is -4. The fact that (0, -4) is not an element of this function is not relevant. As the limits at zero from the left and right are unequal, discontinuous! Cheers!

[@NumberNinjaDave]

@@VladimirHarold did you watch the whole video? I mentioned that for the sake of learning, I went ahead and demonstrated the other half as well. Cheers!

[@chucksucks8640]

Piecewise continous

[@NumberNinjaDave]

Very true!