A awesome mathematics problem | Olympiad Question | can you solve this problem | x=?

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[@pas6295]

One unknown and one equation you getthe answer.

[@pas6295]

You get if the numarstor is multiplied by the denominator as follows Xsquare-4squared (xsqare-5Square)(xsquare-6Square)(xsquare -7sqyare) / in Denominator you have ( x-4)square(x-5)square(x-6)square(x-7) Square.=1.. By taking the denominator on to the right side. You an equality from where you can get the answer.

[@renesperb]

x = 0 is very easy to see.

[@renesperb]

It is also the only real solution, which is not hard to see.

[@SidneiMV]

(x² + 11x + 28)(x² + 11x + 30) = = (x² - 11x + 28)(x² - 11x + 30) x² + 11x = a x² - 11x = b (a + 28)(a + 30) = (b + 28)(b + 30) a² + 58a = b² + 58b (a² - b²) + 58(a - b) = 0 (a - b)(a + b + 58) = 0 a = b x² + 11x = x² - 11x => *x = 0* a + b + 58 = 0 2x² + 58 = 0 => *x = ± i√29*