A HARD Algebra Question | You should know this TRICK!

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[@rainerzufall42]

1 * 8 + 15 * 4 + 15 * 2 + 1 * 1 = 8 + 60 + 30 + 1 = 99 6 * 4 + 20 * 2 + 6 * 1 = 24 + 40 + 6 = 70 => (sqrt(2) - 1)^6 = 99 - 70 sqrt(2). Easy.

[@rainerzufall42]

Without any calculation: This should be 1 / (99 + 70 sqrt(2)) ~= 1 / 198 = 0.0050505... (good enough!). Why that? (sqrt(2) - 1) = 1 / (sqrt(2) + 1) and 99 ~= 70 sqrt(2), because |sqrt(2) - 1|

[@blue_blaze2256]

why not use pascals triangle to figure out the formula for (a-b)^6 and solving it??

[@rainerzufall42]

Or at least (a + sqrt(b)) ^ n ...

[@alokKumar143ak]

You are real teacher.

[@witzar]

I watched some of your videos. You keep solving the same trivial (but you call it "HARD" for some reason) algebra problem over and over again, just with different numbers. What could be the purpose of this?

[@Maths_Se]

Thank you very much

[@RealQinnMalloryu4]

(2 ➖ 1)^2^3 (1 ➖ 1)^2^3 (x ➖ 3x+2).

[@TonyFisher-lo8hh]

What an incredibly cumbersome solution! Just expand the original expression with the binomial theorem, do some simple arithmetic, collect like terms, and the result drops out with about four lines of calvulation

[@TonyFisher-lo8hh]

Sorry: calculation

[@ralkadde]

@@TonyFisher-lo8hh Agreed, this is the general approach to handle such expression. By the way: to correct typos, press on the 3 points that are located right of you text and simply change your text. ('calculation' in this case)

[@TonyFisher-lo8hh]

@@ralkadde "Three dots" to enter edit-mode works in Chrome under Windows, but not in youtube under Android.

[@artemundocotheo]

Podemos resolver também por produtos notáveis(quadrado da diferença), separando em 3 parcelas (V2 - 1)'2. Depois, teremos novamente 3 parcelas iguais e podemos resolver duas delas por produto notável(quadrado da diferença). E o resultado multiplica com o termo que sobrou.

[@Mr.pavan0]

❤❤

[@Prayanshusinghal]

Binomial theorem se Karo 😅😅

[@Prayanshusinghal]

With in 30 sec answer aa Jayega

[@Jayant_nanda123]

Please 🙏 tell kaise aayega , Please 🙏

[@ghiant02]

неплохо

[@SagnikPalshorts]

I love Your types of Mathematics Please Pin my comment🎉

[@fatiherdogan9623]

Are you fun

[@SagnikPalshorts]

I love Your types of Mathematics Please Pin my comment🎉