A Nice Algebra Challenge | Maths Olympiad | 2 Different Methods

[@piman9280]

The second method is known as the common sense method; the first is known as the world cruise method!

[@alexkirchoff5286]

It should be make clear as first what number is 7^7^7 IMO.I found the same solution by chance(through 2nd method); It all works if 7^7^7 is 7^(7^7) which is ≠ (7^7)^7.I know,the former is correct and associativity doesn't work with stacked exponents by the way.

[@gbessinpenieleliezerhoumba3337]

Hi dear Professor, I have a topic that might interest you and I would like to see a video about it: PROVE THAT FOR EVERY REAL NUMBER NOT having A MULTIPLE OF 2 CONTAINS IN ITS DECOMPOSITION AT LEAST ONE ODD NUMBER

[@leonardobarrera2816]

Wow, an amazing video with a genious content!!!

[@MathBooster]

Thank you 🙂

[@leonardobarrera2816]

@@MathBooster you are well come

[@ujwalsmanhas1093]

substitue x =+/- 7^y . we get same answer.

[@buziga236]

So skilled

[@hanswust6972]

I go for the 2° Method. 🤣

[@yakupbuyankara5903]

X=7^6.

[@alicanpolat6174]

Aa Türk buldum .