5^n+3^n is increasing for all values of n; hence, if there's an integer solution, it must be unique. Indeed n=3 works and is, therefore, the only solution.
yez n=3 and since the lhs is increasing and the rhs is constant there can only be one sokution.
@richardamullensАй бұрын
@@SALogics Surely there can only be one solution because both 3^n and 5^n are both monotonic and increasing. Though I can see that perhaps your solution is a general method that may work when trial and error doesn't give an obvious solution in a reasonable time.
The only valid solution comes from the setting the factor (x+y)=8 and (x^2-xy+y^2)=19 When you square (x+y)=8, you get ( x^2+2xy+y^2)=64 When you subtract( (x^2+2xy+y^2)=64)-(x^-xy+y^2=19), you get 3xy=45 or xy=15 Now you have a system of equations: (x+y=8) and xy=15 Solve for x in the first equation and substitute the result in the xy equation to get two values for x and two values for y.
Why not simply solve it by inspection as we do with cubic equations....
@SALogicsАй бұрын
This is not allowed in olympiad! ❤
@valentinaivanova4806Ай бұрын
Why are X and Y integers greater than zero? It's not obvious at all.
@SALogicsАй бұрын
Because n is a positive integer!❤
@valentinaivanova4806Ай бұрын
@SALogics For N - yes, but for "5 rise to the power of (N/3)" this is generally not true. That is, the solution is found from a false assumption. But, fortunately, it was found and it was possible to prove that it is unique.
@matteooliveri6697Ай бұрын
n=3, because 125+27=152.
@SALogicsАй бұрын
Very nice! ❤
@matteooliveri6697Ай бұрын
@SALogics Thank you!
@narsinhapotdar7215Ай бұрын
nice
@SALogicsАй бұрын
Thanks! ❤
@ИринаСавостинАй бұрын
Методом подбора :n=3. Ваш способ решения правильный, но проще сделать таким образом 5^[n*2*(1/2)]+3^[n*2*(1/2)] =152 Замена:5^(п/2)=х 3^(п/2)=у х^2 +у ^2 =152