A Nice Algebra Problem ‼️ | Math Problem Solving

Hello My Dear Family😍😍😍
I hope you all are well 🤗🤗🤗
If you like this video about
How to solve 2^x + 4^x + 8^x = 39 to find the value of X in this math problem
please Like & Subscribe my channel
🙏🙏🙏🙏

[@NhanNguyen-wu3zp]

With 2^x=a>0 we have a^3+a^2+a=39 a(a^2+a+1)=3x13 . Check a={3,13}, we have a=3 is one of result. let take (a^3+a^2+a-39)÷(a-3). We have (a-3)(a^2+4a+13)=0 with a>0. 😊😊😊 Then the only result is 2^x=3

[@hanswust6972]

I loved the last trick: *log a [n] ÷ log b [n] = log a [b]* *Thanks for the class!*

[@deadman7770]

that's no a trick that's just one of the formulas of logarithms.

[@rajasengannann63]

By taking log on bothsides 2^X=3 gives X=log 3 to the base 2

[@musicsubicandcebu1774]

2ˣ(1 +2ˣ +2²ˣ) = 3*13 Or RRT applied to t³ + t² + t - 39

[@hectorsegundoserichevalenc8787]

Así lo hice Yo ❤

[@viktarkrylov5604]

t=2^x >0, по теореме Безу t=3 -корень уравнения t^3+t^2+t-39=0 далее по схеме Горнера находим t^3+t^2+t-39=(t-3)(t^2+4t+13)=0, x=ln3/ln2

[@YusufEpik-o5r]

Müthiş

[@kevinsolari2744]

Having got to t³+t²+t-39=0 it doesn't take much to see that t=3 is a solution so we must have (t-3)(t² + ?t + 13)=0 Then ewustd coefficients to find?

[@joeaberman449]

i like the way you teach !!!!!!

[@learncommunolizer]

Thanks, your welcome!

[@stevenjeng1237]

You push students out of math. It is not a good way. 2^x(2^2x+2^x+1)=39 So, 2^x=1 or 3, but 2^x could not 1, so 2^x=3. Take log both side X(log2)=log3 X=(log3)/(log2)

[@kaushikbasu9707]

log3 / log2

[@kaushikbasu9707]

log3 / log2.

[@Pushpvatika3186]

🙏🙏

[@learncommunolizer]

Thanks 👍😊

[@mohammadhosseinian5986]

the main problem is how we find out t=3? just by guessing? that is not the way you solve math problems

[@miracbarsapaydn650]

There is no need to go on for so long, the correct answer is log(2)[3]

[@is7728]

He's just checking the value of x

[@peterwallman6269]

@@is7728 x is log(2)[3] 🤦‍♀

[@amelgrisssa4422]

il faut mentionner dès le début dans quel ensemble sera la solution.puis vos solutions l'une dans l'ensemble des réels et l'autre dans l'ensemble des imaginaires ce qui n'est pas possible . Désolé.

[@Fredscorpion2]

t= -12t+13t t= 1000t-999t t= 2t-t t= -7t+t t= -0t+t Why -12t+13t???????????? Why?????? Why not 100t-99t? Why not-15t+16t? Why not 28t-27t??????????? Why 12 and 13????????? Why??????

[@hectorsegundoserichevalenc8787]

Muy mala solución Yo lo hice en dos minutos, tanta complicación de usted en este ejercicio matemático 😡😡😡