A Nice Exponential Algebraic Challenge | Unlock the Power of Exponents! | Olympiad Math Challenge

[@Animioentertainment]

Great move sir

[@CharlesChen-el4ot]

(x +4) log 3 = (x+3)log4 (x+4)/(x+3)=log4/log3 1+ 1/(x+3)= log4/log3 x + 3 = log3/(log4-log3) x = ( 4log3 - 3log4)/ (log4-log3)

[@pspprabhat]

3^×+4=4^×+3 3^×)(3^4)=(4^×)(4^3) =>(3/4)^×=4^3)//3^4 🎉=>× =(3log4-4log3)//(log3-log4)

[@obviamorbisterrarum]

❤

[@enkhturgerelt6903]

3^(x+4)=4^(x+3) 3^4*3^x=4^3*4^x 3^x/4^x=4^3/3^4 (3/4)^x=4^3/3^4 X=(3ln(4)-4ln(3))/(ln(3)-ln(4))

[@wes9627]

Simply take the natural log of both sides and rearrange. (x+4)ln3=(x+3)ln4; (ln4-ln3)x=(4ln3-3ln4); x=(4ln3-3ln4)/(ln4-ln3)=0.8188...

[@alfonsojesusdiaz8228]

Congrats - pretty nice exercise from 🇪🇸 .

[@BrightBrainIntegral]

❤️❤️👍👍

[@gnanadesikansenthilnathan6750]

A nice algebra problem. From 🇮🇳 but could you verify this sir. Is any other shortcut or can we do this using trial and error method?

[@BrightBrainIntegral]

Thanks, I will upload another video on this type of challenge using another approach..❤️❤️❤️❤️

[@glasssmirror2314]

Still watching. Pls are you sir teaching in the noisy class

[@BrightBrainIntegral]

No

[@opulence3222]

Nice

[@prime423]

Simply take the log of each side. It saves some work.

[@BrightBrainIntegral]

Okay, thanks for that ❤️❤️❤️👍

[@Occ881]

The answer is x=-4....or -1/0.25 you made a mistake

[@dreingames9137]

lmao are you 8 years old? you commented the same exact completely incorrect thing 3 times. finish algebra 1 before commenting please. the guy was 100% correct

[@Daniboy25]

❤❤

[@OdehJoy-lq1cj]

👍👍👍👍❤️❤️❤️

[@Occ881]

Infact when you verify it doesn't match next time be careful of what you post

[@Occ881]

This answer is not correct there is errors

[@adekunlesunday5897]

U don't know what u are doing, stop confusing people