A Nice Exponential Equation Problem | Olympiad Maths

[@prollysine]

in a first approximation , let u=x^3 , u^2=x^6 , u^2-u-2=0 , u=(1 |+/-| sqrt(1+2^3))/2 , u= (1+3)/2 , (1-3)/2 , u= 2 , -1 , -> u=2 , u=x^3 , x=2^(1/3) , test , (2^(1/3))^6 - (2^(1/3))^3 = 2^2 - 2 , 4-2=2 , test OK , -> u=-1 , -1=x^3 , x=-1 , test , (-1)^6 - (-1)^3 = 1- (-1) , 1 - (-1) = 1+1 , 1+1=2 , test OK ,

[@wisfrank-zc6yp]

Correct

[@prollysine]

@@wisfrank-zc6yp Thanks

[@wisfrank-zc6yp]

You did well, nice one

[@prollysine]

@@wisfrank-zc6yp Thanks...

[@prollysine]

@@wisfrank-zc6yp Thanks...