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Пікірлер: 22
@aresyt50545 ай бұрын
It's a GP, so we can directly use the sum of a GP formula
@MATERémi5 ай бұрын
And you can work out the result using no calculator ...?
@aresyt50545 ай бұрын
@@MATERémi yes , too easy
@-aqua-marine-5 ай бұрын
Yep
@Prem-K0074 ай бұрын
@@MATERémiyes , definitely only 9⁶ should be calculated which is nothing but (9³)² which is (729)² . Is it that much difficult to solve it with a pen and paper?. Using G.P formula =( 9⁶-9)/8 is the answer. Edit:- also you can do this for 9⁶ :- (730-1)²= (730)²+(1)²- 2(730)(1). Whole calculation can be done within 3 minutes
@coreymonsta75054 ай бұрын
It would probably be faster if he derived that formula then used it lmao
+1 to the expression and then times (9-1) which is equal to 9^6-1, so the answer is (9^6-1)/(9-1)-1, or you can simply use the formula of sum of a geometric series.
@mmfpv44114 ай бұрын
Sum all the pascal triangle coefficients for (10-1)^n for n=1 to n=5 (sign alternates) then do the sum of powers of ten. Way faster
@kennethstevenson9765 ай бұрын
I did the problem in 4 steps without the using of a variable using the distributive property.
@최정훈-i9b4 ай бұрын
(9^6-9)÷8
@МаксимЭлектрик-р3ы5 ай бұрын
111110(9) =66429(10) 😅 Просто перевести девятиричную в десятиричную в столбик.
@MathSync4 ай бұрын
i ❤ Mathematics
@coreymonsta75054 ай бұрын
at 2:00 you should just skip the middle two lines of work. And for (80 + 1)(80 + 2) technique was interesting, but you can just do 81*82 on paper in 10 seconds.
@pspandey97375 ай бұрын
A simple sum in GP
@mcichael96615 ай бұрын
It is extremely simpler and faster tocalculate the raised powers and just add the terms.
@olocomeu71374 ай бұрын
Tudo errado
@vanessawelles47605 ай бұрын
its actually easier/faster to simply do the addition by hand.
@gamer1223334444555555 ай бұрын
Why did you add the extra steps of substituting 80 for X? The number is small enough and the math is short enough that in this case it was more efficient to directly foil the numbers rather than make it a algebra problem. There doesn't seem to be a need to generalize one problem in to an algebraic form.