A Nice System of Equations | Math Olympiad | Algebra

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infyGyan

infyGyan

Күн бұрын

A Nice System of Equations | Math Olympiad | Algebra
Welcome to infyGyan, as we tackle an interesting system of equations from the Math Olympiad! In this video, we will break down the steps needed to solve this challenging problem and provide you with tips and strategies to tackle similar questions. Whether you're preparing for a math competition or simply love solving algebraic puzzles, this video is for you. Don't forget to like, comment, and subscribe for more engaging math content!
Topics Covered:
System of equations
Algebra
Problem solving
Algebraic identities
Algebraic manipulations
Solving systems of equations
Factorization
Quadratic equations
Math tutorial
Math Olympiad
Math Olympiad Preparation
#mathtutorial #systemofequations #problemsolving #mathhelp #algebra #learnmath #education #mathskills #math #matholympiad
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Пікірлер: 9
@MrGeorge1896
@MrGeorge1896 2 ай бұрын
Another way is to cube the second equation: x³ - y³ - 3xy (x - y) = -27 and replace x - y with -3: x³ - y³ = -9 xy - 27 and use this result to substitute x³ - y³ in the first eq.
@shmuelzehavi4940
@shmuelzehavi4940 2 ай бұрын
Nice. It was unnecessary to restrict yourself to real numbers. It came from the solution.
@kassuskassus6263
@kassuskassus6263 2 ай бұрын
Let xy=p and solve for p the equation 9p^2+27p+18=0. We'll get p=-2 and p=-1, so xy =-2 and xy=-1. x-y=-3 and xy=-2 gives (x,y)=(-2,1); (-1,2). x-y=-3 and xy=-1 gives (x,y)=((-3+sqrt5)/2; (3-sqrt5)/2); ((-3-sqrt5)/2, (3+sqrt5)/2).
@Quest3669
@Quest3669 2 ай бұрын
(x;y)= (-2;1); ( -1; 2); {(-3+ -√5)/2; ( 3+ -√5)/2}
@RealQinnMalloryu4
@RealQinnMalloryu4 2 ай бұрын
(y ➖ 3x+2). ➖ 3^1 (y ➖ 3x+1) .
@RajeshKumar-wu7ox
@RajeshKumar-wu7ox 2 ай бұрын
X=-1,-2,((-3+√5)/2), ((-3-√5)/2)
@RashmiRay-c1y
@RashmiRay-c1y 2 ай бұрын
If xy = t, the equations yield t[x^2+y^2+t] =-6 > t[(-3)^2+3t]=-6 > t^2+3t+2=0 > t= -1,-2. If t=-1, y=-1/x > x+1/x=-3 > x = 1/2[-3 +/-√5], y = 1/2[3+/1√5]. If t = -2, x+2/x=-3 > x=-1,-2, y=2,1.
@АндрейПергаев-з4н
@АндрейПергаев-з4н 2 ай бұрын
х^3-у^3=(х-у)*((х-у)*2-3ху) Если ху=а а*(3-а)=-2 а=-1, а=-2 Ну и х-у=-3, ху=-2 или ху=-1 Решение не составляет труда
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