A Very Nice Math Olympiad Problem | Solve for n | You Need To Know This Trick | Algebra

[@phillipmcduffie9353]

Well, n < 0 for sure. The term n^3 must be negative. Now, I'll watch a little of the video. A little while later .. Well, so one real root -5. And, two complex roots. Three roots in total. I has no clue how to solve this. So, thanks.

[@prollysine]

n^3-n^2+/-n+150=0 , (n+5)(n^2-6n+30)=0 , solu , n= -5 , 3+i*V21 , 3-i*V21 , 1 5 n=(6+/-V(36-120))/2 , n=(6+/-i*V(84))/2 , n=3+/-i*V21 , -6 -30 30 150

[@prollysine]

Thanks!

[@ngocdo5687]

n^2 - n^3 = 150. *. 150 = 25 + 125 = 5x5 + 125 = (-5x-5) - (-5x-5x-5) = (-5)^2 - (-5)^3 **. n = 5./.

[@SpencersAcademy]

Nice job 👏