Abaqus Explicit: Pendulum Impact with Material Damage

  Рет қаралды 48,060

Abaqus Acumen

Abaqus Acumen

Күн бұрын

Пікірлер: 48
@wahidachraf5656
@wahidachraf5656 7 жыл бұрын
thank you so much.can you please realise a video of wire rope or cable please
@sachina4576
@sachina4576 7 жыл бұрын
and also with gravity used
@geekretroworld
@geekretroworld 4 жыл бұрын
Your videos are awesome and I have been following you for some time now. Finally, I believe I have something to add. The reason the elements are not deleted is because your keyword needs to be "Shear Failure, Element Deletion=YES", you also need to tick element deletion in the mesh element type and in Field Output requests activate SDEG under Failure/Fracture and STATUS under State/Field/User/Time. Your elements should delete properly.
@abaqusacumen7397
@abaqusacumen7397 4 жыл бұрын
Thanks for sharing!
@MrKotur
@MrKotur 5 жыл бұрын
Thank you so much. This video really helped me. I only ever worked with static problems and this tutorial helped me model my dynamic problem :D.
@planctonman
@planctonman 6 жыл бұрын
Thank you so much! all the videos are worthy! Good work. :)
@bibinjose2527
@bibinjose2527 4 жыл бұрын
Than you sir, If there are multiple components then how to give shear failure to a particular component?
@palakshukla9341
@palakshukla9341 4 жыл бұрын
The maximum displacement of plate with element deletion is different from the plate without element deletion. what could be the reason. Please help
@mohdsalim6207
@mohdsalim6207 3 жыл бұрын
in simulation of low velocity impact on cfrp plate .there is one element distortion excessively bcz of that it get aborted .so plz guide me to remove that problem.
@paladynbroda8500
@paladynbroda8500 7 жыл бұрын
I have one question. I did exactly as you, but my ball went through the plate, not reflect. I assumed that problem at constant rotational velocity, but I am not sure.
@sajidali-zh7kd
@sajidali-zh7kd 6 жыл бұрын
Thank you sir. Can you please tell me how did you decide the angular velocity of pendulum ( at time 14:43 ) ? Did you assume it ? If yes then how the time period given by you ( at 16:22) is related to it ? If not then how to calculate it ? Could you please e-mail me
@RaSa-nz4ky
@RaSa-nz4ky 7 жыл бұрын
I want to replicate the piercing operation using abaqus.Can you please let me know the procedure for simulating the piercing operation?
@aakashs1806
@aakashs1806 3 жыл бұрын
Fantastic demo.
@abaqusacumen7397
@abaqusacumen7397 3 жыл бұрын
Glad you liked it!
@palakshukla9341
@palakshukla9341 4 жыл бұрын
can you please share any video for modeling explosion using abaqus CEL?
@amarrch100
@amarrch100 6 жыл бұрын
I wonder if any kind of mesh sensitivity was observed in this analysis.
@kitty861987
@kitty861987 7 жыл бұрын
thank you very much for your interesting video. I have a question , how can you calculate the rotary inertial value for this model ?
@minhly650
@minhly650 6 жыл бұрын
I = (2/5)mr^2 for full solid spheres.
@davidmanley7953
@davidmanley7953 6 жыл бұрын
Firstly, thank you so much for your informative and very useful videos. I have a question in relation to the rotary inertia, this was previously asked by Ryan McKnight The calculated kinetic energy given the 750 r/s, a radius of 500 mm and a ball mass of 1.5 kg is 105468 J Using the 0.77 value (for the solid sphere) produces a kinetic energy significantly less than the stated value. Using the rotary inertia I=mr^2 as per Ryan McKnight's value (375 ton mm^2) produces the correct kinetic energy in the Abaqus analysis. In the case where the rigid body reference point is at 0,500,0, as per your example. If the reference point is placed at the centre of the sphere, the rotary inertia is correctly defined using the 0.77 value. With the addition of an external reference point and coupling constraint in the assembly model, and the application of the velocity field at the reference point. The model also solves with the correct kinetic energy. Again thank you for you excellent work. If this is incorrect please comment.
@SebastianBari-h2q
@SebastianBari-h2q Жыл бұрын
another great video
@fareedahmad1440
@fareedahmad1440 7 жыл бұрын
Is it lowering the global size means lowering the number of nodes? i'm using Student Edition ABAQUS 2016 which limit only for 1000 nodes.
@preethamreddy6726
@preethamreddy6726 6 жыл бұрын
make the grid coarser to get less than 1000 nodes
@khodms
@khodms 3 жыл бұрын
I came across an interesting problem if you wish to try and make video on the same. It's a tensile test upto failure. It is a multilayer steel material with approximately 15-16 alternative layers of austenitic (ductile and low strength, 40%, 1000MPa) and martensite (10% failure strain at 1600MPa). The resulting behaviour is interesting.
@qwm1007
@qwm1007 7 жыл бұрын
I have the warning ( The *shear failure option will not be supported in the future release.) So, I have no damage. How to fix it? I put the keywords as in the video.
@rishabh1297
@rishabh1297 6 жыл бұрын
I have same problem too, if you are able to solve it then plz let me know
@larbigueraiche6721
@larbigueraiche6721 5 жыл бұрын
This warning concerns the future release of abaqus for which the *shear failure option will not be supported however you can use instead *damage initiation and *damage evolution options for modeling progressive damage and failure of materials. I have not paid attention to this warning since the model runs perfectly.
@frente927
@frente927 7 жыл бұрын
Excuse me, I just have one question. Why should the Reference Point's end point be 100,500,0 ? I think both start and end point are same... I'm confused...
@larbigueraiche6721
@larbigueraiche6721 5 жыл бұрын
Useful video. Thanks a lot.
@vivekanand8922
@vivekanand8922 7 жыл бұрын
how to get the pendulum oscillations?
@riyajohn4270
@riyajohn4270 5 жыл бұрын
Thank you so much for this video. Can you please upload a model for ball drop impact on laminated glass
@asuakoenochlarson4624
@asuakoenochlarson4624 7 жыл бұрын
Thank you so much. keep it up
@ksiaoussema9916
@ksiaoussema9916 6 жыл бұрын
thank you so much you did helped me a lot
@SouleymaneS
@SouleymaneS 7 жыл бұрын
Thank, please it is possible to make an impact video with illustration how one obtain the function response frequency. It is very important for me
@alejandroguerrero3229
@alejandroguerrero3229 7 жыл бұрын
Thank you very much for this tutorials, currently your videos are my principal learning source, can you upload a drilling simulation
@abaqusacumen7397
@abaqusacumen7397 7 жыл бұрын
Thank you. We will try
@سیدامینموسوی-ص7ه
@سیدامینموسوی-ص7ه 4 жыл бұрын
Soo nice
@MomoMomo-en2kt
@MomoMomo-en2kt 7 жыл бұрын
sir pls upload FSW(friction stir welding) simulation video
@somnathswain3011
@somnathswain3011 5 жыл бұрын
seems quickly is his fav word!XD
@rjrwashere
@rjrwashere 7 жыл бұрын
i need someone expert in abaqus... please contact me...
@masoodamirshami7628
@masoodamirshami7628 5 жыл бұрын
✌🏻✌🏻✌🏻
@ryanmcknight5063
@ryanmcknight5063 7 жыл бұрын
rotary inertia is wrong I=mr^2 m=1.5e-3 r=500 I=1.5e-3 * 500^2 I=375 its 375 not 0.77
@abaqusacumen7397
@abaqusacumen7397 7 жыл бұрын
Inertia calculated about the ball
@ryanmcknight5063
@ryanmcknight5063 7 жыл бұрын
thanks
@yisehakg5039
@yisehakg5039 6 жыл бұрын
you better start with appreciation.... thanks.
@mattkiernan3571
@mattkiernan3571 6 жыл бұрын
what a nonse
@minhly650
@minhly650 6 жыл бұрын
He used the formula of I = (2/5)mr^2 for solid spheres.
@benalinaserdine8923
@benalinaserdine8923 7 жыл бұрын
i need your help please, your mail please thank you
@jigerwala420
@jigerwala420 7 жыл бұрын
I have one question. I did exactly as you, but my ball went through the plate, not reflect. I assumed that problem at constant rotational velocity, but I am not sure.
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