thank you so much.can you please realise a video of wire rope or cable please
@sachina45767 жыл бұрын
and also with gravity used
@geekretroworld4 жыл бұрын
Your videos are awesome and I have been following you for some time now. Finally, I believe I have something to add. The reason the elements are not deleted is because your keyword needs to be "Shear Failure, Element Deletion=YES", you also need to tick element deletion in the mesh element type and in Field Output requests activate SDEG under Failure/Fracture and STATUS under State/Field/User/Time. Your elements should delete properly.
@abaqusacumen73974 жыл бұрын
Thanks for sharing!
@MrKotur5 жыл бұрын
Thank you so much. This video really helped me. I only ever worked with static problems and this tutorial helped me model my dynamic problem :D.
@planctonman6 жыл бұрын
Thank you so much! all the videos are worthy! Good work. :)
@bibinjose25274 жыл бұрын
Than you sir, If there are multiple components then how to give shear failure to a particular component?
@palakshukla93414 жыл бұрын
The maximum displacement of plate with element deletion is different from the plate without element deletion. what could be the reason. Please help
@mohdsalim62073 жыл бұрын
in simulation of low velocity impact on cfrp plate .there is one element distortion excessively bcz of that it get aborted .so plz guide me to remove that problem.
@paladynbroda85007 жыл бұрын
I have one question. I did exactly as you, but my ball went through the plate, not reflect. I assumed that problem at constant rotational velocity, but I am not sure.
@sajidali-zh7kd6 жыл бұрын
Thank you sir. Can you please tell me how did you decide the angular velocity of pendulum ( at time 14:43 ) ? Did you assume it ? If yes then how the time period given by you ( at 16:22) is related to it ? If not then how to calculate it ? Could you please e-mail me
@RaSa-nz4ky7 жыл бұрын
I want to replicate the piercing operation using abaqus.Can you please let me know the procedure for simulating the piercing operation?
@aakashs18063 жыл бұрын
Fantastic demo.
@abaqusacumen73973 жыл бұрын
Glad you liked it!
@palakshukla93414 жыл бұрын
can you please share any video for modeling explosion using abaqus CEL?
@amarrch1006 жыл бұрын
I wonder if any kind of mesh sensitivity was observed in this analysis.
@kitty8619877 жыл бұрын
thank you very much for your interesting video. I have a question , how can you calculate the rotary inertial value for this model ?
@minhly6506 жыл бұрын
I = (2/5)mr^2 for full solid spheres.
@davidmanley79536 жыл бұрын
Firstly, thank you so much for your informative and very useful videos. I have a question in relation to the rotary inertia, this was previously asked by Ryan McKnight The calculated kinetic energy given the 750 r/s, a radius of 500 mm and a ball mass of 1.5 kg is 105468 J Using the 0.77 value (for the solid sphere) produces a kinetic energy significantly less than the stated value. Using the rotary inertia I=mr^2 as per Ryan McKnight's value (375 ton mm^2) produces the correct kinetic energy in the Abaqus analysis. In the case where the rigid body reference point is at 0,500,0, as per your example. If the reference point is placed at the centre of the sphere, the rotary inertia is correctly defined using the 0.77 value. With the addition of an external reference point and coupling constraint in the assembly model, and the application of the velocity field at the reference point. The model also solves with the correct kinetic energy. Again thank you for you excellent work. If this is incorrect please comment.
@SebastianBari-h2q Жыл бұрын
another great video
@fareedahmad14407 жыл бұрын
Is it lowering the global size means lowering the number of nodes? i'm using Student Edition ABAQUS 2016 which limit only for 1000 nodes.
@preethamreddy67266 жыл бұрын
make the grid coarser to get less than 1000 nodes
@khodms3 жыл бұрын
I came across an interesting problem if you wish to try and make video on the same. It's a tensile test upto failure. It is a multilayer steel material with approximately 15-16 alternative layers of austenitic (ductile and low strength, 40%, 1000MPa) and martensite (10% failure strain at 1600MPa). The resulting behaviour is interesting.
@qwm10077 жыл бұрын
I have the warning ( The *shear failure option will not be supported in the future release.) So, I have no damage. How to fix it? I put the keywords as in the video.
@rishabh12976 жыл бұрын
I have same problem too, if you are able to solve it then plz let me know
@larbigueraiche67215 жыл бұрын
This warning concerns the future release of abaqus for which the *shear failure option will not be supported however you can use instead *damage initiation and *damage evolution options for modeling progressive damage and failure of materials. I have not paid attention to this warning since the model runs perfectly.
@frente9277 жыл бұрын
Excuse me, I just have one question. Why should the Reference Point's end point be 100,500,0 ? I think both start and end point are same... I'm confused...
@larbigueraiche67215 жыл бұрын
Useful video. Thanks a lot.
@vivekanand89227 жыл бұрын
how to get the pendulum oscillations?
@riyajohn42705 жыл бұрын
Thank you so much for this video. Can you please upload a model for ball drop impact on laminated glass
@asuakoenochlarson46247 жыл бұрын
Thank you so much. keep it up
@ksiaoussema99166 жыл бұрын
thank you so much you did helped me a lot
@SouleymaneS7 жыл бұрын
Thank, please it is possible to make an impact video with illustration how one obtain the function response frequency. It is very important for me
@alejandroguerrero32297 жыл бұрын
Thank you very much for this tutorials, currently your videos are my principal learning source, can you upload a drilling simulation
@abaqusacumen73977 жыл бұрын
Thank you. We will try
@سیدامینموسوی-ص7ه4 жыл бұрын
Soo nice
@MomoMomo-en2kt7 жыл бұрын
sir pls upload FSW(friction stir welding) simulation video
@somnathswain30115 жыл бұрын
seems quickly is his fav word!XD
@rjrwashere7 жыл бұрын
i need someone expert in abaqus... please contact me...
@masoodamirshami76285 жыл бұрын
✌🏻✌🏻✌🏻
@ryanmcknight50637 жыл бұрын
rotary inertia is wrong I=mr^2 m=1.5e-3 r=500 I=1.5e-3 * 500^2 I=375 its 375 not 0.77
@abaqusacumen73977 жыл бұрын
Inertia calculated about the ball
@ryanmcknight50637 жыл бұрын
thanks
@yisehakg50396 жыл бұрын
you better start with appreciation.... thanks.
@mattkiernan35716 жыл бұрын
what a nonse
@minhly6506 жыл бұрын
He used the formula of I = (2/5)mr^2 for solid spheres.
@benalinaserdine89237 жыл бұрын
i need your help please, your mail please thank you
@jigerwala4207 жыл бұрын
I have one question. I did exactly as you, but my ball went through the plate, not reflect. I assumed that problem at constant rotational velocity, but I am not sure.