ABCD−Parameters (Solved Problem)

[@jeevithaswamy5741]

On substituting I1 in V1 we can find A,B values as A=0.32,B=1.176 Thank you sir

[@divyarajsinhpadhiyar9739]

I have also same ans

[@dhanasekars8147]

Will you explain your answer??? B=(4-0.4705)=3.5295

[@bilal_ahmad9337]

Thank you 👍

[@VikasKumar-qn3ny]

@@dhanasekars8147 B=4-5.1764=1.176

[@husnioumer6986]

thank sir

[@sankhamitra3862]

Ans of H.W. will be A=11/34 & B=40/34

[@antarapaul564]

The best ever videos on circuit theory. Sir tomorrow I have my semester exam of circuit theory and I was just 0. After watching your videos on network theorems I have confidence to pass. If I will pass tomorrow.. you will be the reason sir. Thank you so much.

[@w1ndro1d]

Did you pass?

[@komalikagaikwad8457]

@@w1ndro1d 😂😂 she would have replied 🤦‍♀🤣

[@jethendraredykomerla5527]

@@komalikagaikwad8457 q😂😂😂😂😂😂😂

[@jethendraredykomerla5527]

@@w1ndro1d 😀😀😀😀😀😀

[@paypal290]

Please do more videos sir I am preparing for gate 2021 from your lectures only Please do videos of ECE sir

[@cairomarcellus977]

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[@kadenira5871]

@Cairo Marcellus instablaster :)

[@cairomarcellus977]

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[@cairomarcellus977]

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[@kadenira5871]

@Cairo Marcellus happy to help :)

[@adarshpal4219]

Wonderful lectures.... ❤❤❤

[@Softwareengineeringdev]

You are very good teacher

[@AsHiShChAuHaN-yd7dn]

Aapka knowledge to bda Kamal h sir( Your knowledge is excellent 👌)👏👏

[@amycoa]

Thanks a lot Professor

[@Govind36-w2z]

A:11/34 B:20/17

[@miiroderrick8821]

Thanks so much 🙏

[@girishgautam5838]

Ans A =0.323(11/34) B=1.176(40/34) C=0.029(1/34) D=0.470(16/34)

[@soar_hub]

Right

[@Codecrafter72]

How??? How you got 40??

[@tapibyai6477]

thank you sir

[@nitishkumarprajapati6096]

Thanks Sir 😃😃

[@qwertypad1387]

Sir while finding the relation between Vx and the currents you haven't included V2 in the KVL equation as the 4 ohm resistor end is connected to the positive terminal of V2

[@anirudhyaguchait5842]

A= 11/34 ,B=40/34 ...is my ans...😁😁😁🤗🤗🤗...

[@karthikbcreddy]

Which clg

[@kowsik222]

Thanks

[@surajkumar-xg1rw]

Sir next please start #Transient. This is Hamble request to you

[@rishabhbahoria1298]

A : 0.3235 or 11/34 B : 1.1764 or 40/34

[@kirubhakirubha8818]

Sub the value of I1 in eq 3 ...... v1=11i1+4i2 We can get V1=11/34v2-40/34 i2

[@ritushreemahata6003]

A=0.3235 and B=1.1764

[@rishabhsisodiya877]

A=11/34 B=40/34

[@manavmalhotra8513]

right

[@amarendrakumarsingh4900]

How please send me the picture

[@kiranmarapureddy5509]

Sir is we find z parameters instead of finding abcd parameters and convert them into abcd parameters in exams

[@rajani2292]

Tq sir!

[@kunnu_4]

10:51 / 11:14

[@ganeshmula4508]

H. W ans A=11/34, B=40/34

[@nishitmeena4791]

A=0.323 ,B=1.17

[@athukuricharan84]

can you explain

[@VikasKumar-qn3ny]

i1 value put eq. v1 then after solve this A=11/34 ,B=1.1764

[@dyias2024]

Sir what law did you follow in calculating vx please reply sir

[@karan-ce8jf]

He used kvl...

[@mindmove3771]

Why Is sign for parameters not taken into consideration???

[@bhaskaralakshmiganisetti3779]

A=0.323 B=1.176

[@HYPERGAMING-nh3tj]

A=11/34=0.3235 B=40/34=1.1764

[@eswararaor9312]

What is the z value

[@kottavalasaumamaheswari2163]

Sir in terms of z lo మీరు cheppinatcheste exams lo marks vestaraa

[@yamaharx100vlogs-zf6yy]

a=0.32352 b=1.17647

[@gopikrishnan1827]

B=11.764, A=0.3235

[@hemani7994]

I2 current direction opposite aa

[@VeniGamkonda]

A will be 0.0323 and B will be 1.176 sirr

[@parikshit3271]

A = 44/136 ; B = 160/136

[@jambugarisurendranath583]

A=11÷34,B=60÷17

[@sharialamia6729]

plz some one tell me how to get A and B by solving equation like we got C and D??

[@VikramKumar-st7xs]

Simply replace i1 in v2

[@nitian8012]

Put the value of i1 in the value of v1.

[@namanibhavana3597]

How can we find |Z| ?

[@jayvamsisayyapureddi7846]

Ad- bc

[@rvlog7163]

A=11/34,B=40/34

[@adarshpal4219]

Transient 🙏plz

[@manojknowmore]

11/34,40/34

[@rahularutla7423]

Transients

[@raceregos]

Looks like im not going to be an engineer :(

[@alphasatari]

A : 0.3235 B : 1.1764

[@supriyodas5927]

how?

[@s.m.senses7199]

🙏❣

[@avunooritagore6089]

A=3/17 B=14/17

[@ShrutiAgrahari0803]

A=0.3235,B=1.176

[@Atnarp]

A=11/34 B=20/17

[@RaselAhmed-xc4wv]

How send me pic plz

[@ikennaakupuome9595]

match the ABCD equation to the Y parameter equation, you will get the answer

[@MaheshKumar-gi5gj]

A=0.323 and B=1.1764

[@mimoray6708]

a =0.3235 b= 1.176

[@krishnachellamuthu1722]

A=1.176 B=0.3225

[@vishwastg8983]

A=11/34,B=40/34

[@___samarth_bawasker]

A = 0.32, B = 1.176

[@parthib.1555]

A = 11/34, B = 20/17

[@luckysuman7838]

A=11/34, B=20/17

[@sarangae9437]

A=0.323 B=1.176

[@vishalks7342]

A=0.3235 B=-1.176

[@Codecrafter72]

How??? How you got 40??

[@தமிழாதமிழா-ர1ட]

A=11/34 B=40/34

[@reficeismail6520]

A=11/34 B=40/34

[@sumanlai4044]

A=11/34,B=40/34

[@mugaberobertsolomon8340]

A=0.3235, B=1.1765

[@aneeshafathimaalavudeen3489]

A= 11/35,b=40/34