shouldnt the result of (1+sqrt(5))(a+b*sqrt(5)) = (a+5b) + (b + a)sqrt(5) regardless as a result you would get b = -a ---> -4a = 2 --> a = -1/2 which is not an integer leading to the same conclusion that u is not in Z[sqrt(5)]
@ezraguerrero28794 жыл бұрын
Yes, he had a typo that luckily did not alter the result.
@asht7502 жыл бұрын
can you add more abstract algebra videos on modules and fields? Module theory and field theory with Galois theory?
@frankreashore3 жыл бұрын
Nice. I liked your counter examples.
@addemfrench4 жыл бұрын
At about 7:00 I think you're saying that if a=/=0 then b=0. Not clear to me why. Maybe something like: a^2+3b^2 is a large positive number so we need to minimize it if this is going to divide `a`?
@timurpryadilin88304 жыл бұрын
Can you make a video about a proof of the Fermat's Last Theorem for cases n=3,4,5? For n=4 it is quite trivial, and for n=3,5 it requires some ring algebra, but I am sure you can present it easily
@MichaelPennMath4 жыл бұрын
I already have an n=4 video!! kzbin.info/www/bejne/aHrOhWdomcZkmJo I will put those other cases "on the list".
@timurpryadilin88304 жыл бұрын
Thank you! I am looking forward for tge other cases! By the way, do you have any understanding of the the Andrew Wiles's proof or at least the theory of elliptic curves? I want to learn them on some minimal level an perhaps you could make a video about them too
@firettoYT2 жыл бұрын
In your definition of irreducible, you forgot to state that an irreducible element cannot be a unit.
@heisenbergmuzik49484 жыл бұрын
I think there is some misunderstanding. Plz clarify. a/a^2+3b^2 would belong to Z only for a=0 coz a,b belongs to Z.