I once came across a physics paper that employed the Trigintaduonions (T). Thirty-two dimensional numbers!
@MercuriusCh Жыл бұрын
I really need the link. I want to see its application...
@kpopalitfonzelitaclide2147 Жыл бұрын
Need the link
@michaelgerardi2126 Жыл бұрын
This was it. Not sure what's harder to read, the math or the broken English! arxiv.org/PS_cache/arxiv/pdf/0704/0704.0136v2.pdf
@rrr00bb1 Жыл бұрын
Geometric Algebra for n-dimensional space has 2^n coefficients in its objects; so it gets quoted as 2^n "dimensions". 5D space for conformal algebra is common, which is 2^5 dimensional. The 2^n comes from n directions in space included or not; because directions in space square to real numbers -1, 0, or 1.
@KarlFredrik Жыл бұрын
Crazy. Wonder how long time it would take to understand än article like that.
@herothecrow994 Жыл бұрын
This is the epitome of “Elementary students when their math has letters” “Higher math students when their math has numbers”
@AmryL Жыл бұрын
I'd love to one day learn enough to understand a word of what this video is teaching.
@izak5775 Жыл бұрын
Same 😂
@philipm3173 Жыл бұрын
Check out the channel dialect. You will get an intro to vector calculus. They also demonstrate elementary matrix algebra. They just started a series on Christoeffel tensors so if you can get Riemannian geometry, you're well on your way to getting quaternions, it's just adding more to matrix operations.
@sazam974 Жыл бұрын
@@philipm3173 is there a channel to explain anything of what you just said?
@philipm3173 Жыл бұрын
@@sazam974 3Blue1Brown
@philipm3173 Жыл бұрын
@@sazam974 they have a 16 part course called the essence of linear algebra which introduces vectors and linear transforms.
@zlodevil426 Жыл бұрын
I would love to see a video on the splithypercomplex numbers!
@Utesfan100 Жыл бұрын
Zorn matrices might be nice. Yes, that Zorn.
@synaestheziac Жыл бұрын
So splithy
@pugza1s731 Жыл бұрын
split hyper complex?
@zlodevil426 Жыл бұрын
@@pugza1s731 yes
@henrikljungstrand203610 ай бұрын
Yes, especially a way to systematically construct splithypercomplex numbers over any field, including those of characteristic 2. This most likely means not all independent generators can be anticommuting but instead may be "skew commuting" rather.
@General12th Жыл бұрын
Why was Hamilton considered such a jokester? Because he always said i j k.
@TomFarrell-p9z Жыл бұрын
The first telephone company in Hamilton Ontario was started by a physicist. He built a young ladies dormatory on the 2nd floor of the exchange because he knew Hamiltonian operators do not commute.
@PunmasterSTP2 күн бұрын
@@TomFarrell-p9z This is exactly the type of humor I live for! Thank you both!
@edoliveira188516 күн бұрын
I like what this means for Physics: if there are more than 4 dimensions, there are at least 8. if there are more than 8 dimensions, there are at least 16. (etc) Physics requires a square root (that's why spinors were invented, and spinors are just a rotation on quaternions)
@RealClassixX Жыл бұрын
"Coming up" with quaternions for myself during a boring university lecture is still one of my proudest moments.
@mohammadmehdivazir511 ай бұрын
howw
@Karan_k188810 ай бұрын
I did the same in 9th grade
@schizoframia487410 ай бұрын
Like come up with the multiplication rules? Or something else?
@datboy0387 ай бұрын
@@schizoframia4874probably the multiplication rules
@JxH7 ай бұрын
Was there a bridge nearby ?
@AlexiMorinDuchesne10 ай бұрын
What goes wrong if you try to use the same construction with two different algebras, for instance if you take R x C?
@freyc113 күн бұрын
If you multiply two such numbers following the rule of multiplication, you generally won't get another number of that form. For instance, (ac-d*b) is not necessarily real, if a and c are real numbers and b and d complex numbers.
@littlekeegs8805 Жыл бұрын
Seeing how we start losing common features like having no zero divisors or communitivity as we apply this construction, I'd be curious if we lose anything else after the sedenions, or if they have the same basic properties after that.
@GerhardTreibheit Жыл бұрын
After the sedenions, your balls fall off
@Cielo20023 Жыл бұрын
Lmao
@sk4lman Жыл бұрын
I kinda hope it all unravels into complete anarchy as you move up through the dimensions, and then suddenly assumes strict rules again. Repeat ad infinitum. That would be awesome :)
@stevanwhite Жыл бұрын
Yes, this is a very deep question. Is there an infinite family of (increasingly abstruse) algebraic properties, which are incrementally lost as the ladder is climbed? Or, do the (somehow meaningful) algebraic properties completely run out at some point, and as abstract algebras, the higher-dimensional conjugation algebras are all the same? (But then, they are continuous algebras parameterized by 2^n copies of the reals... which in itself is an algebraic property. They are not isomorphic...)
@stevanwhite Жыл бұрын
If you're hoping for things to come back being like the wonderful unity of the complex algebra, sorry, that won't happen. Any algebras that does just what the complex numbers do, is itself the complex numbers. Etc. Fortunately, different algebras are different, and life is richer! These things came to life as abstractions, but people have applied them to real-life problems. For example, multiplication by quaternions preserves geometry in 4 dimensions, and thereby, motion and scaling of solid 3-dimensional objects in 1 time dimension. Their non-commutativity reflects the non-commutativity of 3-D rotations.
@allinclusive169 Жыл бұрын
Since quaternions have very interesting properties when it comes to describing rotations in 3D space, I'd love to see a video about practical (or not so practical) applications of these higher dimensional algebras. Also, what about algebras, that don't obey this 2^n dimension rule? Great video! 🎉
@deltalima6703 Жыл бұрын
Google "cohl furey"
@CM63_France Жыл бұрын
Such as those used in matter theories.
@rodrigotrujillo5451 Жыл бұрын
😢😢😢😢😢
@holliswilliams7717 Жыл бұрын
They don't have applications.
@levprotter1231 Жыл бұрын
There are attempts at applying Octonions to physics. Probably not the beat idea, but there are some interesting results there.
@Zebinify Жыл бұрын
And there's a nice trivia for the "motivation" of this construction. If we would like to preserve the norm multiplication rule, |X Y| = |X||Y|, we have to stick to the 2^n dimensions.
@Utesfan100 Жыл бұрын
So long as |a| is quadratic in the components of a. Otherwise matrices provide a counter example.
@sinclairabraxas3555 Жыл бұрын
doesnt this have to do with the topological characteristics of spaces? I've been getting into topology and there are some theorems dealing with parity of dimensions and how they don't allow for certain constructions
@benjaminojeda8094 Жыл бұрын
On sedenions there are Zero divisors
@henrikljungstrand203610 ай бұрын
@@benjaminojeda8094 Yes, and they are not a composition algebra, that is they fail the important rule: forall X and Y: |X Y| = |X||Y|. Where || is the quadratic norm form in question (related to a symmetric bilinear form sometimes called an orthogonal form).
@henrikljungstrand203610 ай бұрын
@@Utesfan100 I am pretty sure that, as long as we investigate *composition algebras* rather than merely the special case of *normed division algebras*, there are 3^n dimensional algebra analogues with cubic norms, to these 2^n dimensional algebras with quadratic norms. In the general case these norms are not necessarily positive definite but merely nondegenerate indefinite.
@dcterr1 Жыл бұрын
Amazing construction! I already know about the first five of these algebras, but I've never seen this way to get from each one to the next, and I never even knew there were infinitely many of them! Great, educational video!
@jakobthomsen1595 Жыл бұрын
Really cool! And yes, interested in the split (and the dual) variants!
@RalphDratman Жыл бұрын
THIS IS GREAT! Thank you Michael!
@almazu2770 Жыл бұрын
it would be nice to see a video about the split octonians
@enumeratenz10 ай бұрын
I would like to see this too
@briangronberg6507 Жыл бұрын
This is fantastic. I’ve been looking forward to this video for a while so thank you, Professor!
@rohitg1529 Жыл бұрын
Would love to see some examples of zero divisors in the sedonians
@henrikljungstrand203610 ай бұрын
The basic idea is that a^-1 * (a*b) ≠ b ≠ (b*a) * a^-1 generally. That is multiplication by the reciprocal of a is not the same as division by a, which means these reciprocals are not true inverses. You need to pick four fully independent sedenions a, b, c and d (none of them expressible through multiplying and/or adding the others). If you pick them to be orthogonal i think you may form (a+b) * (c+d) or something and show that is then zero. I don't remember exactly though, it was some years since i read about it. Iirc there is some claim about the zero divisors of the sedenions being closely connected to the Lie group G_2.
@riccardosarti323412 күн бұрын
Great video! For octonions, I was thinking about taking (1,0), (0,1), (i,0), (0,i), (j,0), (0,j), (k,0), (k,0) as generators - in analogy with what was done for quaternions starting from C (so taking (1,0), (0,1), (i,0), (i,0) as generators). But I can see that including some negative signs in the definition, we get the very nice triangle at the end!
@LuigiElettrico Жыл бұрын
I love complex numbers. Subscribed! Any video on this topic is appreciated.
@ow7398 Жыл бұрын
Your best video in a while. You always make good videos but this one was particularly great
@JamesLewis2 Жыл бұрын
When you kept pronouncing "sedenions" as "sedonians", I kept thinking about Sedona, AZ.
@edhodapp6465 Жыл бұрын
This did it for me. I just joined your Patreon. Sigh, I work full time writing code for folks, so not always possessing enough free time, but I like to try. :)
@SpartaSpartan117 Жыл бұрын
The most famous onsight in history was Hamilton's onsight of the quaternions
@w.randyhoffman1204 Жыл бұрын
Ummm...I think Newton's insight about gravity and Einstein's insights about relativity (among others) are *just a tiny bit* more famous than that. ;-)
@mathophile716 Жыл бұрын
@@w.randyhoffman1204we are talking about history of mathematics here :)
@praharmitra Жыл бұрын
@@mathophile716Newton’s insight into Calculus then.
@aadfg0 Жыл бұрын
If I see you spell it like that, it's on sight.
@kasiphia Жыл бұрын
@@praharmitra Let's not debate what's greater, Newton, Hamilton, doesn't matter. All true geniuses.
@tomholroyd7519 Жыл бұрын
Interesting, the conjugation on the pairs (a, b) is reminiscent of the twist structure (a, b)* = (b, a) but using two different negations instead. So if you think of b as being the complement of a everywhere
@eveeeon341 Жыл бұрын
I find the rules for going from one algebra to the next fascinating. The video states that it was produced by looking at R->C->H, but is this the only set of rules that can do this? And is it minimal or maximal? Can you remove or add additional rules? I'm guessing you can't just remove them, but what about removing and adding a different rule, or reframing the whole picture.
@angeldude101 Жыл бұрын
Nope, it isn't! There's another process that generates the same 3 algebras at the start, but never loses its associativity, and that is Clifford algebras. The Reals are Cl(0,0); Complex numbers Cl(0,1); Quaternions Cl(0,2). Past that it diverges from the Cayley Dickson construction with Cl(0,3), Cl(0,4), and so on. Like the Cayley Dickson construction, each is 2 times larger than the prior, and in general Cl(0,n) is 2^n dimensional (or rather Cl(p,q,r) is 2^(p+q+r) dimensional). Most explanations of Clifford algebras won't actually define the algebras in this way though, instead generating them from Cl(2), Cl(3), and so on, and then using the even subalgebras to extract the Complex numbers and Quaternions respectively. This method more cleanly shows that the systems in question are specifically the algebras of rotations in 2 and 3D respectively.
@henrikljungstrand203610 ай бұрын
Some while ago i tried working out something similar to Clifford algebra, but using the Moufang identities and scalar squaring, anti-commutation and anti-association relations rather than associativity and just scalar squaring and anti-commutation relations. This would produce O from H, but then produce something entirely else from O. Never got the calmness of mind to complete my reasoning though, life is a bitch sometimes.
@amitphogat1729 Жыл бұрын
Wow!! Simply, one of the best explanation.
@disgruntledtoons Жыл бұрын
@6:43 you refer to the results as a "non-negative integer" when I think you meant to say "non-negative real", and likewise shortly following.
@d69p-eix7 күн бұрын
This is so much easier to construct and understand with code, ones simply constructs higher levels from the components of lower levels
@marcelopires1773 Жыл бұрын
Congratulations, the explanation was clear and usefull. Thanks.
@tompw31417 күн бұрын
This is wonderful! And I'd love to see a video on the split complex numbers etc :-)
@ciCCapROSTi Жыл бұрын
Good one mate, and the suggestions in the other comments already cover what I'm further interested in in number sets. I learned these in university, but we didn't go into the regularities or construction rules of them.
@meerak915 Жыл бұрын
The Title or Description should mention that this is covering the Cayley Dickenson Construction as this is one of the better and more complete lectures on the topic.
@ianmathwiz7 Жыл бұрын
What properties do we lose going from the sedenions to the 32-dimensional algebra?
@holliswilliams7717 Жыл бұрын
anything of interest is lost
@locrianphantom3547 Жыл бұрын
That from these honored dead, they take increased devotion to the task for which they gave the last full measure of devotion. 💀
@lizzycoax Жыл бұрын
woah this is really interesting, im glad you made this video
@humbledb4jesus Жыл бұрын
By far, one of my favorite videos...
@BethKjos Жыл бұрын
@14:30-ish there's an interesting claim about phi(C). The fact that phi(C) behaves like R' does not rule out the supposition that C has some je nais se quoi not preserved under phi.
@youtubepooppismo5284 Жыл бұрын
I love the cayley dickson construction!
@tomholroyd7519 Жыл бұрын
aa* is another way of writing a and not a --- indeed x*(x+1)=1 (adding one is conjugation) in the finite field Z2 is an irreducible polynomial and the "splitting field" is F4, where something can be both true and false without the logic dissolving into triviality ... so there is a sequence of logics, 2 valued, 4 valued, 3 valued ... and then stop because 3 is enough. #RM3
@trumanburbank68992 ай бұрын
Roughly speaking, octonion element multiplication could be written as e_p e_q = ±e_{p XOR q}. Write the subscripts in binary e_0 = 1, e_1 = i, e_2 = j , etc. Then octonion multiplication would be e_p e_q = C_{pqr}e_r where r = p\text{ XOR }q, and the $ C_{pqr} $ is a 3x3x3 array with elements -1, 0, or +1 .
@tonyhorn295427 күн бұрын
I'm pretty good with maths but this is above my understanding. I'm fine up to and including complex numbers. I didn't even know there was more above that.
@michaelparis6039 Жыл бұрын
I would love to see some content where you could motivate an isomorphism from this construction to the language of geometric algebra. It seems to be related
@angeldude101 Жыл бұрын
Well octonions and above are non-associative, but Clifford algebras are _always_ associative, so the isomorphism stops at the quaternions.
@franks.6547 Жыл бұрын
Maybe it is more of a coincidence that the more "primitive" structures like complex numbers and quaternions show up in unrelated contructions. And yes, Octonians and above don't fit in any geometric algebra, because of associativity, as was said above. What would the cartesian product be? Addition of elements with different grades? The isomorphic embeddings of R, C and H may just not be related to each other in a way that resembles the Cayley-Dickson construction, because it uses tools not available within one Clifford algebra. Or maybe you would need a very large one to have blades of grades that don't interfere with each other that they become "free" = independent like the components of a Cartesian product, but then you don't actually benefit from Cliffordness.
@MathFromAlphaToOmega Жыл бұрын
I know that there's an identity for writing (a^2+b^2)(c^2+d^2) as a sum of squares, and similarly for (a^2+b^2+c^2+d^2)(e^2+f^2+g^2+h^2), the first coming from norms in C and the second from norms in H. Is there an analogous formula in 8,16,... dimensions? By the way, I'm pretty sure that diagram at the end is basically projective 2-space over F_2. We can treat e_1 as the vector (0,0,1), e_2 as (1,0,1), and so on. Then that explains the looping on the collinear points.
@jakobthomsen1595 Жыл бұрын
I think the second identity you mentioned is this one: en.wikipedia.org/wiki/Euler%27s_four-square_identity
@MathFromAlphaToOmega Жыл бұрын
@@jakobthomsen1595 Thanks for the article. It looks as if it's only possible up to 8 variables if you want linear expressions in the squares, but there are analogues for any power of 2 if you allow rational functions.
@henrikljungstrand203610 ай бұрын
Thanx to octonions, there is such a formula in 8 dimensions, yet there is none in 16 dimensions or higher.
@phee4174 Жыл бұрын
a video on the split octonians would be neat
@stephanevernede8107 Жыл бұрын
Thanks for the great video I find it easier to see those algebras as the even subalgebra of a n dimensional geometric algebra with unit metric 2D gives the complex numbers, 3D the quaternions, ... The conjugate is then simply the reverse and all properties simply derives from the geometric product (no need to memorize the multiplication tables) Also it is then easy to go to split algebras by changing the metric , for example dual quaternions is the even subalgebra of a 4D geometric algebra with a 0,1,1,1 metric
@kikivoorburg Жыл бұрын
All geometric algebras are associative, the octionions aren’t! That means the octionions and beyond are not the even subalgebras of some geometric algebra. Depending on your perspective this is either disappointing (a nice pattern doesn’t hold) or exciting (the Cayley-Dickinson Construction is a different way to generate algebras that happens to line up with the Geometric-Algebra-derived ones in low dimensions!)
@stephanevernede8107 Жыл бұрын
@@kikivoorburg Thanks for your remark! The next question is where does the equivalence breaks between the 2 algebras ( octonions and the even subalgebra of a 4D geometric algebra with unit metric) . I guess those 2 algebras still share a lot.
@francescaerreia8859 Жыл бұрын
Can you do geometric algebra next? The dimensions scale up forever there too but much more nicely, it seems
@asmithgames5926 Жыл бұрын
Id like to see what insights this gives us into Abstract Algebra, if we keep climbing tonhigher and hugher dinensions!
@holliswilliams7717 Жыл бұрын
none at all
@nathanbarajas9174 Жыл бұрын
Thanks for the video.
@AlbertTheGamer-gk7sn Жыл бұрын
Also, we can add virtual numbers, or numbers with negative absolute values, to get even more complex numbers.
@henrikljungstrand203610 ай бұрын
Such numbers are called split complex numbers, or rather they are part of those numbers.
@Gordy-io8sb10 ай бұрын
Yeah, and there could be a virtual unit, v, so that abs(a*v)=-a. |iv|=-i also, there could be |(-a)v|=a Interesting, isn't it? The general form could be: a+bv Higher orders could entail: a_0+a1v1+a2v2+...+a2^n-1v^2^n-1 Just my speculation.
@henrikljungstrand203610 ай бұрын
@@Gordy-io8sb Try conic complex numbers, also called tessarines and bicomplex numbers. They are a commutative algebra over the complex numbers, indeed they are a composition algebra with complex quadratic norm. All complex numbers are represented as norms (or absolute values if you like) of numbers in this algebra.
@I_exist_I_guess Жыл бұрын
has anyone done some theory on the proprieties of infinite dimensional number? like, aleph_0-nions or something. How would they work? _can_ they work? would they have any useful proprieties? it seems like such a wild concept that it can't be usefull but then again p-adics are a thing
@josephengel2091 Жыл бұрын
If rotations in N dimensional space can be described by, for the lack of better phrasing, 2^(N-1)-ions and fractal geometry allows for fractional dimensions, that leads me to wonder if we can talk meaningfully about numbers like objects between the complex and the reals or the complex and the quaternions, and, if so, what sorts of properties would those numbers or number like objects would have, assuming they exist?
@asmithgames5926 Жыл бұрын
I was wondering the same thing, although I hadn't considered the fractal nature. Perhaps they would be half-associative 😂😂 We should invent a system.
@cottoncandyreverie Жыл бұрын
At this point I think we might want to ask what limits there are, if any, to the amount of different types of numbers and the possible properties of said numbers that can be logically constructed within the rules of mathematics. To what extent can the set of ALL numbers be comprehended at all?
@henrikljungstrand203610 ай бұрын
That is not how it works. There is a correspondency between rotations of vectors, and of spinors though, but you need to study something called Bott periodicity and Clifford periodicity to understand it properly. For real vectors of dimension n, the corresponding spinors can be real, complex or quaternion, and they can be either single spinor or two half spinors. Each complex spinor has a conjugate spinor, these function somewhat similar to half spinors. SO R¹ ≈ Spin R¹ SO R² ≈ Spin C¹ SO R³ ≈ Spin H¹ SO R⁴ ≈ Spin H¹± SO R⁵ ≈ Spin H² SO R⁶ ≈ Spin C⁴ SO R⁷ ≈ Spin R⁸ SO R⁸ ≈ Spin R⁸± SO R⁹ ≈ Spin R¹⁶ SO R¹⁰ ≈ Spin C¹⁶ SO R¹¹ ≈ Spin H¹⁶ SO R¹² ≈ Spin H¹⁶± SO R¹³ ≈ Spin H³² SO R¹⁴ ≈ Spin C⁶⁴ SO R¹⁵ ≈ Spin R¹²⁸ SO R¹⁶ ≈ Spin R¹²⁸±
@henrikljungstrand203610 ай бұрын
So for example quaternions are related to 3D and 4D rotations. While octonions (with various internal structures) are related to 5D, 6D, 7D and 8D rotations. 9D rotations are special since they introduce tensoring of previous spinors with 16D spinors, which continue by periodicity onwards.
@astroid-ws4py Жыл бұрын
Which book is good to read about this fascinating subject?
@ilanlevin463 Жыл бұрын
I'd recommend Chapter 33 in "The book of involutions", a book by Alexander Merkurjev, Jean-Pierre Tignol, and Max-Albert Knus. But I'm a graduate student mastering algebra, so this might not suit your preferences. In that case I'd recommend "On Quaternions and Octonions". A book by Derek A. Smith and John Horton Conway.
@acompletelyawesomenameyay2587 Жыл бұрын
Has anyone done papers/research on infinite dimensional numbers?
@EebstertheGreat Жыл бұрын
FWIW, the word is "sedenion," not "sedonion." It comes from the Latin _sedecenarius_ meaning "sixteen-fold." So the word should really be "sedecenion," but I guess that was too long.
@AlbertTheGamer-gk7sn Жыл бұрын
Sedenants are 4D graphical regions.
@cftug Жыл бұрын
I am going to pronounce that "oct-onions" and you can't stop me.
@cd-zw2tt Жыл бұрын
especially consiering he calls them "sed-OH-nee-ans" instead of "sed-EN-ee-ons"
@TimothyReeves Жыл бұрын
@@cd-zw2tt What do you call people from Sedona, Arizona?
@TomFarrell-p9z Жыл бұрын
@@TimothyReeves "John." But he's the only one I know in Sedona. 🙂
@MNbenMN Жыл бұрын
@@cd-zw2ttHmm? Who said onions?
@mus3equal4 ай бұрын
awesome thanks!
@spawn142001 Жыл бұрын
I've heard it say that each step up looses a degree of freedom or something like that and they become increasingly more limited in use. I'd be more interested in someone discovering a successful system for say tricomplex numbers or some. Complex is two. Quaternians is 4 and 4 dimensional. Good for 3d rotations. But amongst that ladder we haven't found one that does the in-betweens. There's no purely 3dimensional system it goes from 2d to 4d. And I believe one could be discovered but it's rules might be unique and outside of the ladder. It's arbitrary but arguably all systems in mathematics are. As long as it works and it's useful it really doesn't matter how different it is from those in that ladder. That's what I mean by arbitrary. Mathematics is infinite and the number of discoverable calculatable systems are infinite. As well as the uncomputable systems.
@evandrofilipe1526 Жыл бұрын
Geometric algebra explains all of this. You can define one by saying how many and what type of basis vectors you want to have. In general G(x, y, z) is saying there are x vectors that square to 1, y vectors that square to -1, and z vectors squaring to 0. G(2, 0, 0) is basically 2d space and isomorphic to the complex numbers. To get something for 3 dimensions simply: G(3, 0, 0) -> 3D space. The rules for working with geometric algebra are very simple and gives as a greater understanding of the objects we use. Find out more: kzbin.info/www/bejne/bGHdkJumeqaneposi=87Zw1fA8KWX3Bedu G(4, 0, 0) -> Quaternions G(8, 0, 0) -> Octonions G(2^n, 0, 0) -> 2^n-"nions"
@kikivoorburg Жыл бұрын
It’s worth noting you _can_ make 3D number systems, they just don’t act like complex numbers. If you demand that the elements of your algebra i and j square to -1 like with the complex numbers, Quaternions, etc. It is (as far as I’m aware) provably impossible to get 3D numbers to work. This, however, does work: 1^2 = 1 i^2 = j j^2 = i i^3 = j^3 = -1 Giving the set {1, i, j} which is 3D and closed under multiplication! It does have zero-divisors though. Look up the video “Let’s invent the Triplex numbers”, that’s where I got this example from. It’s well worth a watch! I think you could define any dimensionality just by having a unit q where q^n = +- 1 This algebra is closed under multiplication and has n dimensions: {1, q, q^2, q^3, … , q^(n-1)} Edit: also, multiplying by i or j in the Triplex numbers both corresponds to some rotation about the diagonal axis (passing through 0 and 1+i+j) so I’m not sure you could do other 3D rotations with it.
@kikivoorburg Жыл бұрын
@@evandrofilipe1526 the relationship for the Octonions doesn’t actually hold, because all geometric algebras are association and the Octonions aren’t! The Cayley-Dickinson Construction splits off from GA after the Quaternions
@jameswise9171 Жыл бұрын
11:17 Minor nitpick: I would've done (1,0)(c,d) I was trying to verify that (1,0)(a,b) was in fact just (a,b) according to the above equation and I kept getting tripped up by a and b being different in the two equations
@BongoFerno Жыл бұрын
Can you post the "inverse Cayley´-Dickson construction". The construction to go from S to R?
@andrewparker8636 Жыл бұрын
I think it would be interesting (although maybe not practical 🤔) to do a follow up video on semi-algebras and the fact that if you tensor any of these algebras with C then you're going to get a matrix algerba over C. I think this is really interesting as it effectively shows that all these algebras are somehow just matrix algebras.
@ВасилийТёркин-к8х Жыл бұрын
Matrix algebras ate associative which isn't the case for octonions.
@XenophonSoulis Жыл бұрын
22:30 why did we do water?
@xyz.ijk.5 ай бұрын
Outstanding video. I love dummy videos ... they always make me smarter ... and I acheive a new level of dummyhood.
@fritzp9916 Жыл бұрын
At about 6:40, you say "nonnegative integer" but I'm pretty sure you mean "nonnegative real number".
@benjaminbrat3922 Жыл бұрын
Yes, please, more :) I don't suppose you would know a nice mnemonics or shorthand to remember this last diagram? It's ... complex
@deltalima6703 Жыл бұрын
Imagine one.
@travisporco Жыл бұрын
I see quaternions come up in 3-d rotations, but what is the "killer app" of the octonions?
@Philomatha Жыл бұрын
Unit quaternions (isomorphic to SU(2)) generate rotations since they're a double cover of SO(3). Their relationship with the groups SO(3) and SU(2) are among the reasons of many other applications of quaternions to physics. In a similar way, octonions are deeply related to physics and the standard model; for more info I recommend taking a look at: kzbin.info/www/bejne/pJiUk4CpiNSendk
@henrikljungstrand203610 ай бұрын
Quaternions are used for both 3d and 4d rotations, while octonions may be used (in less obvious ways) for 5d, 6d, 7d and 8d rotations.
@fabiocaiazzo2715 Жыл бұрын
Can you explain why there are also 480 possible definitions for octonion multiplication?
@kkanden Жыл бұрын
great video!
@d.lawrencemiller575515 күн бұрын
What's up with octonions losing zero divisors? Why does that happen? Do 8-dimensional manifolds not cross the zero axis? That doesn't sound right. Are the two connected or no?
@Stobber1981 Жыл бұрын
Where do the split-complex and dual numbers fit into this scheme?
@jamesrivettcarnac7 күн бұрын
Hell yes i want the split complex, and quaternions
@oblivion5683 Жыл бұрын
That diagram at the end looked a lot like the fano plane?? Is there some connection between these algebras and projective geometry???
@henrikljungstrand203610 ай бұрын
Yes. There is a relationship between these algebras and projective spacea over the field GF(2) = Z/2Z. This is because every generator unit squares to a scalar.
@dougdirac2 ай бұрын
Where did this multiplication rule come from? Is there some kind of analogy in vector or matrix multiplication?
@wilderuhl3450 Жыл бұрын
Yes please
@jean-baptistelemen3681 Жыл бұрын
I don't know if it's a relevant question but : I understand that the octonions can be seen as an algebra with a construction process that derives from the Fano plane. Is there a way to perceive what an equivalent way of constructing an algebra would lead to when starting from a non-desarguesian projective plane, e.g. the Hall plane or its dual ? Something like the equivalent of a skew field but it would be an algebra? I thought intuitively about a malcev algebra but have absolutely no clue how to prove it. And I forgot to tell, but of course thank you for the great quality of your online content. Helps amateurs such as me a lot!
@richardcasey4439 Жыл бұрын
This is fascinating.
@dcterr1 Жыл бұрын
So do we keep losing structure past the sedonians, or do all the ones after it have the same basic properties?
@arisweedler4703 Жыл бұрын
This felt like playing around with notation yielded a more general ways to describe a set of similar yet previously un unified systems. Like something Conway would do, with the transcendental numbers. It’s cool to see. Although I didn’t understand why it was fine to just assume that certain properties of the constructions held - like associativity or commutativity - without first proving them. That probably just made this video shorter and more engaging which I guess I can get behind :) …
@metamusic64 Жыл бұрын
For associativity and commutativity at least, I think the assumption of their holding in the reals is reasonable since that proof is probably a bit out of scope of the video. He proved commutativity in the complex numbers, and that's the last algebra where it holds. He did skip associativity in the complex, but I think the proof of that would look the same as the proof of it in the quaternions, which he did show
@michaelgolub2019 Жыл бұрын
It is interesting: are there possible systems with arbitrary number of imaginary units, say 5, 6, 7 and so on? If no then why? What are the applications of such hypercomplex systems? We know vast usage of real and complex numbers, using quaternions for 3D rotations, how other systems are used?
@kikivoorburg Жыл бұрын
The answer I find the most satisfying is from geometric algebra (though it’s far from rigorous): Basically, any time you introduce an element in a geometric algebra, you end up ‘generating’ other elements from the multiplication. Let’s try to construct an algebra with just a single “-1” squaring unit we’ll call “i”. Then we have: i^2 = -1 Which ‘generates’ the scalar values. So actually we can’t have a geometric algebra with only “i”, we need {1, i}. Let’s try another -1 squaring element “j”, giving {1, i, j}. Watch what happens: 1^2 = 1 i^2 = -1 j^2 = -1 ij = ? What does “ij” equal? Well, in geometric algebra, different basis elements anti-commute. Hence: ij = -ji This lets us figure out what it squares to: (ij)^2 = ij ij = -i jj i = ii = -1 So by introducing “j” we also ‘generate’ another -1 squaring element which we can label k. So we have {1, i, j, k} where ij = - ji = k and by extension ijk = (ij)^2 = -1. This is the definition of the Quaternions! Notice that we were able to have the 2D complex numbers and the 4D Quaternions, but not 3D-complex like numbers since it sort of “wants” to generate another element. Sadly the explanation doesn’t extend to Octonions since they’re non-associative and all geometric algebras are associative, but I find it a nice way to understand the case for Quaternions more intuitively at least
@henrikljungstrand20364 ай бұрын
There are other ways, but then you need to set not i² = s etc but rather i³ = s (i⁴ = s; i⁵ = s ...) etc, for a scalar s. Different scalars s may be used for i, j, l, while the scalars for ij, il, jl and (ij)l are calculated from these. Also, it is more natural to start with split complex, split quaternion and split octonion numbers (set scalars s to 1), then modify from scalar squares to scalar cubes etc. This will work better over rational numbers than over real numbers (avoid zero divisors). For complex analogs you just use abelian group theory. For quaternion analogs you use group theory. For octonion analogs you use Moufang loop theory. Also, when using units squaring to a scalar, it is natural to use anticommutativity, since this multiplies with the scalar -1, which is a square root of 1. When using units cubing to a scalar, it is natural to use a modified anticommutativity where we multiply with a *scalar* that is a primitive cube root of 1, say w. This would mean e.g. that if i³ = j³ = s for a scalar s, then ij = wji but ji = w²ij, since w and w² are reciprocals, because w³ = 1. Not sure how this would work out in the non-associative case, but probably something like (ij)l = wi(jl) might work. Most likely we can get complex look alikes of any dimension d, quaternion look alikes of dimensions d², and octonion look alikes of dimension d³. So we can go from dims 2, 4, 8 to dims 3, 9, 27, or dims 4, 16, 64, or dims 5, 25, 125 etc. We may need to multiply with another dimension for the scalars needed though, one less than the degree of the primitive root of 1.
@karlwaugh30 Жыл бұрын
Didn't expect a surprise Fano Plane at the end there... are there more shapes as we go to other sets???
@nL841wK68l Жыл бұрын
well done. really cool 😁
@noahwright4599 Жыл бұрын
Ok this is a wild question but could we use numbers of n dimension where n approaches infinity? Negative dimensions? Dimension approaching zero?
@MonsieurSeize Жыл бұрын
I didn't see yet the video but i just saw the last diagramm and i don't think that two arrows has to ends on e5 beacause it doesn't make the diagramm invariant under rotations. To be symmetrical, you have to reverse the arrow between e5 and e7.
@deltalima6703 Жыл бұрын
What sort of idiot gets the diagram that charts the system wrong?
@Frahamen Жыл бұрын
So wait I can start my own domain on squarespace? Is it an associative and commutative domain?
@musicarroll10 ай бұрын
Is there a Fano-like diagram for quaternions?
@DavenH Жыл бұрын
Are there any theorems like the convolution theorem that exclusively permit big algorithmic speedups (e.g. O(n^2) -> O(n log n) for multiplying large numbers, enabled by complex numbers and Fourier transform) using quaternions or octonions?
@pizza87252 ай бұрын
Do a video about voudons
@APaleDot Жыл бұрын
2:40 Michael is a time traveller!? It all makes sense now...
@rac1162 ай бұрын
at 30:00 YES I'll like a video about the Split Complex Numbers
@2kreskimatmy Жыл бұрын
why do dimensions of these algebras appear to be powers of 2?
@pyropulseIXXI Жыл бұрын
Why does the cross product 'only' work in three and seven dimensions?
@henrikljungstrand203610 ай бұрын
Because no higher C-D algebras than quaternions and octonions are composition algebras. Cross product works trivially in one and zero dimensions also.
@mat3271 Жыл бұрын
I like to see the complex system plus abut instead of moving forward of it just do the colpexer system of that system
@phrygianphreak44286 ай бұрын
Are there transfiniterneons?
@codatheseus5060 Жыл бұрын
The answer for the value of x when x²=-1 is any number on an infinite dimensional unit sphere in a complex plane
@jamesrivettcarnac7 күн бұрын
I finally understand quaternions.
@samueldeandrade85356 ай бұрын
"Sedonions" or "Sedenions"?
@growskull4 ай бұрын
sedenions is the correct name
@jeffreyhowarth7850 Жыл бұрын
Is quaternions as H the upper half plane?
@LegendLength Жыл бұрын
So the complex plane is really just an extension of the number line into 2d. And quaternions are the 4d version?
@AlbertTheGamer-gk7sn Жыл бұрын
There is also a real-imaginary-virtual number system that is 3D, with virtual numbers that have negative absolute values.
@LegendLength Жыл бұрын
@@AlbertTheGamer-gk7sn I always viewed negative numbers as a kind of hack. Like "let's just add one bit of data to numbers and see what happens". But it seems they are quite intrinsic to all of math. I guess i've changed my mind on how i feel about negatives now.
@eccentricorgan Жыл бұрын
WOW...just wow!
@stephaneg.8623 Жыл бұрын
Seems like the right place to ask this if anyone can enlighten me, since we've known for almost a century that the universe is quantized, and that there actually is a minimum size we can operate in (plank length), doesn't that invalidate the idea of infinitesimally small numbers? When I was taught that number systems above the reals(long long ago 😂)...it was under the assumption that you can always find a number in between 2 fractions... Doesn't this assumption now seem wrong? Wouldn't this relegate all non-real number systems to just be in the realm of erroneous past ideas we should stop using?? Utterly confused.
@arnouth52606 ай бұрын
Not at all, it just means that certain numbers “exist” (we’ll ignore the discussion of whether numbers actually exist or not, it’s irrelevant and rather boring) which don’t appear in the real world. This isn’t shocking, after all there are numbers so vast they already can’t have any physical description. Quantum mechanics actually uses a ton of math that simply wouldn’t work without the assumption that between any two numbers there is another one (actually it requires slightly more than that to work, but that’s beside the point). Oh and a sidenote: infinitesimals are non-standard. Whilst it’s possible to develop them rigorously, the standard way of doing analysis doesn’t have them. The relevant search term would be non-standard analysis.
@joshuagenes Жыл бұрын
What's the advantage of using these algebras over Geometric Algebra?
@DmitryZvorygin Жыл бұрын
At 6:44 probably you meant "non-negative real numbers" instead of "non-negative integers"