AC Thevenin Equivalent Circuit Problem

[@nerdyowl3407]

Amazing tutorial. I am a 3rd year Electrical Engineering student. Thevenin Theorem is now a very easy and old thing for me. Your tutorial is very much clear to understand for beginners and the concept you are giving here is really important.

[@vxcci]

Chuch here!

[@theslackerengineer9351]

Dude you're back! I wanted to say I myself have wanted to be a Electrical engineer since I was 10 and am ecstatic I came across your videos on Amazon and saw your story on your website of struggling with math and working for NASA. Thank you for making videos .

[@MathAndScience]

+The Slacker Engineer You're very welcome. Thank you!

[@vtgaming9204]

+mathtutordvd I have the same dream. o.o I dream of working for nasa as an aerospace engineering or even an astronaught, but i never finished school. After years of time off, i turned 18 and did a diploma and went to uni, struggling with maths but i'm getting through it thanks to your videos.

[@theslackerengineer9351]

VT Gaming You just gotta work your ass off for it. Engineering Truth is a good channel for career advice and tips like that

[@Anonymous1995]

Started a new computing internals course last week, and the first day of class the professor assigned homework on circuits. 95% of the class (including me) had never even heard of a circuit because it's not a prerequisite for the course, so we were completely lost. What a coincidence you just uploaded a lesson on circuits hahaha.

[@wongtszpong]

Thank you so much. i always feel that i am hard to understand how to calculate. Your clear explanation helps me a lot. I have watched a lot of videos about the sample topic but no one like you can help me to learn one thing so clear. Also, I am not a English native speaker, but your accent is easy to understand without any subtitle. Thanks a lot again.

[@LoxBeats]

I totally aced my test thanks to this insanely helpful video! thank you so much Sir!

[@Wonllyyuu]

I am so loving your videos sir. You're such a blessing. Thank you very much.

[@AsBi1]

I love your videos.. they are so much helpful not only did I learn complex numbers but also much more about my TI 89 calculator which i never had thought could be so useful.

[@MA-qz1sd]

Your a good teacher I really appreciate your work.

[@shubhamshukla9179]

Wow !! Explained in the easiest possible way

[@DaiR0kuten]

Thank you so much! I really like how you made it so easy to understand it.

[@samikkarmakar9959]

I am an indian.....but thnx

[@mausefue]

Great video, easy to follow and very helpful. Thank you

[@nabiloov5637]

Thank you so much ,, i have an exam in two days about this ,,

Thank you my teacher

[@MathAndScience]

+‫محمود اليعرب‬‎ welcome!

[@HereIM27]

Very clear. Very clean. Very coherent. Thank you so so much !

[@nazanwar6469]

Mate thanks a lot your explanations are the best

[@MMS_0707]

👏👏👏 you are really an engineer

[@madisonh5459]

This is so helpful! Thank you!

[@nehadevadiga1094]

Sir please explain this type of problem using Casio FX 82 ms

[@piro9384]

this is a good video, play on 2x even better

[@ultralaggerREV1]

Do you have a tutorial that shows the mutual inductance? Like, you got an inductor of j20 ohms and a mutual inductance of j5 ohms and then find thevenin circuit

[@natehagen9710]

I like this channel

[@tixchicken]

Are you a baldwin brother per chance?

[@Prepaidgeecko]

You're the man

[@waseemsiddiqui8959]

your many lectures are only 4 minutes. plz upload the full lectures on dc circuits.

[@HamidCreation07]

Bihar se kaun aaya hai yaha attandance please 😂

[@delusionalbobby]

pakcik lu memang style

[@keithmckeown7286]

still no idea how you managed to get 6-j2

[@oraoraoraoraora6959]

just use calculator it will solve for ya

[@valest9290]

@@oraoraoraoraora6959 But its fucked up anyway...

[@shanjeeta5379]

THANK YOU :)

[@joseparedes3765]

Thanks brother

[@leberonjeeyms267]

Do a nortons of this bro please

[@kennethvenzonmusic_]

How did you get Zab= 3.6+j10.8 ohms?

[@enriqueespinoza5467]

For future reference because I was confused too: multiply the top so the top becomes 432j and then multiply the fraction by the complex conjugate and simplify

[@PasanJayaweeraYashoda]

thank you sooooo much!!!!!

[@bass9454]

i love you !!!

[@seunanekhosiking3627]

Am I right if I call the short circuit current... Norton current??

[@alpha-rh4dr]

thank u sir....

[@jomz3721]

Z= 18/5 + 54/5 i How you got Z= 6 - 2i ?

[@noahlape8187]

Is current across the short in method 2, Norton's current?

[@malharkhairnar485]

Why you are using polar and rectangular form?

[@قناةطاقة]

I think that you found the drop voltage on the R=36 and this is not the voltage between a and b 5:28

[@charefeddine2199]

it is the same because its parallel with a and b

[@graysonschiller3288]

Lost you at 4min when you said to do the math to getI= 6-j2. Any chance you have any videos going into how you got there?

[@graysonschiller3288]

or at least explain what you mean by putting in the calc polar and rectangular numbers

[@MathAndScience]

Hi, I think you need to review complex numbers and how to work with them. There are 2 ways to represent a complex number. Rectangular form and polar form. You need to be able to work with both by hand and in the calculator. Please search my channel for that as I have lessons on these topics. Good luck! Jason

[@user-uz8od7ir3b]

Can u explain star and delta in ac

[@paparazzymedia]

God bless the camera person

[@binodtharu8348]

nice

[@zerohooman4403]

240 V is Vpeak or Vrms?

[@samikkarmakar9959]

Yeahh

[@vedantjoshi1487]

how did you get 6-2j..?

[@manslayerpupil]

It was the division of 240 phasor 0 deg divided by 36+j12. At first glance, they cannot be divided by each other because they are in different, non-compatible notations. If you convert 240 phasor 0 deg to a complex number, it is just 240+j0, or simply 240 since the imaginary part is zero. Now that the numerator and the denominator are both complex numbers, you can divide them with no issue, which equals 6-j2.

[@abdullazarrar1910]

but then how do u get j12?

[@nn11412]

You can change the numerator into complex numbers, then multiply both the numerator and denominator by the denominator conjugate, keep in mind that j^2 is equal to -1, hence you'll get 6-2j.

[@arunmalik790]

those problem are two board long and it will take too long!!!

[@Samy697]

are you om facebook? Is there any way we can chat ?

[@mattgamer999]

1:48 did he say "All of these in penises"?

[@Jo3yL]

"All of these impedances"

[@MathAndScience]

Lol, but no. "Impedances"....its like resistance but applies to AC circuits.

[@nikhilanand984]

Tumse na ho paaega

[@redaalasadyss248]

أستاذ ممكن تتكلم عربي

[@mahmoudalawasheer9220]

Thank you my teacher

[@samihaelahi3138]

How did you get 6-j2?