The fact that the woman is able to write upside down without any problem...
@adityasharma23802 жыл бұрын
The nervous laughter cracks me up every time 😂😂
@sitrakaforler8696 Жыл бұрын
Imagine the stress of the camera AND the interview combined. Co ngrat to that girl !
@fyradur3 жыл бұрын
sin(x)=x -> f(x) = 1 foralll x. Congratulations you are now an employed engineer.
@dcmk46833 жыл бұрын
the fuks the fbi doing here
@dcmk46833 жыл бұрын
quick burn the hard drive
@NitroniumGaming3 жыл бұрын
haha. Other ways to become employed as an engineer is to note that 3^2=pi^2=g=10
@stormtrooperfun25252 жыл бұрын
@@NitroniumGaming Or even better: ∫cos(x)dx from 0 to π/2 cos(x)=1 therefore we have ∫xdx from 0 to π/2 Fundamental Theorem of Calculus: (π/2) - 0 = π/2 Consider: π=e and e=2 2/2 = 1
@avesta53903 жыл бұрын
My interview is this Wednesday at 5:15pm... can’t wait but also so nervous!
@ngocanhdoan48353 жыл бұрын
mine is on 12pm on wed as well!
@defene49663 жыл бұрын
@@ngocanhdoan4835 Mines wednesday too!
@katiegardiner48403 жыл бұрын
hope it went well!!
@zanerobison29563 жыл бұрын
how’d it go?
@SilvioPorto3 жыл бұрын
tell us how it went!
@pinklady71843 жыл бұрын
If I ever see question like this, I would make graph of the equation and see what that looks like.
@Treviscoe3 жыл бұрын
Sure, but that's a tricky equation to draw a graph of (which is why it's a question for a place at Cambridge), because of what happens at x=0.
@samuel087902 жыл бұрын
@@Treviscoe graph is discontinued at x=0
@bawseeeee6022 жыл бұрын
@@samuel08790 No it is 1.
@sahydes2 жыл бұрын
@@bawseeeee602 no, the function approaches 1 around x=0, but it's undefined at x=0
@prayogaliong53952 жыл бұрын
@@Rokkc you're not allowed to use lhopital for sinx/x, its a mathematical definition
@Craloye5 ай бұрын
Mathematics is the Art of Simplification.
@loneranger42822 жыл бұрын
No way the Math one is that easy. I'm 95% sure that they put an easier one for video purposes.
@RazorFistMusicOuttaTheWorld2 жыл бұрын
definitely. mine was way harder
@loneranger42822 жыл бұрын
@@RazorFistMusicOuttaTheWorld What was your question that they gave you?
@austenlamacraft2 жыл бұрын
This isn't an interview for maths, but for natural sciences. Maths questions would surely be harder
@bishy2007 Жыл бұрын
and interview for a maths undergraduate course will have harder questions, this is most likely for natural sciences, computer science, etc.
@alish29509 ай бұрын
How would you approach drawing that? How would you know the Y value when X tends to zero? You knew l'hopitals rule at age 17?
@blaze73453 жыл бұрын
i would walk straight out of the interview
@kevinbyrd4441 Жыл бұрын
Lol
@afrinahmed16203 жыл бұрын
Awesome criteria to look for😊😇
@mrpeanutbutter60943 жыл бұрын
Me: get up from the seat and exit thru the door
@tha52899 ай бұрын
very easy math shown in that video!
@MrPabloguida9 ай бұрын
Be more like you. Wow!
@chrisc4753 жыл бұрын
🎶🎵 Dr Keeler, he makes me happy. Dr Keeler in the morning Dr Keeler when it's closing time 🎶🎵
@kenichimori85333 жыл бұрын
p = np 7 problem solution 777
@h4z4rd283 жыл бұрын
Divide p on both sides and n=1 ez where is my million bucks
@farazriyaz90783 жыл бұрын
@@h4z4rd28 What if p=0 though?
@h4z4rd283 жыл бұрын
@@farazriyaz9078 bruh man you dont know that p stands for prime?😂
@farazriyaz90783 жыл бұрын
@@h4z4rd28 Well, does it? P stands for Polynomial Time, and I don't think that has anything to do with primes. Correct me if I'm wrong haha
@h4z4rd283 жыл бұрын
@@farazriyaz9078 P also stands for the set of all polynomials over some field but yeah, in this case its prime in my opinion. And btw i still didnt get my fields medal idk whats wrong with them
@smalmarufbillah_yt6 ай бұрын
Want to short vedio clips on Mathematics. Thanks.
@afrinahmed16203 жыл бұрын
sin0/0 will be a problem and so the function becomes undefined there and as a result you cannot draw the graph of undefined unless you are Ramanujan(the man who knew infinity) Just joking😂Love from India💝👍
@nonamesleft96993 жыл бұрын
Lhopitals rule?
@afrinahmed16203 жыл бұрын
@@nonamesleft9699Nice Bro😀😅 But only when lim x tends to zero. Here it is exact zero. There is no limit introduced here. Only the graph of the function is demanded.
@takyc78833 жыл бұрын
it is indertemined there but limx->0 is 1
@bigshrekhorner3 жыл бұрын
Uhh, you can perfectly draw the graph of this function. The fact it is undefined at 0 doesn't mean it's undrawable. If that was the case, 1/x would be undrawable too, because it's undefined at 0 When you want to see how a graph will behave when reaching a point at which it is undefined, you check the side limits (knowing the existence of the limit as a whole isn't necessary for drawing a graph). In this case, the lim of sinx/x when x is tending to 0 is 1, from both sides (you can check it using De L'Hospital rules) so what you do is make the graph so as to go close to 1 when x is approaching 0 and put a white circle on the point (0,1). Also, graphs of the type sinx*f(x) where f(x) is a polynomial, a logarithm, an exponential and prolly other shorts of functions, have the "property" that the sinx function is essentially deformed so as to match some of its points to those of the original f(x) and -f(x), thus making it easier to draw Edit: did a mistake with calculating the limit, it tends to 1 Edit 2: Influenced by the original sinx function, I initially said that the local maxima and minima of an f(x)*sinx are matched to points of f(x) and -f(x). Those points aren't necessarily local minima or maxima. Edit 3: just a heads up; when it comes to sinx/x, note that using De L' Hospital rules isn't considered a proper way to prove that lim(sinx/x) = 1 when x tends to 0. It's more of a way to confirm that.
@afrinahmed16203 жыл бұрын
@@bigshrekhorner Exactly sir, the behaviour of the graph will hint us that we need to put a white circle there but this also means that at x=0 we are not allowed to draw. That is what I said we can draw the graph but not at x=0 directly.
@rohithsudarshan65244 жыл бұрын
It’s very difficult to do math on the computer, how is that going to be solecrd?
@MathematicsatCambridge4 жыл бұрын
Hi Rohith, I'm not sure what you meant when you typed 'solecrd'. If you want to see an example of how an interview will be conducted online this year, watch this: kzbin.info/www/bejne/i6KvZpSIpbKEe5Y. Whilst the physical set-up will be different, the content of the interview, and how Colleges assess candidates’ knowledge and potential will be the same as it is for in-person interviews. There is more helpful advice at www.undergraduate.study.cam.ac.uk/applying/interviews/online-interviews
@cloroxbleach75543 жыл бұрын
@@MathematicsatCambridge I think he meant 'scored'.
@MidnightStorm49903 жыл бұрын
@@cloroxbleach7554 Bruh that's the worst typo ever
@takyc78833 жыл бұрын
how would you actually solve these kind of plot the nature of the graph questions?
@alastairritchie6925 Жыл бұрын
You would determine if there's any symmetry, see where the graph crosses the x and y axis (if it does cross). Find stationary points and their nature, find points of inflexion, find asymptotes and see how the value of the function changes as you approach said asymptote, and see how the graph behaves as x approaches infinity in the positive/negative directions.
@anmoljhamb87753 жыл бұрын
Am I the only one who thought that the question was a bit easy? Like not that difficult. I am also a highschool student, and I had never seen this question before. How I proceeded was, first noticing the fact that the function is an even function, meaning it is symmetric about the y axis, and we don't need to draw from -2pi to 2pi, we just need to draw from 0 to 2pi, and for -2pi to 0, would be a simple mirror image. Next, I found the points of discontinuity, that being, x=0, we just find the lim sinx/x as x approaches 0, which we know is just 1, now the next fact, we know that sinx
@adrianwongso37843 жыл бұрын
well for people that is capable in math the question will be considered easy, its not for the average student though. Also the point of this interview question is just to show how you think its never meant to be hard (to compensate for that Cambridge has the STEP examination) :) .
@anmoljhamb87753 жыл бұрын
@@adrianwongso3784 oh!! I didn't know about the examination! Thanks!!
@markusklyver62772 жыл бұрын
Yes, but this interview is probably for a BSc and not for a MSc.
@earendilthebright54022 жыл бұрын
I'm pretty sure this is not the full depth of mathematical questioning being asked lol
@英語で学ぶ会計入門5 ай бұрын
Why do they have interviews? Is is so they can let in the people they want? Seems especially dodgy in the area of maths because a) the exams are pretty objective and b) you could be very good at maths but not across well in an interview.
@irwinsaltzman9793 жыл бұрын
Sorry but sin(x)/x is a very common question in calculus 1
@babajani35693 жыл бұрын
Yes but plz correct me if I am wrong. This is for high school students and from I know, calculus 1 is done at college.
@irwinsaltzman9793 жыл бұрын
True calculus is a college course. Many high schoolers do take calculus as seniors.
@babajani35693 жыл бұрын
@@irwinsaltzman979 thanks for the info. Also, can you plz let in on what you mean by that (senior). I live in england so am not really familiar with the american education system but I am quite interested tho.
@irwinsaltzman9793 жыл бұрын
Final year of high school in US the students are classified as seniors.
@babajani35693 жыл бұрын
@@irwinsaltzman979 ok thx. Also if you dont mind, cab you plz send s link yo the syllubus for everything that is covered in high school. I am quite intrigued. Thank you
@accideux51823 жыл бұрын
The question is too easy lol
@ComFinStory-uw4fi3 ай бұрын
Can anyone in his late 30s apply to study math at Cambridge or trinity
@jimbano48692 жыл бұрын
Cambridge interview chemistry
@tyssotteddy3167 Жыл бұрын
*This is soo easy. Is that a Masters question?*
@aditya39842 жыл бұрын
she hasnt seen sinx/x. is this undergrad interview or what
@BrokeBad Жыл бұрын
Everyone here is such a nerd you will probably not even get in lol
@spicyy8123 жыл бұрын
but sinx/x=1...
@afrinahmed16203 жыл бұрын
Put x=90 and your equation fails. Because then y=1/90
@spicyy8123 жыл бұрын
@@afrinahmed1620 its a meme.. dont take it seriously
@nischaysingh69523 жыл бұрын
The unit of x axis is radian not degrees
@afrinahmed16203 жыл бұрын
@@spicyy812 Exactly, I know😊😇
@afrinahmed16203 жыл бұрын
@Newtube Simple value putting will also do the same but yes the points will have to be carefully chosen and will take some time.
@jamesbedukodjograham55082 жыл бұрын
I am quite impervious to what women think about the Math Question. You know nervousness is actually the the first reason why I would fail the Cambridge Math interview. However hesitation is part of the Cambridge tutorial. In fact the School is obviously beyond the reach of those of us who went to State and Religious Schools.
@benatronbtang6877 Жыл бұрын
over half of the people who study at cambridge went to non private schools
@jamesbedukodjograham5508 Жыл бұрын
@@benatronbtang6877 A policy since year 2000
@dac89392 жыл бұрын
Seems far too basic. I was asked crazy stochastic calculus question. Even though most do not even study that until masters level, let alone degree. To be fair, they were not wanting an exact answer but just thought process.
@creamcheese35963 жыл бұрын
What utter bullshit this is. The interviewers only have to check if the candidate attended Eton or Harrow or Rugby and if so, they are in, regardless of their interview. But if the candidate was very bright but attended Smegma College in Worksop they'd have no chance.....
@maria64513 жыл бұрын
Not really true tho is it look at they admission stats
@funwithflags75063 жыл бұрын
Not true at all salty because you cant get in
@hungryhog13 жыл бұрын
What a load of nonsense. If you look at the stats most students are from state schools. My local state school sends 20 per year
@creamcheese35963 жыл бұрын
@@hungryhog1 The number your state school sends is irrelevant. How many get a place? Probably zero. Smegma College Worksop get zero also.
@pinemarten62413 жыл бұрын
How absolutely ridiculous. Admissions statistics repeatedly prove that Cambridge welcome all applicants, including those from disadvantaged backgrounds. You’d do best not to spread harmful misinformation like this