GIbbs Free Energy and Spontaneity

[@peterlauridsen8403]

Best teacher in the world

[@_BENG__]

World best teaching skill!

[@boutainayahia4986]

I am a medical student :D and although we study in French , i couldn't ignore the fact that your lectures are much more well explained . Thank you !

[@hahahaha4304]

Kffu

[@abbiejefferson6528]

This was SUCH a helpful video! Thank you!!!

[@wgdanmourad]

you cannot imagine how much these videos are helping me , thank you very muchhh

[@walaaabusada7130]

i study in jordan and your lectures are very good and useful ❤

[@Lucerozeus]

Thank you for your effort... this is awesome!

[@micro672]

Thank you soo much sir for explaining concepts incredibly well, we are still watching these videos and sharing to our friends because these are extremely helpful.

[@anash2520]

without your great explanations i was gonna get F in biochemistry :"')

[@raniabelkheir67]

Merci beaucoup ! thank you sir i've never understood it better 🤗

[@fikadunigusie6343]

You are brilliant Man ,any way thank you so much our sir🙏

[@peterlauridsen8403]

OMG you are saving my life

[@yasmineadel9956]

My success in biochemistry in college really because of you thanks so much waiting always for more Andrey

[@imagineabout4153]

i think you just changed my life... thank you

[@mgmartin51]

Colonel Jessup: Are we clear? Lieutenant Coffey: Crystal.

[@alvinjesus100]

awesome explanation....great job done

[@sailormoontsuki]

Thank you for the great explanation

[@AKLECTURES]

sailormoontsuki you're welcome! :)

[@kulvirsingh819]

bravo

[@josephboakyeomane4400]

i love your channel.........too much

[@ds.6974]

Where does the 2.303 come from? Its not in my textbook

[@mariatury9553]

I think it's from using log instead of ln?

[@KalKiKhabarAaj]

yep think so

[@donnystellar1885]

I’m studying AHE in science. If I don’t understand any of this, would it be safe to think that I am probably on the wrong course ?

[@lindsaymason8427]

Where does the 2.303 come from?

[@ds.6974]

Did you get an answer to this?

[@KalKiKhabarAaj]

The number 2.303 is used for the conversion between natural logarithms and common logarithms. Natural logs are based on the number base "e" which has a value of 2.71828. Common logs are based upon a base 10. So, you can convert from natural logs to common logs by multiplying 2.303xlogN = ln N. For example 2.303xlog 9 = 2.197; ln 9 = 2.197 he converted from lnKeq to logKeq. The factor of 2.303 allows him to make this conversion without changing the value of the equation

[@kennethyadhielbracerorios7973]

Goat

[@dhooy7150]

Do you have any videos on metal-ion catalysis, covalent bonds formed, and etc?

[@AhaanIshan1720]

Thank you so much sir

[@Broccoli821]

But Delta G naught does not describe the spontaneity of a reaction.. according to my textbook. Never mind lol

[@Jfresh55]

Please, can anyone help me? Illustrate an organic contaminant (e.g. benzene) plume that is entering a previously uncontaminated aquifer from a point source (e.g. a leaking underground storage tank), and show the predominant terminal electron accepting processes that you would expect to be occurring at different regions of that contaminant plume. “Defend” this by determining the thermodynamic favorability of these different terminal electron accepting processes, assuming the potential terminal electron accepting processes would be aerobic respiration (O2reduction), Mn(IV) (pyrolusite) reduction(to Mn2+), Fe(III) (ferrihydrite) reduction(to Fe2+),sulfate reduction(so sulfide), and methanogenesis.Before calculating the energetic favorability of these processes, produce balanced reactions depicting these terminal electron accepting processes based on H2as the electron donor (be sure to normalize all reactions on the basis of one mole of H2). Explain how the thermodynamic favorability of the different terminal electron accepting processes.A table that includes ∆G0frelated to this question is provided at the end of the exam.Why might it be “scientifically defensible” to use H2 for these calculations, and not benzene. Chemical Species include: Mn(2+) MnO2 H2 H(+) H20 S(0)=elemental sulfur HS(-) SO4(2-) Fe(OH)3 Fe(2+) CO2 CH4 O2 ∆G•f (correlates to the chemical species) -228 kJ/mol -457 kJ/mol 0KJ/Mol -40kJ/mol (@ pH 7) -237 kJ/mol 0 +12KJ/Mol -744Kj/Mol -692Kj/Mol -83KJ/Mol -397KJ/Mol -34KJ/Mol 16.4KJ/Mol Please, I know it is long, but if anyone can help with this, it would help me out a lot.