Algebra Challenge

Рет қаралды 9,563

Prime Newtons

6 ай бұрын

In this video I solved an algebra equation of cube root terms.

Пікірлер: 41

@joevostoch8768 6 ай бұрын

I never rely on Pascal's triangle or any other memorized shortcut. I always do the algebra out in long hand. I find it more informative and quite relaxing as well. I believe that the joy of mathematics doesn't come from getting a quick answer but rather in knowing and logically following all of the rules for the type(s) of math objects you are working with. The beauty of solving any math problem is producing a logical workflow that can be read as a rigorous proof by anyone, not an exercise for the reader to figure out on their own. My two cents worth.

@klevisa.b 6 ай бұрын

I mean I don’t agree, but good to know your opinion

@AlexCranston-rb1wi Ай бұрын

How is it more informative to not use pascals triangle? It literally is the fundamental underlying structure behind binomial expansion to any degree and it is literally key to approximating roots, etc. I understand that it feels more rewarding to expand correctly and it does help with algebraic multiplication for higher degrees. But i feel that skill is best developed through just general mathsmatical practice. Just my take anyway, if you feel it helps you best go ahead. im just really curious.

@warbraid 6 ай бұрын

You're a fantastic math communicator.

@notsublo 6 ай бұрын

Beautiful, detailed, and clear explanation! And, I must say, beautiful handwriting. Keep up good work!

@awierdo69 6 ай бұрын

Totally loved your way, Another way - We know if x+y+z=0 then X^3+ y^3 +z^3= 3xyz (it is what it is, search) Now from the first equation that's the sum of cuberoots pf x ,y and z= 0 We can substitute in second equation that is (x+y+z)^3= 3yz As (3 multiplied by cube root of x, y and z) ^3 = 3yz Now 27xyz= 3yz And x=1/9 And the others solution as you did But in the solution I gave you just know a simple formula and apply it which saves time but does not develop approach.

@RahulSharma-te3yc 6 ай бұрын

I really enjoyed this problem...... thank you for providing this..... great work ❤❤❤ Love from India ❤❤❤

@georgesbv1 6 ай бұрын

actually last case is already covered.

@glorrin 6 ай бұрын

Very small mistake at the end, on 3rd part of the board x =1/9 (x,y != 0) should be (y,z != 0) Nothing major very good video :)

@PrimeNewtons 6 ай бұрын

Thank yoy!

@PrimeNewtons 6 ай бұрын

My brain took a break there 🙃 😪

@glorrin 6 ай бұрын

@@PrimeNewtons Don't worry it happens to every one

@97Bhai__gaming 6 ай бұрын

@@PrimeNewtonsbrother where are you from

@setoko3189 5 ай бұрын

@@PrimeNewtons Since you didn't you give more information about X,Y and Z , I immediately said that they're all equal to zero😅

@Alex4ndreSoares 6 ай бұрын

great work man! love from Brazil

@BLUETHUNDERMATH 6 ай бұрын

A very beautifull solution! Your videos are asome! Greetings from Paraguay

@klevisa.b 6 ай бұрын

I don’t remember when I subscribed to you (probably when I was in school) but I very happy I still am. This was very relaxing and more productive than doom scrolling

@PrimeNewtons 6 ай бұрын

Glad you are still here.

@BBBey 6 ай бұрын

At first, I had the same thought process you did to get to x=1/9, but I made much more work for myself than was necessary by missing some substitutions that are so blatantly obvious in hindsight; and now I have a headache. That was fun. Lol

@h.d.5779 6 ай бұрын

Otro excelente video

@lukaskamin755 Ай бұрын

BTW I noticed, that the 4th option is actually a common particular case of 2 above. they state if y or z =0, them x = - (another letter), but if it's also 0, than equal to -0 = 0 LoL

@user-yd4ky5vb3w 6 ай бұрын

Thanks for an other video master

@skwbusaidi 23 күн бұрын

The last codition is not required because from the second and third condition, we can get x=0 if y=z=0

@keithrobinson2941 6 ай бұрын

An excellent problem and solution. I am having visions of an xyz-coordinate system with a yz-plane at x=1/9, crisscrossed by two lines passing through the origin. No, that's not correct, is it? To be explicit: When x=1/9, don't we still have to solve for y and z? (Okay, I guess the problem didn't ask for that.) Even more impressive is that you got through the entire lesson with once saying, "zed"!

@PrimeNewtons 6 ай бұрын

Did I really say 'zed'? 🤣🤣🤣🤣

@97Bhai__gaming 6 ай бұрын

Yes brother

@anglaismoyen 6 ай бұрын

@@PrimeNewtonsZed is correct. Don't let the Americans influence you. Everyone else says zed.

@BukhalovAV 6 ай бұрын

But cubic root is not the same thing as 1/3 power. In cubic root the argument can be any real number, even negative, but if we use power notation, the argument must be positive.