Supernode Analysis Explained (with Examples)

[@pigfaced9985]

INCREDIBLY helpful since my teacher decided that not caring at all is an option. Thanks a lot!

[@dpenterprise8015]

Very well explained, you say in minutes what my teacher takes the whole class to do

[@slinky9512]

There are only 2 weeks left to me and this vid really helps me study suprenode problems. Thank you very much.

[@hrez4367]

@harley quinn I have 3 hours, I wish I had a good enough work ethic to be stressed about having 2 weeks to study lol

[@kirubelasrat6759]

thank you very much , this will help me with my exam

[@giovannivielma2909]

I don't ever comment but thought your video was good enough to say so Thanks

[@yash2786]

Are you from Australia

[@tanuaishwarya4362]

Liked???? Nahh... Loved the ease of explaining 👍👍

[@soul2197]

Which branch and sem

[@quicknaturalbeauty]

Sir💙💫 For supernode we offed all other circuit except supernode. 💯🤗

[@kartikijadhav7310]

Very well explained!!!!!!

[@reubengoh8056]

Thank you very much. Awesome and clear explanation, I can understand school now

[@gimmedaloot754]

Thank you for your clear explanation. Good job. Been out of school for a while now and am studying for my EIT. This was sooooo very helpful. Thanks again.

[@ALLABOUTELECTRONICS]

I am glad that it helped you. Good luck.

[@hrez4367]

Super helpful, thank you!

[@abadyelhertany8604]

the best video out there

[@KhaiNguyen-ez5mp]

Thank you, the video is very informative and well explained

[@ccantieny88]

when solving for node 2 - it should be (v2 -v1)/5. I put this into the simulator LTspice and it checks out that way.

[@deepthi4238]

Simple and perfect explanation....Thanks...Keep it up

[@mohammadyousef6374]

thanks bro , really likes the video. in future please do algebraic more clearly and try not to skip it . thanks bro

[@kushagrakrishnaagrawal4497]

Thanks a lot for these videos!! This will definitely help me a lot in my exams

[@mahendrailla-o8u]

Excellent brother ur videos

[@GD-mm9ou]

i have a doubt.. 6:45 the 2 ampere current should be in minus at last ...am i correct??please reply

[@dddhhj8709]

I thank you for all the videos 👏👏

[@minazulkhan8287]

how u have decided sign of current ( minus 1 amp ) in second example equation 1 ...similarly in eq 3 sign of 2 amp

[@soul2197]

Awesome channel

[@dhairyaverma3933]

this explanation is too good

[@pragnyas7604]

Thanks!

[@Sk-ew7cn]

खूब सुन्दर 🤗

[@mayurshah9131]

excellent, nice presentation

[@notzuhriashraaf4912]

Thank you for teaching me😄

[@mohammadibegum4704]

at 4:19....u took ( -3) but it should be +3 as u told in ur previous video, current entering a node is considered as positive ?

[@ALLABOUTELECTRONICS]

You can follow the convention you are comfortable with it. If you consider the current entering the node as positive and the current leaving the node as negative, then also you will get the same equation. I hope it will clear your doubt.

[@kneha9510]

Thanks a lot

[@sanojshrestha3533]

Thank you great explanation

[@sudeepsaha452]

Good. Informative.thanks.

[@bikashmohapatra7791]

Nice explanation

[@parameswararao6030]

I BECAME UR FAN

[@the_petite_higi]

2:09 for node 2 it should be v2-v1

[@pawantej7432]

Right

[@fahimhasan6832]

That was great... Thanks a lot..😍

[@parameswararao6030]

A VERY NICE VIDEO SIR

[@tarangghetia7235]

Can you please follow passive convention!

[@PetakyahBuckley-ht5iz]

Every thing before 2:15. Where are you getting the number 5 from? Where are you getting 2 from and where are you getting 1 from. I noticed your dividing the nodes. But I don’t get where the denominators are from. Please tell me. 🙏

[@ALLABOUTELECTRONICS]

All are resistances. The 1 ohm, 2 ohm, and 5 ohm. Basically, we have applied the KCL at the node. And for every current, we have used the Ohm law. (I = V / R). I hope, it will clear your doubt.

[@poornachandra_Ec]

please explain in detail of super node

[@diptishah3232]

well Explained..

[@complex_variation]

2:56 starts

[@rijohnkpius3687]

Sir what if a resistor is connected in series with the voltage source between nodes.is that a supernode case??if not how to solve such a problem.??sir,could u pls make a video on that.

[@anikbhowmick1044]

thank you

[@dawarking5443]

1st example me V2-V1/5= V2+2 Aayega na sir na ki V1-V2/5=V2+2

[@ALLABOUTELECTRONICS]

Would you please mention the timestamp where you are referring?

[@hariprabhakar6112]

sir I have one doubt in example 2 of supernode analysis in that circuit upper we have 1A current supply we dont take that in solving........ for what we dont take that in our prblm.... i have another dout sir in nodal analysi example 2 when we want current i 1 we have that i1=va-v1/r1 appadi than a potu kandu pidikanum neenga v1/r appadi solve pandringa athu crt method aaaaaaa

[@jeffsam5495]

current entering the v1 junction must be 3A at 5:28

[@ALLABOUTELECTRONICS]

What I meant to say is, the net current that is entering into supernode is 2A, (3A - I1) and the net current that is leaving out of the supernode is 2A. I hope it will clear your doubt.

[@pradeepsharma4905]

you are trying to say that out of 3 amp, 1amp is going to i1 and 2amp is going to supernode branch am I right sir?

[@ALLABOUTELECTRONICS]

Yes, you are right Pradeep.

[@Jamboreeni]

Thanks bud 👊

[@suvrosawon4545]

Normally we took inward current to a node is positive, but why we took that as negative for a supernode??

[@ALLABOUTELECTRONICS]

It's just a sign convention. You can take according to your convenience. In either way, you will get the same result.

[@suvrosawon4545]

@@ALLABOUTELECTRONICS Thanks

[@sanjayganesamoorthy4251]

Bro put many vedios

[@electriacl8834]

thanks a lot !

[@bitanpramanik6672]

At 7:24mnt,at node 3 how the equation comes i2+2=1??

[@ALLABOUTELECTRONICS]

If you observe, the current i2 and 2A current source are entering the node, while 1A current source is leaving the node. So, simply applying KCL that equation can be obtained.

[@bitanpramanik6672]

@@ALLABOUTELECTRONICS thank you.

[@vishal2938]

Sir I'm having a doubt what should I do in case of super node is connected parallel across 2nd and 3rd node

[@ALLABOUTELECTRONICS]

Well it depends, how it is connected in the circuit. Sometimes, using source transformation, it is possible to simplify the circuit.

[@mayureshdhanawade7394]

Bro what to do if there's 3 such nodes what to do

[@ALLABOUTELECTRONICS]

It actually depends on how the circuit is connected. Some times in such case, it is easy to apply KCL. If there is any such circuit, message me the circuit on FB or Instagram. will take it as the next quiz on the channel.

[@mayureshdhanawade7394]

@@ALLABOUTELECTRONICS I have done the same please checkyour facebook

[@exceptionalchris]

One like, just for the accent

[@anikbhowmick1044]

than you

[@MrStarnger1]

the voltage source terminals should be opposite no? current enters through the negative terminal and leaves through the positive terminal right? that means that V2 has higher potential than V1 as current always flows from higher potential to lower potential? so it should be V2-V1 at 4:50 ?????? please clarify

[@ALLABOUTELECTRONICS]

The expression at 4:50 is written based on the polarity of the 2V voltage source. The '+' terminal of 2V source is connected towards V1, while ' - ' terminal is connected towards V2. That's why the difference between the positive and negative terminal is 2V. Hence we can say that the difference between V1 and V2 is 2V. That's why its V1- V2 = 2V. I hope it will clear your doubt.

[@muhammadazrirosli4387]

why for the equation 2 is v2-v1=3, and why not v1-v2=3 can some one explain to me, im a bit confuse

[@ALLABOUTELECTRONICS]

Just check the polarity of the voltage source. The positive terminal is on V2 side and the negative terminal is on V1 side. So, V2 is at higher potential than V1. And that's why V2- V1= 3V I hope it will clear your doubt.

[@ramshah7853]

If a resistor os also connected with votage source in case of supper node the how can solve these types of problem pls reply.

[@parameswararao6030]

SIR PLZ MAKE A VIDEO ON SUPER MESH ALSO

[@ALLABOUTELECTRONICS]

Yes, I will make it soon.

[@anuradha407]

At 6:42 why 2A current at v3 not considered while writting kcl equation

[@ALLABOUTELECTRONICS]

Because the KCL equation is written for the supernode. If the KCL equation is written at the node, where the voltage is V3, then it should have been considered. I hope it will clear your doubt.

[@Itsmesam99]

Did u use mouse for writing

[@hardiksingh4557]

was it necessary to solve for node 3 since we already know current in all three branches

[@ALLABOUTELECTRONICS]

It is required to find the value of V1, V2, and V3.

[@fake_guy-o8x]

what if there is resistor and voltage source between two node? is that a supernode case?

[@ALLABOUTELECTRONICS]

Using the source transformation, it can be converted into the current source in parallel with the resistor.

[@pradeepchandra7828]

awesome

[@durganshtaneja]

In the last example, what if there is another voltage source between v2 and v3 ?

[@ALLABOUTELECTRONICS]

Do you mean in series with 1-ohm resistor? or in parallel with 1-ohm resistor? If it is in series, then just use source transformation and convert voltage source in series with resistor into a current source in parallel with the resistor. If you are talking about connecting it in parallel with 1-ohm resistor then consider that voltage source with a parallel 1-ohm resistor as a supernode. And then you can solve it. I hope it will clear your doubt. And still, if you have any question then do let me know here.

[@mohammadamirqureshi9530]

What does the negatives potential shows in first example V2= -1v

[@ALLABOUTELECTRONICS]

The negative polarity of the voltage shows that the assumed polarity of the voltage is in fast reverse.

[@jitrajjana3447]

my dear sir what is the most important criteria to select a supernode otherwise it's little bit confusing that the super node that i choose is correct or wrong. kindly reply it sir.

[@ALLABOUTELECTRONICS]

If the given circuit is easy to solve using nodal analysis method and if you find the voltage source connected between the two nodes, then that node can be considered as a supernode. I hope it will clear your doubt. If you still have any confusion then do let me know here.

[@jitrajjana3447]

ALL ABOUT ELECTRONICS ; sir ''in case of rotationally symmetrical circuits the equivalent resistance of any two points of the circuit doesn't depends on the applied potential to the circuit" - am i wright sir ? if yes then why am getting different eq.resistances across the same two points of a rotationally symmetrical circuit by taking different applied potential using nodal plane method ? kindly reply sir.

[@ALLABOUTELECTRONICS]

It's hard to tell without looking at the circuit. kindly message me the circuit diagram on the facebook page of ALL ABOUT ELECTRONICS. I will let you know in 2-3 days.

[@jitrajjana3447]

ALL ABOUT ELECTRONICS , ok thanks sir. SIR, YOU ARE ONE OF THE GREATEST KZbin TEACHER OF ALL TIME.

[@palabandlababu5561]

What if resistance is connected in series to the voltage source in 3rd problem

[@ALLABOUTELECTRONICS]

Using the source transformation, it can be converted into the current source in parallel with resistor.

[@mokkalapradeepans6756]

Bro why u take the -3 in supernode problem,i mean you take negative when current was entering why????

[@ALLABOUTELECTRONICS]

It's just a sign convention. You can choose other way too. But you need to follow the same convention through out the analysis to get the final output.

[@mokkalapradeepans6756]

@@ALLABOUTELECTRONICS tq brother

[@vanireddy6739]

What if there is a resistor kept in series with the voltage source? Will it still be a supernode?

[@ALLABOUTELECTRONICS]

No, it will not be a supernode. But in that case, the combination of a voltage source in series with a resistor can be converted into current source using source transformation method.

[@vanireddy6739]

Sir instead of converting it by transformation,if there is a 4ohm resistor kept in series with a voltage of 2volts,the whole setup kept between node 1 and 2,At node 2,Cant we directly write it as (V2-V1-2volts)/4 ? Please reply sirrr

[@ALLABOUTELECTRONICS]

In that case, V2-V1 = 2V + (drop across 4 ohm resistor). And we don't know the current through 4-ohm resistor. So, it's better to use source transformation.

[@ghanshyamsoni3594]

Sir are you faculty in ADIT?

[@srinivas5226]

How can we calculate power delivered by that single voltage source

[@ALLABOUTELECTRONICS]

Just find the current supplied by that source. V*I will give the power delivered by the particular source.

[@srinivas5226]

@@ALLABOUTELECTRONICS thank yoy

[@durganshtaneja]

what if there is a current dependent current source between 2 nodes ?

[@ALLABOUTELECTRONICS]

If there is dependent current source between the two nodes, then simply use the nodal analysis method to solve the problem. There is no need to use super node in that case.

[@abadyelhertany8604]

in equation 3 why did we say V2 - V3 not V3 - v2 ?

[@abadyelhertany8604]

at 7:00

[@abadyelhertany8604]

can anybody help me?

[@krishanmurariratawa21]

what happens when a resistor in series with voltage source connected in supernode

[@ALLABOUTELECTRONICS]

The concept of a supernode is under the assumption that the voltage source which is connected between the two nodes is the ideal voltage source, that means it has zero series internal resistance. If the voltage source is not ideal and has series finite internal resistance then you can not apply supernode concept. So, if the circuit has series resistance with voltage source between the two nodes, then you can't apply supernode, except in the case where the value of series resistance in too small compared to the remaining resistors in the circuit. (e.g if series resistance is in few ohms, and other resistors are in kilo ohms. In such case, you can neglect series resistance and treat the source as an ideal source. I hope, it will clear your doubt.

[@anikbhowmick1044]

if a resistance is also present in the supernode. how can I do it ?

[@ALLABOUTELECTRONICS]

If resistance is also present with voltage source then you can apply the source transformation and convert the voltage source into the current source. And then the problem can be solved by simple nodal analysis instead of applying supernode. I hope it will clear your doubt.

[@shuaibkaleem6052]

how he replaced 5 ohm with 2v

[@enagla9566]

I didn't understand too

[@atahanaggunlu6017]

that another question

[@muttahirulislam6706]

He didn't mean they are equivalent or didn't replace it. He just showed what if a voltage source remains between two non-reference nodes by another example.

[@lakshyasethi9727]

i didnt understand supernode :(

[@charlesazevedo4849]

At 5:36 the top left current it is not 2A or is it? Isn't that 3A?

[@ALLABOUTELECTRONICS]

If I had drawn that 2A on the other side of the supernode, it would have been easy for you to visualize it. Means out of 3A current 1A current is flowing through a 2-ohm resistor (i1). And remaining 2A current is flowing through supernode. I hope it will clear your doubt.

[@mr.unique7689]

at 6:03 how i decide which node i take as reference ????? why i should not take node 3 as reference ???

[@ALLABOUTELECTRONICS]

Generally, the node which is at ground potential or the node with a maximum number of branches is taken as the reference node. There is no hard and fast rule. But when you take that node as the reference node, calculations will become easy.

[@thy7917]

why is it that I1 and I3 comes out but not coming in?

[@ALLABOUTELECTRONICS]

If current directions are not given in the circuit then you can assume any direction for the currents(either entering or leaving the node). If your assumed current directions are not correct then you will get negative values for those currents. For example, let's say current i1 is 1 A, which is going out of the node. If you assume that current direction as incoming current for that node, then when you solve it, you will get the value of current i1 as -1 A. so, actually, it doesn't matter which direction you choose, it will be taken care of when you write KCL equation at that particular node. I hope it will clear your doubt. And still, if you have any questions then do let me know here.

[@thy7917]

I didn't think it would apply for supernode, but it does! you have my thanks.

[@electriacl8834]

ac and dc motor and generator math !

[@mohammed05622]

in equation 2 u mixed up, it should be v1-v2

[@ALLABOUTELECTRONICS]

Do you mean to say at 7:08 ?? If so, then it would be V2- V1 only, please check the polarity of the voltage source. It would be V2- V1= 3

[@mohammed05622]

if you assume that the current flows out of the positive end of the V.source and assign the currents throughout the circuit accordingly, you would find that the assignment of v2-v1 contradicts the direction of the current. I belive that the question is faulty

[@umayalsairam6494]

Why -3A in super node first equatiin it entering cureent only know

[@ALLABOUTELECTRONICS]

It is a sign convention. You can take it according to your convenience. You can consider the current leaving the node as negative current and the current entering the node as a positive current, and still, you can get the same result.

[@MrAnperm]

How did you get 30? @1:42

[@ALLABOUTELECTRONICS]

Just take the LCM of (2,5). It will be 10. And the same is multiplied on the R.H.S (i.e with 3) I hope it will clear your doubt.

[@AR_BSME]

8.28 u cant math!!!!

[@RealMe-ju9hh]

Bhai ki ijjat badadi bancho

[@mirandoo300]

10q

[@uday_kiran]

Binod

[@karimkhan1312]

speak slowly - u r too fast -- i can not under stand u r fast speach

[@ALLABOUTELECTRONICS]

Hi, if you find it fast then please change the video playback speed and use 0.75 as video playback speed. It will help you.

[@jahinmahbub8237]

I hate your accent , but it was a good video.

[@kushagrakrishnaagrawal4497]

Thanks a lot for these videos!! This will definitely help me a lot in my exams

[@olaayman1900]

thank you

[@kushagrakrishnaagrawal4497]

Thanks a lot for these videos!! This will definitely help me a lot in my exams