Superposition Theorem Explained (with Examples)

[@ALLABOUTELECTRONICS]

Minor Correction at 11:50 ; It's 2*[〖√9+√25+√49]〗^2

[@karthiksukumaran85]

ALL ABOUT ELECTRONICS why is v1=-i1 in ex 3

[@HabiburRahman-ol2lu]

Sir..i think you shouldn't give every resistor 1π or same.if you not do this-it will help us to understand correctly which one, you are using.

[@animasgaming522]

@@utena8518 Lol 8 month later 😅😅😂 still thanks for telling because I was wondering the same but I figured it out and then came to comment section 😅

[@subhashpurushothaman3831]

Even I was about to comment the same thing sir....I like the way you explain things but pls consider this request of mine....pls give some other value other than 1 for resistors to understand the same much better.......and one more thing if am not wrong there is a mistake in your calculation sir, you can't separate things within square root with squares like that while calculating Pmax......reply me if am wrong....

[@kgamphulanga9315]

why did you remove R from the square root , i think this is mathematically incorrect

[@dd-iu6iy]

You make this video perfect. I realize that it is very hard to draw figures of resistance, battery,etc. And show slide line by line. Good work bro

[@umasrivastava4142]

“........And the circuit will look like this” Thank you sir.

[@sharminmonika8887]

Though you are so fast , your tutorials are really clear, educative,and informative.Thanks a lot.

[@paramjitkaur181]

Sir had we considered that ammeter is non ideal in first case. Otherwise those two resistors will be short circuited. Also in removing voltmeter the wire was connected. But while removing 1A source u didnt removed wire which will create short circuit

[@olaoluwaomopariola4867]

Great video, but I wish you would make your pointer brighter. I had to rewind like 4 times wondering which one ohm resistor you were talking about before I saw that there was actually a very small pointer moving to show what you were saying. So maybe make it bigger and a color like orange, so it's very easy to follow what you're explaining

[@aryantiwari986]

very nicely explained ....you did a great job by creating this video.....bcz of which i am able to comlete my syllabus quickly ,,,,you explanation is out of remarks....finally '''''GREAT JOB''''''

[@karimfaizy766]

bro do not avoid that people make on you critisim. this is your excellent point.

[@deepanshupandey5435]

this is nothing but a good video

[@tharii314]

3:23 I just heard something... Actually a sound effect I was looking for.

[@amaytiwatane6661]

Put one video of Tellegen's theorem

[@nikeshparajuli6345]

Appreciate the effort.Thanks a lot .

[@rajabhay6535]

Super way to make understand bro.. thanks a lot

[@abhaykewate__]

Hey we have same name

[@storyofmaldives]

It'll be a good idea to put subtitles

[@ut7111]

2:3 super thankyou sir

[@mastrammeena328]

All other independent sources would be replaced by internal impedance Quire useful - AC Sources with different frequencies Power can't be calculated by superposition - with exam 8:45 Min power max power By - Minimum and maximum current through load 13:48 - dependent source example

[@hruturajkedar1547]

Concept is cleared ,thank u☺️

[@swapnilsingh6899]

in ex3 for 1ohm resistance voltage diff. is v1 so it given or we have considered it as v1 due ti dependent source 4v1 and why v1 = -i1 it should be i1 only.

[@arizaftab4840]

Excellent 👍

[@protikhalder8750]

I couldn't understand how did u wrote the equation by applying KCL at v1" in the last problem in 2nd case

[@dolanagamukeshvabilisetty8958]

Super explanation

[@techgamer1333]

nice work I want more problem-solving circuits hopefully u will do that like this video

[@NikhilSingh-yk3gc]

Video helped me 👍👍

[@lcm-nx2zi]

Can anyone explain In 5:20, why the two 1ohm resistor can be consider as parallel but on the other hand in 5:49 the 1ohm R why is that in series with the 0.5ohm resistor

[@priyanshisomani9569]

Sir, in the last example, the potential across the 1ohm resistance is v1, this is given in the question?

[@dimitrisfotiou7280]

thank you rly your examples make me understand the theorem

[@techieboy1983]

I have a doubt in 3rd ques that how you decided direction of current source when you considered 2A as current source

[@ALLABOUTELECTRONICS]

2A current is entering the node. while the other two currents are leaving the node. That's why there is a negative sing before 2A current source in the equation. I hope it will clear your doubt.

[@techieboy1983]

@@ALLABOUTELECTRONICS thankyou 😄

[@LionKing-yf3gw]

why arent dependent sources switched off ?

[@cpavithra8880]

Sir,why you can replace with one ohm resistor in the case of considering current source alone

[@yashwardhansingh6677]

worth watching videos. what software do you use ?

[@sriranganayakulugadey202]

Best explanation ever seen

[@aakashharish9373]

Thank you so much 😊

[@rajendrashah7921]

Excellent very nice theory

[@animasgaming522]

This video cleared my doubts thanks sir keep uploading

[@nishanthsinceborn]

Bro.. Awesome awesome awesome..... Congrats.. It's very useful... Keeping doing😘😘😘🤗🤗🤗🤗🤗

[@harshsoni4414]

This is " Nothing But A " Comment

[@king-aviiisapk7788]

Kon re tu ?(

[@king-aviiisapk7788]

Kopargaon kr

[@dilipgowdaan4666]

Super easy sir Thanks so much

[@hehek1536]

at 5:30 how is the short circuit same as 2 sets of 2 parallel 1ohms? A set on the left is correct but how did the set on the bottom be there? I thought those two 1ohms would disappear since the circuit is shorted.

[@bruceramirez9474]

Excellent explanation

[@nemalasurya7623]

your way of explination very clear..thank you so much sir

[@muralimohanreddy1344]

Excellent explanation BROOOO......

[@lakshay0132]

Nothing but a ka taaau ,,, mstt samjhaya

[@jeetenderkakkar7570]

a 230V 50hz ac supply is connected to a resistance 2.5ohm coil of inductance 0.06h and capacitor of 6.8uF connected in series. calculate impedance of circuit current phase difference between voltage & current

[@shadowphotography2848]

Thank you!

[@nishkarshshukla2908]

a very good lecture

[@huzeyfaabdella1385]

at p=i2R you took common multiple of them out ok but you should have square 2 also because the square is for all the component which is radical of (square root of 25+49+9) the 2 my second question is how V1=-I1 can you answer it plz this question is nothing but a request

[@allipsasethi2927]

someone plz explain why in the 2nd ex in Pmin we took total current as (I3-I2-I1) ???

[@ALLABOUTELECTRONICS]

P min = I min^2 x R. So, to find minimum power, current should be minimum. (I3 - I2 - I1) is the minimum possible value of current. And hence, it will give minimum power.

[@allipsasethi2927]

@@ALLABOUTELECTRONICS thankyou but .. y is i3-i2-i1 the min. Current??

[@ALLABOUTELECTRONICS]

At 11:27, I1, I2 and I3 are calculated from the given power. So, for a given R, the (I3 - I2 - I1) will make the current minimum. Isn't it ??

[@allipsasethi2927]

@@ALLABOUTELECTRONICS thankyou sooooo much 🥺🥺 this was the 1st time .. my doubt cleared via utube 🙏🙏🙏

[@arafatrahman2186]

sir ...at the last example ..v1"-2 +v2/5=0 is written...but by sign convention V1 should be negetive ....I could not understand this point

[@ALLABOUTELECTRONICS]

At supernode, the KCL is applied. See, 2A current is going into the node. While other two currents (V1''/1ohm) and V2/5 ohm are going away from the node. So, if you consider the incoming current as negative and outgoing currents as positive then you will get the above equation. If you consider the sign convention other way around (Outgoing current as negative and incoming current as positive ) then also you will get the same equation. I hope it will clear your doubt.

[@satyamitguru]

Plz keep a video of reciprocity theorem

[@sambenkamel]

At 6:21 The current that is going through the .5 ohm resistance is .25 A so the current going through 1.5 ohm resistance is going to be .75 A which is not reasonable because the larger the resistance the lower the current which is not consistent in this example because the larger resistance is 1.5 ohm and it has the lower current which is reasonable and logical.

[@MinutesAcademy]

yesss.....bro its 1.75

[@akshayaramaswamy1954]

Super explanation, request from me is explain about remaining theorems like Norton's and reciprocity ,

[@ALLABOUTELECTRONICS]

Norton's Theorem I have already covered at the end in the Thevenin's Theorem video. You may check that video.

[@EsmeWootliff]

why at 7:50 is the current through the 1ohm resistor 0

[@ALLABOUTELECTRONICS]

In the Wheatstone bridge circuit, since the resistance of all the arms are same, the point A and B will be at the same potential. And that’s why no current will through 1ohm resistor at the centre.

[@santoryu8940]

Why is I1 negative? at V' = I1? is it because of the polarity of the resistor?

[@tayyab.hussain786]

What's the meaning of this "Short Circuit" that replaced V2

[@shivamkumarrai9687]

It means shorts (the) circuit

[@sjjayaswal7621]

Thanks for information 👍

[@drsudhabhutada3565]

Sir please let me know how to make such type of video. I really appreciate your videos

[@souravbarua9685]

all good.. please be more careful using nothing but nothing but all the time..

[@mvsivaram]

Sir, u r explains super, but u scrolling bottom explained literally they disturbing main contains (circuits) , so, please observe in u contains vedios.

[@ALLABOUTELECTRONICS]

I think you are talking about the subtitles. You can turn off the subtitles (CC) manually in the video settings.

[@arinzeewuzie]

Concept well understood, can i make transcription of this video?

[@ALLABOUTELECTRONICS]

In English it is already available. If you want to make transcription in any other language, you are most welcome. And that will be a great help.

[@sathyamoorthy8763]

Thank you so much bro 🔥🔥

[@moazelsawaf2000]

Thanks sir

[@kesiyajoseph5222]

awsum explanation!!!👍

[@govayadav6010]

Hello

[@michaelkwamedarke3741]

I have subscribed

[@Rakeshkumar-bp5ku]

How to know which sources is dependent??

[@umeshkumarpandey9222]

Diamond shaped sources are dependent while the circular ones are independent

[@judy-chan4536]

in the last example, how is V1' a voltage drop? the source is clearly flowing from low potential to high potential which is clearly a voltage lift. if your 1I1 is negative then your dependent voltage of 4V should be negative as well, but obviously it isn't since its experiencing a voltage lift lol.

[@tomholmez12]

hey, this video was uploaded on my 18th birthday!

[@psubramanyam6831]

How to take direction

[@ALLABOUTELECTRONICS]

Please watch the video on KVL for direction. kzbin.info/www/bejne/mp21gIekeceIgtE If you still have any doubt then let me know here.

[@akshaynandal6409]

Very good

[@sandhyasandhya2898]

super explanation sir thanku so much it is very useful to me

[@manashrisattigeri9992]

In 1st problem, why you took I2 is zero, plz explain it sir

[@FR0S7B1T3]

at 15:08 how is V1 = -i1? as according to the current direction of i1, it would be a voltage rise?

[@ALLABOUTELECTRONICS]

with the direction of the current (Clockwise), there should be a drop in voltage across the 1-ohm resistor. but it is rising. That means assumed voltage drop V1' has reverse polarity and that's why with the given polarity there will be a negative sign. I hope it will clear your doubt.

[@dwaipayansengupta334]

I perfectly understand the concept.Thank u sir

[@suthiraheenetimulla8123]

When considering only 10V voltage source, how did the voltage across the 1Ω resistor became (-V'1)?

[@ALLABOUTELECTRONICS]

Because the direction of current is assumed in a clockwise direction. i.e I1 is flowing in a clockwise direction. So, if you apply KVL, then V1' = (-I1)*(1 ohm)

[@Mere_Human]

Its help me, thanks sir

[@kasarammoulika796]

excellent explanation... I'm impressed...

[@saimudhiraj9192]

Hii

[@lakshay0132]

i suggest you to decrease the use of word 'nothing but a' ,,you are misusing it to irritate us ,,lol

[@engineer1136]

Lol

[@lakshay0132]

@@engineer1136 😂

[@satishroyal7933]

Sir ur videos r super but don't write on the screen sir we r unable to see the video

[@its_yantiw_15]

At 17:05 V2 - V" = 4V" hi kyu hua V"- V2 = 4V" kyu nhi hua.....?

[@ALLABOUTELECTRONICS]

It is simple KVL. Just apply KVL between V2 and v1''. In case, if you find it difficult, replace V2 and V1'' with voltage source ( with plus - minus sign). It will help you in visualising them.

[@tushardangayach5263]

Sir last question main supernode nahi lagega, please check this again.. Total current across 5 ohm will be 4/3

[@ALLABOUTELECTRONICS]

If you simply apply the loop equation in the outer loop then it won't require. ( I mean no need to apply the concept of supernode) but when it is solved using the nodal analysis method then there will be a supernode.

[@lakshyasethi9727]

in third example, why is V1'=-I1 and not +I1

[@pratikmutyalwar2613]

Sir electronics ki puri book dalo 11class of ssc

[@saikatshee6273]

What is the defference between superposition and thevinin theorem ?

[@ALLABOUTELECTRONICS]

The superposition is used for linear circuits. And to find the current or voltage across the particular element, only one source is considered at a time. The overall response (current or voltage across the element) is the summation of the individual response. The Thevenin's Theorem is used to find the equivalent circuit across the to terminals. Using it, any linear circuit can be replaced by the Thevenin's equivalent voltage source in series with Thevenin's equivalent resistance across the two terminals of the circuit. For more info, please check my video on Thevenin's Theorem.

[@subashinit3422]

Please give me easy way to pass important questions and important topics in each units wise give me please in circuit analysis-1 second semester for engineering

[@ALLABOUTELECTRONICS]

Please go through the second channel.( ALL ABOUT ELECTRONICS- QUIZ). There is an entire playlist on network analysis subject.

[@piyush9355]

In last example why is it - 5I1 and not +ve as there is a rise in that 5ohm resistor.

[@ALLABOUTELECTRONICS]

Because if you move in the clockwise direction, then there is a drop across the 5-ohm resistor (moving from positive voltage to negative voltage). That's why it was considered negative.

[@towsifsalauddin3138]

as far as i know after replacing 1 volt with short circuit current won't pass through right and below 1 ohm resistor as current likes to pass through the path with less resistance the current will simply pass through the short circuit.

[@ALLABOUTELECTRONICS]

What you are saying would be true if there is a short circuit in parallel to the current source. (Across the current source)

[@MUKESHKUMAR-ir4bl]

thanks sir

[@anishchhabra5313]

U didn't explained the formula to find p max and p min..

[@gunnalasaidineshreddy1147]

Tq bro

[@debmalyadutta4756]

It's got nothing to do with your teaching. You teach very well. But by any chance are you South Indian?

[@FPerez-qc8ek]

When you applied the current divider rule(example 1 at 6:02) you say "into 1 ohm", shouldnt it be into 1A?

[@jayantrkulkarni67]

Can you add AC circuits transient analysis?

[@hgtannhaus4889]

bruh u r a pro but if u teach like a pro noobs won't understand

[@vishnu5027]

How is it +V1' ? Why is it - to + at 1 ohm resistor?

[@priyanshisomani9569]

Ya, I have also the same doubt plz explain.

[@janakiram8842]

Can we use mesh or node analysis while solving ckt in super position theorem

[@ALLABOUTELECTRONICS]

After applying superposition (Considering only one source at a time), the equivalent circuit can be solved using the node or mesh analysis.

[@janakiram8842]

@@ALLABOUTELECTRONICS thankyou

[@endlashiva2220]

At 12:04 made a mistake see once i.e you have to keep power2(square) for Pmax,then only we get Pmax=450 otherwise we get Pmax=30 watts....my humble request to cross check once

[@ALLABOUTELECTRONICS]

Yes, that's true. And I have already mentioned that in the pinned comment two years back :) But anyway, I am glad that you have pointed that out.

[@gudurumadhu9391]

good videos but u explained briefly

[@reddysaimaram]

Nice explanation

[@mayurshah9131]

nice Narration

[@shahidbangash8491]

sorry you actually confused me...you made it too difficult .....

[@lols5761]

But why is that..show me..