Altering the X-ray Spectrum | X-ray physics | Radiology Physics Course #22

[@rishabhshrivastava6290]

This videos are very very helpful to me sir.i was not able to understand this concepts in class Especially the calmness through which you teach and giving conclusion of every topic make it easy to understand Thank you sir🙏🙏

[@fazaltahir4216]

Superb explanation, very very nicely presented. Thanks a million 😊

[@radiologytutorials]

Thank you Fazal 👍🏼 really appreciate all your support on these physics videos!

[@saaniakapila6600]

your whole x-ray series has been insanely helpful! so grateful to you!!!!!

[@radiologytutorials]

Ah that’s so good to hear! Thank you for letting me know Saania ☺️

[@Dysacanthos]

Very helpful, thank you! Highly appreciated.

[@radiologytutorials]

Great! Glad it was helpful ☺️

[@sawanisadeera1915]

Thank you so much sir...🥹🙏 well understood..♥️

[@seeseteb]

Really helpfull and clearly discussed😊

[@radiologytutorials]

Excellent! Glad it helped 🙂

[@Robbieron]

Great explanation 😀

[@radiologytutorials]

Glad it was helpful! Thank you Robin 🙂

[@user-tc9do9kg7m]

Thank you, this is helpful

[@SmitBirajdar]

Thank you sir. Sir any video for understanding tube and thermal rating please.

[@janmauer4859]

Can’t get enough!!!!

[@emiliasalas1447]

eres el mejor! hi from Miami, Florida USA

[@MuhammadIbrahim-ip7nq]

Excellent explaination

[@radiologytutorials]

Thank you Muhammad!

[@ramaymd]

perfect...you are a good man :)

[@radiologytutorials]

Appreciate it 🙂

[@franziskamuhlhoff4587]

I finally understand what ist going on. Thank you very much! However, I have a question. In the filament current you use 80 kV as an example but you have in the next graph 100 keV. While in the tube potential the 80 kV has 80 keV. And I do not really get, why..

[@clairekelly6730]

Can you clarify how increasing kVp increases beam quantity? My textbook says that higher energy electrons individually create multiple interactions at the anode, resulting in multiple photons produced from each electron. In this video it sounds like you're saying higher kVp pushes more total electrons from the cathode to the anode, not that each electron is creating more photons?

[@chad969]

Hi Michael, in this video you say that bremsstrahlung radiation production is exponentially proportional to the atomic number of the target material. But in your review course on Radiopedia you wrote "anode material: beam quantity is *_directly_* proportional to the atomic number (Z) of the anode material". Maybe I'm misunderstanding what it meant by the phrase "directly proportional", but I interpret that to mean that there's a positive *_linear_* (rather than exponential) relationship between atomic number and bremsstrahlung production. Can you clarify what you meant by that statement on radiopedia? Does the phrase "directly proportional" mean exponentially proportional? Thanks

[@sid17391]

thank you for this amazing video series. One question, is the ma (tube current) the same as the filament current. I've read that it is not. Can you clear it up for me?

[@radiologytutorials]

Pleasure. Yes, there is a difference. Filament current is the current passing through the tungsten filament (changes affect the number of electrons released via thermionic emission). Tube current is the flow of electrons across the tube - this is influenced by a combination of the filament current and the tube potential. A change in tube potential will influence the tube current but not the filament current.

[@asraflatif4172]

Hi i would like to ask if we were to use single phase alternating does the tube current move through and fro the anode target due to the alternating direction of the current. Or am i totally in confus ion. 😂

[@radiologytutorials]

Exactly Asraf 🙂 There obviously wouldn't be any electrons produced at the anode but those within the vacuum would head back towards the cathode when the current switches (not ideal!) That's why we need a direct non-alternating current 👍

[@michael_nel]

First! 🎉