First year of Radiography and your videos are literally saving my mental sanity. You speak so clear and in depth that it doesn't even feel I am learning, you make physics "easy" Thanks a lot!
@radiologytutorials Жыл бұрын
Ah that’s great news Delia ☺️ so glad they’re helpful!
@timothymeunier5657 Жыл бұрын
I'm paying thousands a month for my classes and i'm learning more from your "free" videos than at my collage. Great job.
@radiologytutorials Жыл бұрын
Thank you Timothy. Makes me very happy to hear! Appreciate your support. Feel free to ask any questions if you come across something you don’t understand. Best of luck with your studying 📚
@timothymeunier5657 Жыл бұрын
I'm finding it challenging to find the answer to this objective: Identify factors affecting characteristic K-shell photon production.
@amandahiya8067 Жыл бұрын
Thank you so much for making xray physics so much interesting and easy. What i liked the most is that you are not just brushing the topics off, you are letting us dive deep into your wisdom
@radiologytutorials Жыл бұрын
Thank you Aman. That's very kind of you!
@daisycasado1694 Жыл бұрын
Understanding physics for X-ray more with your videos than I did in my radiology classes and that was a very long time ago.
@GrahamScott-j7h8 ай бұрын
Brilliantly explained! Thank you!
@emmablassel8437 ай бұрын
Thank you is not enough. You saved my life !
@rupamghosh2020 Жыл бұрын
2:20 - Major difference between Bremsstrahlung and characteristics radiation
@noonereallyknows66439 ай бұрын
By far the best explanation I was able to find! Thanks! Subscribed!
@ebbamarie Жыл бұрын
Thank you so much for your input! Finally I got it!! 😊 Just a comment on the term "Bremsstrahlung" : "Bremsen" as you said means to "break or slow down" in German and "Strahlung" is nothing else than "radiation" . So Bremsstrahlung means "Radiation slowing down". Just to mention it, in case it helps and makes sense.👋
@radiologytutorials Жыл бұрын
Thanks for letting me know 🙂☺️ glad the video is helpful!
@griseldarios53702 ай бұрын
Bravo 👏 you’re brilliant!
@shemymwanalindah Жыл бұрын
Just completed my diploma level in radiography but am understanding what i missed out in school you the best
@radiologytutorials Жыл бұрын
Nice! Well done on completing your diploma! Always good to refresh once in a while
@ShaimaAbnIdriss4 ай бұрын
Thank you for the great effort Medical physics master student
@anyanzonathan59636 ай бұрын
Brilliantly explained
@MohammadSadiq-n8p9 ай бұрын
Thanks for amazing explanation sir
@ShamimHossen414 күн бұрын
Thanks for the good lesson
@biancawalker3976 Жыл бұрын
Your explanations are so brilliant! I finally understand bremsstrahlung and characteristic radiation 😁😁 Thank you!
@radiologytutorials Жыл бұрын
Yay! Thanks Bianca 🙂
@Ronnock Жыл бұрын
You're better than my online tradeschool. I'll be spending some money on your material, soon.
@radiologytutorials Жыл бұрын
I’m so glad you find the videos helpful 🙂
@Zeyad-i5l9 ай бұрын
amazing explanation ❤❤thank you .
@harukabbh7 ай бұрын
you explained so clear thank you so much
@priyanshisharma07055 ай бұрын
Location of 1.x ray tube 2.grid 3.image intensifiers 4.transformer 5.control panel Please tell.
@giorgilagidze9020 Жыл бұрын
Amazing video. A couple of questions. 1) if electron directly hits the nucleus(kinetic energy becomes 0) and highest photon energy is produced, does the electron that hit the nucleus dies ? or what happens to it ? disappears ? dies ? on your video, on the screen, you didn't draw any line for it or mentioned it. 2) since we know Bremsstrahlung can produce continous spectrum, can it produce gamma-rays/visible light or it can only produce x-ray ? 3) would be awesome if you could have mentioned inner and outer Bremsstrahlung as the way it's explained on the internet is super difficult. Thank you.
@nightowlandabibliophile4 ай бұрын
Are you referring to the Electron binding energy?
@riio15 Жыл бұрын
So grateful for finding you, u hooked me up i guess i just have to watch the full playlist ♥
@radiologytutorials Жыл бұрын
I hope it helps!
@SA--------80807 ай бұрын
Very nice👍👍👍.. Love from Pakistan 🇵🇰🇵🇰
@armandmorin50162 ай бұрын
An electron (charged particle) generates its own magnetic field, so after a change in direction.. is it the field that carries on forward that we call an X-ray?
@maemetjamadike5538 Жыл бұрын
Sending gratitude, you helped a lot
@radiologytutorials Жыл бұрын
Thank you Maemetja 🙏🏻
@yitzchaqbanda8846 Жыл бұрын
@@radiologytutorials can't see the bank of questions
@maramnashwan2433 Жыл бұрын
Thanks a lot you made it crystal clear
@JavanKibet-lv7kw8 ай бұрын
THANK U MONSIEUR
@ashdos720511 ай бұрын
this is amazing thank you!
@doctorshinki88485 ай бұрын
along the x-axis, why is the maximal keV up to 90-100? sorry i don't understand this
@SakariEklund5 ай бұрын
what does p mean in the formula of the photoelectric effect probability? Thank you
@dareenjiad22464 ай бұрын
density of the filter material (greek letter rho which looks like a p) :)
@SakariEklund4 ай бұрын
@@dareenjiad2246 thank you :)
@paolofedeledigiglio2405 ай бұрын
incredibile spiegazione...
@giggitygoo92 Жыл бұрын
Loving the videos! Will likely be a full subscriber to your Q-banks in a few months before CORE. Kudos to your great work and commitment!
@radiologytutorials Жыл бұрын
Thank you for your support 🤗🥰
@emmanuelmakinde07 Жыл бұрын
Please can you explain why out of the 1% of Xray produced at the anode majority is Bremsstrahlung
@radiologytutorials Жыл бұрын
Sure! Characteristic X-rays only occur when an electron collides with inner shell electrons in the target material. The atoms that make up the target material are large. Relatively speaking the electrons are tiny (they make up a very small proportion of the atom). Therefore, a bombarding electron is much more likely to ‘miss’ the electrons. Very few will actually collide with electrons. The majority will slow down when experiencing the attractive electromagnetic force of the nucleus - and subsequently release a bremsstrahlung radiation.
@emmanuelmakinde07 Жыл бұрын
@@radiologytutorials thank you so much
@LolRoboShotU Жыл бұрын
Somewhere around the 6 minute mark on the bremsstrahlung diagram, you display the nucleus's positive magnetic field strength. Wouldn't each individual electron has its own negative magnetic field? I understand that could junk up the diagram and make things too complicated. I was just curious
@إبراهيم-الحاسي20058 ай бұрын
Thanks... I am Arabic students, I study in medical college.
@radiologytutorials8 ай бұрын
Pleasure. Good luck with the studies!
@priyanshisharma07055 ай бұрын
Please make the vid on auto transformer and self rectification before 13 please kindly request there is exam
@nightowlandabibliophile4 ай бұрын
Ty for this♥️
@LauranceLi Жыл бұрын
very clearly
@butterfly7448 Жыл бұрын
الحمد لله الله اكبر لا اله الا الله
@drharuna-bw9rn Жыл бұрын
Thank you
@colourless2843 Жыл бұрын
Long lost memories🥲🥲thank you so so much
@kennediclarke Жыл бұрын
Helpful!
@radiologytutorials Жыл бұрын
Glad to hear it Kennedi 👍🏼
@flosyeet11 ай бұрын
awesome
@fadhiraabdallah7358 Жыл бұрын
How,i cant see the bank of question ......can u plz help m
@radiologytutorials Жыл бұрын
Hi Fadhira. It should be in the first line of the description
@yogeshanfat627811 ай бұрын
🙏🏻🙏🏻
@radiologytutorials11 ай бұрын
🤗🤗
@yogeshanfat627811 ай бұрын
❤❤
@radiologytutorials11 ай бұрын
Glad it was helpful 👍
@PadmaPriya-kr9vjАй бұрын
Can u put this vid in tamil !!! 😢
@herbkilian11 ай бұрын
As a German I shudder at your pronunciation of Bremsstrahlung.