Python Tutorial - Prime Numbers | Printing Prime Numbers in Given Interval

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Have been struggling with understanding this and suddenly stumbled on this. So explanatory. Thank you for your effort.

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[@AmulsAcademy]

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[@Sidramnathsing]

I have done what you did but then many of the numbers ended up printing multiple times. Can someone help me with this?

[@lekkalabhargav-di5fo]

Break the statement after one loop

[@sabithrad8899]

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[@AmulsAcademy]

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[@AmulsAcademy]

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[@rma1563]

Your explanation is crystal clear! ❤

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[@AmulsAcademy]

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[@bhavana333]

It's awesome . The way you explained was too basic and it's really helped me to understand internal loop flow.

[@AmulsAcademy]

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[@AmulsAcademy]

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[@TusharsMedlife]

Best explaination

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[@hhemanthkumar8599]

Ⓛⓞⓞⓢⓤ

[@rahulprasadsingh2639]

lower=int(input('lower')) upper=int(input('upper')) for num in range (lower,upper+1): if num>1: for i in range (2,num): if num%i==0: break else: print(num)

[@jitheshjackeyjo4998]

Wow..!! Excellent explanation ma'am

[@AmulsAcademy]

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[@kfbscit074aryansingh4]

Very well explained !!! Keep it up

[@prathameshpawar8793]

Nice explanation.

[@AmulsAcademy]

Thank you :)

[@tgdesihiphopraps]

Wow!! Nice explanation Finally i got the logic for prime number I appreciate ur work

[@AmulsAcademy]

Glad to hear that :)

[@tgdesihiphopraps]

@@AmulsAcademy have u uploaded prime number using while loop because its way too confusing in while loop

[@yaswanthreddy3839]

Great teaching ma'am

[@AmulsAcademy]

Thanks a lot :)

[@sushimeng]

Hi, I have a question about what if 2 in the range(2, num), the range will be (2,2) which has no number contained.

[@harikrishnants8545]

It will print nothing. In this case, if your "num" is two(2), it means you would have given your upper limit as two(2).In range, it will take only (n-1) values. So that would print nothing. As it would be like (2,1), I suppose.

[@siewkingsam2534]

@@harikrishnants8545 then how she get 2 in the second example

[@anunayshukla7195]

will this program work if we take lower value as 2 ???

[@k_abhishek2056]

Thank you so much .now i m getting confident in coding because of ur video..love and respect🙏🙌❤

[@NBEESETTISRAVANI]

Than you so much mam,ur explanation will be change us ,please come again with more video to improve us mam

[@AmulsAcademy]

Pleasure 😊

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[@mamatharani-xd6zp]

I love your teaching

[@sangbala9201]

I want numbers in single line and I want comma in between numbers. What can I do

[@AmulsAcademy]

use end parameter . you can try end="," in print function

[@sangbala9201]

@@AmulsAcademy Thank you

[@sangbala9201]

@@AmulsAcademy I have another doubt. If I use print(i, end=",") as you said, I get comma at the end of the number. That is , my lower range is 1 and my upper range is 10. My prime numbers are2,3,5,7 . If I use end="," in print , i get my output as 2,3,5,7, . I get comma at the end of 7. How to avoid this.

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you got a new subscriber!!😊😊👌😘👍👍

[@AmulsAcademy]

Welcome!! :)

[@subbusubramanyam3375]

what is the execution if inner loop range is (2,2)

[@unknown__..--]

Same doubt

[@sachinshukla2227]

I am learning ,keep it up please

[@AmulsAcademy]

Thank you 😊

[@gokceozkonuk9300]

Thanks for the help!

[@AmulsAcademy]

Happy to help! :)

[@rajaarya117]

Valuable teaching.. 👍

[@advatprashr13]

maam, i am not able to understand how 2 is getting printed if we use 2 as our lower limit. 2 will get divided by range(2,1) hence will break out from the loop and nothing should be printed. please reply

[@AmulsAcademy]

We took range form 2 to num. {for i in range(2,num)} when num is 2 range will become range(2,2) so it won't execute for loop body so it will execute else part and it will print 2 as prime number.

[@AnkuTelang]

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[@girijaaakula5322]

Thank you so much mam.. 👍🙏

[@dhritimanbharadwaj2741]

Why ELSE part is written below FOR, not below IF?

[@AmulsAcademy]

We can use else with loops, for and while loop. And here we can't use else part with if . If i use that i won't get proper output. for i in range(2,num): if (num % i) == 0: print(num,"is not a prime number") print(i,"times",num//i,"is",num) break else: print(num,"is a prime number") for example: take number 21 control goes to if condition and it will check, if 21%2==0 No so it come out of the if body and execute else part, that is it will print message 21 is prime number, but it is not. i need to check all divisors right. So we can't write like this. We are using for - else because it will check whole for loop body, it will divide the number with every other number starting from 2 and if that number is not divisible then we will print the message that is "not prime number". :)

[@charvireddy6432]

@@AmulsAcademy Thank you so much. I have the same question. it really makes sense to me now.

[@vedantx-b2986]

@@AmulsAcademy I was having the same question thnx for answering , actually no one explains this for-else loop nor I find it on any website so it's a bit confusing

[@ekeshtayal8178]

awesome video Sister,your videos helps me lot......................

[@AmulsAcademy]

Thank you:)

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Excellent video

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Thank you 😊

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[@pravalmarya1892]

Thankyou for the incredible explanation.....

[@ASHOKKUMAR-jm6yn]

Tnq for clean n crisp explanation. Keep uploading.. Lots of love from Visakhapatnam

[@AmulsAcademy]

Thank you :)

[@allenjr4978]

@@AmulsAcademy what if the lower value starts from 2

[@sufiyanmogal1527]

Nice Explanation Mam 👏

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[@sakthivel-dq2wr]

simply superb 😍

[@zaedgtr6910]

Excellent explanation

[@mdfarhan0203]

well explained✌😊😊

[@AmulsAcademy]

Thank you :)

[@eshanirajverma676]

Best explained.....🙂🙂😘👌👌👍👍

[@DeepakRaj-pv5eo]

Hey amulya I have watched a video for prime numbers... I cant remember but it was like for i in range(2,n//2+1): If n%i ==0: break else: print(n) Is it true

[@AmulsAcademy]

Yes i think this will work :)

[@nagapavanyarramsetti283]

@@AmulsAcademy pls explain this

[@AnishEmilGodsonR]

i want to know why you are printing else statement in the line of for loop rather than if statement ???

[@AmulsAcademy]

We can use else with loops also, and here we need else with while loop 😀

[@shruteekhot1483]

This is so nicely explained.Thank you!

[@AmulsAcademy]

Glad it was helpful! :)

[@sahanasjalageri1092]

Mam only this method can use Or other methods r in there

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Has to really appreciate how well u explain everything 🙏🏻❤️💯

[@arbinsubba1956]

Excellent teaching

[@AmulsAcademy]

Thank you:)

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Thank you Amul for a very well presented lesson. Thanks to you I now understand !

[@AmulsAcademy]

My Pleasure :)

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Nice teaching

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Thank you so much mam ur videos are Very helpful... please keep going

[@AmulsAcademy]

Thank you :)

[@wasimferoz6378]

Very lucid explanation ma'am Thank you

[@hideweapon1361]

wow u explained very well thx

[@AmulsAcademy]

You're welcome! :)

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Nice explanation

[@AmulsAcademy]

Thank you :)

[@saleem7266]

thank you madam u are really teaching well

[@AmulsAcademy]

Pleasure :)

[@roasted_boy6213]

thanks mam u r really awesome i was not able to understand about num function in this code but u cleared my doubt thanks a lot again

[@AmulsAcademy]

You are welcome 😊

[@hemchandmovva4460]

Thank u so much madam Ur so great

[@AmulsAcademy]

Thank you :)

[@nokiavodafone3394]

Thankyou ....great explanation

[@AmulsAcademy]

You are welcome :)

[@athirakthilak1743]

Thank you mam..😄👍

[@AmulsAcademy]

Most welcome 😊

[@rohanmalandkar8566]

For which 'if loop' that 'else loop' is applied??

[@AmulsAcademy]

else part is used with for loop here :)

[@rohanmalandkar8566]

@@AmulsAcademy ok thanks got it

[@gujjugaming3177]

Nice mam this was useful in my study📚✏

[@adityaac5852]

Really good explanation mam!!!! 👍👍

[@deepikachalla8163]

Could you please upload the video for difference between functions,class,attributes,methods and explain it clearly with one example...how all works

[@AmulsAcademy]

Ok i will try :)

[@lalithapriya9484]

clear cut explanation tq mam

[@AmulsAcademy]

My pleasure :)

[@elavarasanrangaraj3956]

awesome explanation.

[@AmulsAcademy]

Thank you :)

[@madhun4532]

great work!

[@AmulsAcademy]

Thanks a lot! :)

[@jithendrareddytamma6565]

Mam what about 2. 2 is also prime number, but after if statement is true, break statment will execute and I think its a loop. Pls explain

[@jithendrareddytamma6565]

I understood. This reply is for those who didn't understand for 2. If your Lower limit is 2. It's 2 > 1 but when 2 will go to the (2, num) loop. It will become (2,1) because num will be excluded. So it will directly go to the print(num) function.

[@saikrishna.arumalla3355]

your explanation is super.is this any possible to decrease the length of the programe ?

[@nidhirajput810]

Amul good job...but I have a small doubt ..here u used else condition may I know it belongs to which if condition...

[@AmulsAcademy]

else is for, for loop :)

[@anniedhawan7945]

superb 👌 could understand very easily. Thankyou ☺️

[@AmulsAcademy]

Most welcome 😊

[@saikiran-zp6qk]

Thanks for this video

[@AmulsAcademy]

Pleasure 😊

[@muhammedanask8556]

Bro, what about num=2 and i=2 case So the loop will break, but 2 is prime Please explain

[@deepikachalla8163]

I tried using without break statement in this code...I have given number as 9..output as showing as 9 is not a prime number and 9 is a prime number Num=int(input("enter a number:")) If num>1: For I in range(2,num): If num%i==0: Print num,"is not a prime number" Else: Print num,"is a prime number" Else: Print num,"is a prime" Pls explain

[@AmulsAcademy]

When i know there is a number which divides entered number then i know that number is not prime , so when for i in range(2,num): if num%i==0: This condition becomes true then i will print number is not prime and i don't want to execute anything else, so i used break statement there. for example if i take number as 16, first i will check whether 16 is divisible by 2 if yes then i won't check further , i know 16 is not prime so i will print that and stop execution. in your case you are not using break statement, so when i take number as 9, it will check 9%2==0 no so it will check 9%3==0 yes , so it will print 9 is not prime number, but again continue with the for loop, so it will check 9%4==0.... till i =8 ok. here if any other number divides 9 then again the massage "9 is not prime number" will be printed. After that control comes out of the loop , and it will execute else part because , The else block just after for/while is executed only when the loop is NOT terminated by a break statement. Ok so you will get 9 is prime number message also :)

[@deepikachalla8163]

@@AmulsAcademy thank you so much

[@manikandand2541]

hey 9 is not a prime number

[@technicalguy5668]

i dont understand how 2 is printed when (2%2 == 0) if u take range from 2 to 15 instead of 5 ...how 2 is printed when its remainder is 0 when divided by 2...but your code is printing 2 how ?

[@austinejose1516]

yeah this is what my question also,,

[@AmulsAcademy]

for i in range(2,num): if (num % i) == 0: when num =2, for i in range(2,2) : so it won't execute for loop body, control goes to else part directly. so it won't execute if condition. If you have still confusion, execute this piece of code for i in range(2,2): print("h") else: print("a") in range() start and end value is same it won't execute the for loop. :)

[@kangajankuganathan7457]

@@AmulsAcademy thanks sister

[@andrinrafealla8763]

Mam, how did this logic work for when num is 2 Coz 2%2==0

[@reetasharma7505]

Range from 2, num means num will not be included in the for loop

[@andrinrafealla8763]

@@reetasharma7505 : I didn't get it... can you please elaborate

[@AmulsAcademy]

for i in range(2, num) when num=2 for i in range(2,2) here range is from 2 to 2, so it won't execute for body. :)

[@craftnclash1952]

its awesome tomorrow is my exam I hope I will do better tomorrow !😊😊

[@uddandamjyothsana1959]

Nice explanation thank you

[@soulfulman4834]

In case if we have to check only one input number is prime or not then how can we do it??? Another one that we know that 1 is prime number but by using this code we can't get result as 1 is prime number as u mentioned number > 1. So how we check 1 is prime number or not???

[@AmulsAcademy]

To check entered number is prime or not: kzbin.info/www/bejne/oJacd5aunLF1nJY 1 is not a prime number. :)

[@shubhamjain154]

Would this code work or not if not then plzz tell me why no = int(input("enter the no")) count = 0 for j in range (1,no+1): for i in range(1,j+1): if j%i == 0: count+=1 if count == 2: print(i) else: pass

[@luisvaldez6295]

Explain me please, why you added " +1" the beginning . For num in range (lower, upper +1) , I ran without "+1" and it worked.

[@AmulsAcademy]

In range function, end is exclusive. syntax of rang function is, range(start,end,step) if you want to print 1 to 10 numbers then you need to take range as, range(1,11) try this: for i in range(1,11): print(i) :)

[@luisvaldez6295]

Amuls Academy I understood. Thank you 🤗