Fun Math Problem

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Andy Math

Andy Math

Күн бұрын

Пікірлер: 232
@EAOO
@EAOO 7 ай бұрын
3:37 i think you meant to say you rounded not truncated :)
@AndyMath
@AndyMath 7 ай бұрын
Oh no! You are right! I messed that up...
@bebektoxic2136
@bebektoxic2136 7 ай бұрын
I see, that's why I'm a bit confused 😂
@EAOO
@EAOO 7 ай бұрын
@AndyMath all good, love the videos!
@insaneclips1184
@insaneclips1184 6 ай бұрын
Truncated means rounded off. Both are same dear
@EAOO
@EAOO 6 ай бұрын
@@insaneclips1184 no, truncated means you cut off additional digits (usually decimal). So 76.73 would truncate to 76 but round to 77.
@T100Tyrant-xh7ph
@T100Tyrant-xh7ph 7 ай бұрын
My mind after 0.00000001 seconds of looking at this equation : Log Log Log Log
@Aman_Gupta0
@Aman_Gupta0 7 ай бұрын
fr same
@abatall
@abatall 7 ай бұрын
idek what log is i'm doing alg 1 rn
@yotzexotadrogue
@yotzexotadrogue 7 ай бұрын
Fr
@progisloveprogislife4501
@progisloveprogislife4501 7 ай бұрын
It's the opposite of exponenciation, your x in a logarithm is the exponent you need to give to the base (10 in this case) so that the result is equal to 80 (which is called the argument I think). Not that hard to grasp as a concept
@chaabomed
@chaabomed 7 ай бұрын
Exactly! Log from line 1
@ethastum
@ethastum 6 ай бұрын
You could also solve this problem using logarithmic properties: 1. We take the log() of both sides, which allows us to put the exponent as a factor to the logarithm of the base. Giving us: "(x-1)log(40)=(2x+1)log(2)" 2. We multiply into the parenthesis on both sides, and isolate the terms with x in them. Giving us: "x log(40)-2x log(2)=log(2)+log(40)" 3. We isolate x by factoring, and dividing the resulting parenthesis to the right. Giving us: "x = (log(2)+log(40)) / (log(40)-2log(2)) 4. Due to the rule of logarithms used in (1), we can express the "2log(2)" as "log(2^2)" which equals "log(4)", whereafter we use the rule of sums and differences of logarithms. Giving us: "x=log(80)/log(10)" 5. Due to log-base10 of 10 being 1, this gives us the result as: "x=log(80)"
@sm_artx
@sm_artx 3 ай бұрын
For the people trying to show off your logarithmic skills, Andy intended this problem to be understood by those who aren't really familiar with log. So, instead of using log identities from the get-go, he used log only when the equation was already simplified. You and I may be familiar with log, not everyone is.
@iTube4U
@iTube4U 7 ай бұрын
everyone is gangsta untill log shows up
@faizaanfazal
@faizaanfazal 7 ай бұрын
True af
@HableGiday
@HableGiday 6 ай бұрын
Perfect comment😂😂
@hasandhrolia8353
@hasandhrolia8353 6 ай бұрын
Kids!!
@hellboysp7263
@hellboysp7263 6 ай бұрын
bro lowkey
@russellthescout9639
@russellthescout9639 6 ай бұрын
log is taught in 9th grade though. it's just BAP.
@Jack_Attack1234
@Jack_Attack1234 7 ай бұрын
Before even watching the video I know I'm gonna hear "Lets put a box around it" and "How exciting". Almost forgot the “Nice” every time 69 or 420 shows up. And you can’t forget the “this looks like a fun problem” when the video starts.
@ianyoon7336
@ianyoon7336 7 ай бұрын
how exciting
@frankstrawnation
@frankstrawnation 7 ай бұрын
This looks like a fun comment.
@outerspacedog
@outerspacedog 7 ай бұрын
it’s pure hype
@mzoxololinda8408
@mzoxololinda8408 7 ай бұрын
And it looks important, so let's put a box around it 😅
@englishsong8399
@englishsong8399 7 ай бұрын
Or one can just use log
@kae4881
@kae4881 7 ай бұрын
i did it by applying log to both sides, and then solving. it makes it easier because after that its just manipulation. but you do need the value for log 2 and log 40.
@vaibhavgupta8681
@vaibhavgupta8681 7 ай бұрын
Need to know just log 2. log 40 would be log 4 + log 10 . Everyone knows log 10 value and log 4 would be 2 × log 2.
@mr.turtle375
@mr.turtle375 7 ай бұрын
Wonderful explanation.This man can teach us faster than a professional professor.
@frommarkham424
@frommarkham424 7 ай бұрын
I think he is a professional
@euloge996
@euloge996 7 ай бұрын
He is a teacher
@FylinB563
@FylinB563 7 ай бұрын
A professor is inherently a professional
@shivambharadwaj9580
@shivambharadwaj9580 7 ай бұрын
Definitely a middle school teacher ​@@euloge996
@canonogic
@canonogic 7 ай бұрын
Idk why, but this felt like pulling off a combo KO in YuGiOh
@Redawesomeoby
@Redawesomeoby 7 ай бұрын
Bro why ain't I ever thought bout learning math as learning combos in fighting games dawg
@canonogic
@canonogic 7 ай бұрын
@@Redawesomeoby Hadouken to find x 😂😂😂
@olivier.st-amand
@olivier.st-amand 7 ай бұрын
A video about a list of the usual "tricks" that can be used in such math problems (like the 30-60-90 triangle, the exponent substitutions you used here, etc...) would be amazing! Thanks!
@TheBiggerNoise
@TheBiggerNoise 7 ай бұрын
I’m having flashbacks to helping my daughter with Algebra 2 😮 I love how you manage to keep the presentation so brisk, yet also don’t have any mystery steps.
@abeonthehill166
@abeonthehill166 7 ай бұрын
An excellent demonstration ! That was clear and easy to follow. Thanks for sharing !
@craigk.gowens7534
@craigk.gowens7534 7 ай бұрын
My math teacher in high school wouldn't have allowed log 80 as an answer because it can be reduced like square root of 80 can be reduced. Because it is base 10, log 80 = log 10 + log 8 since log ab = log a + log b if the base is the same. Log 10 = 1, so log 80 = 1+ log 8.
@adwaitpandey2526
@adwaitpandey2526 7 ай бұрын
1+3log2 which is approx 1.9
@GrGalan6464
@GrGalan6464 7 ай бұрын
Depends, sometimes it’s the opposite. With a class that I was in, they would want me to write 1 + log 8 as log 80. But log 8 on its own would need to be simplified to 3log 2.
@tovarishch420
@tovarishch420 6 ай бұрын
This is the first time I watch your videos and honestly they're actually helping me understand math even better, I don't know, I try to resolve the problem a little faster than you just to see if I can do it, sometimes I get it wrong but it's fine, I keep trying, thank you! you're helping someone get better at math!
@kartikmaher5
@kartikmaher5 7 ай бұрын
India's secondary school students be like,"like, seriously‽."
@tanishthakur7
@tanishthakur7 7 ай бұрын
Really!!
@unknownfbk
@unknownfbk 6 ай бұрын
Yep, its kinda easy
@D402S
@D402S 6 ай бұрын
Mein timepass karne KZbin mein aaya aur yaha aake yeh problem solve karne baith gya 😂
@evilgaming7860
@evilgaming7860 6 ай бұрын
Even though it is easy for us it may not be the case for whole India. So we should not be full of ourselves.
@shashankyadav5703
@shashankyadav5703 6 ай бұрын
So true
@HurricaneZ
@HurricaneZ 6 ай бұрын
I tried solving it before the video, ended up with the same answer. I just did the log base 2 of 40 first to get the exponent bases to 2. got something around 5.32. set the exponents = to each other due to same bases and boom basic algebra to get to the same decimal answer. (with calculator ofc) nice video tho man 👍
@Epyxoid
@Epyxoid 6 ай бұрын
2:31 I think explaining that with the inverse function is more logical. Just like in _tan x = 2_ we take the inverse function of _tan_ on both sides, which is _tan^-1_ that gives us _tan^-1 (tan x) = tan^-1 (2)_ which simplifies to _x = tan^-1 (2)_ Here, the inverse function of _10^x_ is _log 10 (x)_ Taking that on both sides gives us _log 10 (10^x) = log 10 (80)_ which simplifies to _x = log 10 (80)_
@Shmizzad
@Shmizzad 4 ай бұрын
Of course it’s because we have 10 fingers, not because we count in base 10. I see we’re skipping the intermediate steps now
@kharshithaashree7447
@kharshithaashree7447 7 ай бұрын
Easy method here Just take log on both sides and multiply it in side then you should have an equation with both sides having x of power one and substitute values of log40 ( log4 +log10) and log 2 Then u get 1.602x-1.602=0.601x+0.301 On bringing x oneside and constant on other side u get 1.001x=1.903 Which is approx answer x=1.903 If you need more precise then increase the decimal numbers That's it not even a 2min task
@aadityasrivastava16
@aadityasrivastava16 7 ай бұрын
That's what i was thinking it took me about 1 min to solve this mentally i was like he must have asked a numerical value i solved log 8 ans 3log2 = 3X.30 and i got 1.90
@SaidVSMath
@SaidVSMath 7 ай бұрын
Hey Andy, unsure if you check the comments, but what software do you use to animate your videos? Thanks!
@frankstrawnation
@frankstrawnation 7 ай бұрын
He said that a very few videos ago.
@Dinglebeardedlady
@Dinglebeardedlady 7 ай бұрын
I usually have the answer in my head before he finishes the countdown. ...then I watch the video to see HIS process and what the right answer is.
@RealReen
@RealReen 7 ай бұрын
Kinda boring, but you can solve this almost instantly using log(a^b)=b*log(a)
@sauten2565
@sauten2565 7 ай бұрын
Yeah that’s what I was taught but I guess the way he does it can be understood better by most people
@RealReen
@RealReen 7 ай бұрын
@@sauten2565 true and it also demonstrates far more, useful rules.
@sauten2565
@sauten2565 7 ай бұрын
@@RealReen fax, how far have you gone in maths education, like A levels or further?
@RealReen
@RealReen 7 ай бұрын
@@sauten2565 I'm not sure how it applies to your levels, but danish A-level, and I will be having a lot of maths a uni soon.
@Livvv_happy_3727
@Livvv_happy_3727 3 ай бұрын
Can you show the whole working
@starboy001
@starboy001 3 ай бұрын
I arrived just after studying logarithms. And now this time it is again equality more exciting as always.
@4.0.4
@4.0.4 7 ай бұрын
I should start writing down these equivalences.
@DaniSC_l1
@DaniSC_l1 2 ай бұрын
I feel like just log the 40 so we get 2^5.32 and then just do the rest is so much easier
@Magp1ee
@Magp1ee 2 ай бұрын
I got to the right anwser myself the most inefficient way possible in like a billion steps
@RobG1729
@RobG1729 7 ай бұрын
It'd be cool for you to make videos about our ten fingers and base 10 number system versus others like base 12. I'm sure those too would be exciting.
@metaphoricalhuman
@metaphoricalhuman 7 ай бұрын
Great video, it randomly appeared in my recommendations and i'm having a test on this exact stuff this week
@SRINIX4356
@SRINIX4356 4 ай бұрын
Hi man! What an amazing video! But, the verification can be done like this without a calculator: 40^(x - 1) = 40^(log80 - 1) = 40^(log8 + log10 - 1) = 40^(log8 + 1 - 1) = 40^log8 2^(2x + 1) = 2^(2log80 + 1) = 2^(2(log8 + log10) + 1) = 2^(2(log8 + 1) + 1) = 2^(2log8 + 2 + 1) = 2^(2log8 + 3) = 2^2log8 * 2^3 = 4^log8 * 8 = 4^log8 * 10^log8 = (4*10)^log8 = 40^(log8) here, we can see that 40^(x - 1) gave us 40^log8 and 2^(2x + 1) also gave us 40^log8. so, verified.
@rocky101016
@rocky101016 6 ай бұрын
would it be incorrect to just take the root of x-1 to both sides, which means the 40↑x-1 becomes 40, and the 2↑2x-1 becomes 2↑x and solve from there?
@epsilonthetalambda
@epsilonthetalambda 2 ай бұрын
(x-1 root 2^(2x-1)) = (2^(2x-1))^(1/(x-1)) = 2^((2x-1)/(x-1)) = 2^((2x-2+1)/(x-1)) = 2^((2x-2)/(x-1)+1/(x-1)) = 2^(2+1/(x-1)) = 2^2 × 2^(1/(x-1)) = 4 × (x-1 root 2) You could move more stuff around to get the x-1 on the top, but it's way easier to just use logs
@TrollSilver.
@TrollSilver. 6 ай бұрын
You can also be silly and just find 2 to the power of what is 40 (comes out to 5.2319) and then finding x
@reelkanha
@reelkanha 6 ай бұрын
as a ninth grader, anything after 2:31 is witchcraft
@Sg190th
@Sg190th 7 ай бұрын
yeah, log can work. I just prefer natural log because it looks easier to format in my opinion.
@rathersane
@rathersane 7 ай бұрын
But when the base is already 10…
@Grizzly01-vr4pn
@Grizzly01-vr4pn 7 ай бұрын
How (and more importantly why) would you crowbar ln into this?
@Sg190th
@Sg190th 7 ай бұрын
@@rathersane You can use logarithm regardless but yes, it's usually 10 as base. In this case, it works better. I'm just saying what I prefer in my opinion. Is that bad?
@Sg190th
@Sg190th 7 ай бұрын
@@Grizzly01-vr4pn Crowbar? Huh???
@rathersane
@rathersane 7 ай бұрын
@@Sg190th No… It just seems like more work in this particular case.
@gamingplus8625
@gamingplus8625 7 ай бұрын
@andymath what kind of training do you do for your deep voice?
@krewmermore3324
@krewmermore3324 7 ай бұрын
What a smart and simple way to solve it by rules of indices 😻
@aviationkidd5380
@aviationkidd5380 6 ай бұрын
if u try to compare the exponential powers it gives us the result as 2 which probably is a good approximation pls correct me if i'm wrong thanks :)
@ViReel9436
@ViReel9436 6 ай бұрын
Shouldn't a and b from the LHS and RHS be same?
@Reaper-jr7sz
@Reaper-jr7sz 7 ай бұрын
I did this problem a whole different way and still got 1.903 as a answer
@diazlard
@diazlard 7 ай бұрын
This could be much simpiler. Use a logarithm to find what exponent makes 2 = 40. Expand that through x-1. Use algebra to find x.
@jonathantheyorkie
@jonathantheyorkie 7 ай бұрын
I'm used to the ones that share a common base
@jackmoore2636
@jackmoore2636 7 ай бұрын
I got ln(80)/ln(10) but it came out as the exact same thing, beauty of maths, different kinda methods but same answer if you do it right.
@hilariousroom3181
@hilariousroom3181 7 ай бұрын
Couldnt u do on comparing powers?
@jozeppelachetti7137
@jozeppelachetti7137 7 ай бұрын
I checked this equation with gpt, the first answer for x=4. Then I asked to recheck and it was able to find the same answer but using log2
@adaaaa6642
@adaaaa6642 7 ай бұрын
I solved it in seconds just multiplying entire equation with log10 and got answer without calculator. Anyone with log knowledge can do it.
@dungtrantien1669
@dungtrantien1669 7 ай бұрын
How exciting🗣🗣🔥🔥🔥
@Mecha_Math
@Mecha_Math 6 ай бұрын
Very amazing 🎉🎉🎉🎉
@MarcoPolo-bn9qr
@MarcoPolo-bn9qr 6 ай бұрын
Yay!!! I do it before of seeing the video and I got it right🎉🎉🎉
@papawoolliest423
@papawoolliest423 6 ай бұрын
“Log 10 means the same thing as log, and the reason for that is we have 10 fingers” Wh… what?
@joeyd9351
@joeyd9351 6 ай бұрын
Everything is base 10 unless otherwise stated. I'm not sure if our amt of fingers is the reason for that, but maybe it is
@SlovakiaPanda
@SlovakiaPanda 7 ай бұрын
Thank you, it is actually really funny !!!!!!!!!!!!
@barhas0019
@barhas0019 7 ай бұрын
could you also just do x-1(log 40)=2x+1(log 2) and solve that way?
@Abhi-lz6zo
@Abhi-lz6zo 6 ай бұрын
actually It's much easier that way
@Abhi-lz6zo
@Abhi-lz6zo 6 ай бұрын
Log 40 could be written ans log 4+log10.The only thing is we should know the value of log4 and log2.
@shakhawatparvez8705
@shakhawatparvez8705 7 ай бұрын
As an Asian parent I would say this should be easy for my 2 year old one
@NaveenThiagarajan
@NaveenThiagarajan 7 ай бұрын
Approximately 2, right?
@terakhanthis
@terakhanthis 3 ай бұрын
So, just for the sake of it, 40 is equal to 2^5.321928. If I understand powers right, this would give: (2^5.321928)^x-1 = 2^(2x+1) 2^(5.321928x - 5.321928) = 2^(2x+1) 5.321928x - 5.321928 = 2x+1 3.321928x - 5.321928 = 1 3.321928x = 6.321928 x = 6.321928/3.321928 x = 1.90309
@fuzzballyes
@fuzzballyes Ай бұрын
0:01 saw it and thought 1.90309 immediately 🤭
@CharashGanja
@CharashGanja 7 ай бұрын
Lol i sloved it in my head 😅😅
@kmktruthserum9328
@kmktruthserum9328 6 ай бұрын
I knew that because I brute forced and put 1 as x and 2 as x and then just did 1.5 and kept raising it to 1.9.... They need to make it a bigger x so that I can't just input numbers quicker than it takes to actually use the correct formulas😅
@abeonthehill166
@abeonthehill166 7 ай бұрын
Fascinating ….!
@henrygoogle4949
@henrygoogle4949 7 ай бұрын
x to the a to the b. Whole thing squared.
@anayjoglekar5920
@anayjoglekar5920 2 ай бұрын
just take log in the first place on both side u will end up with 1 + Log(8)
@Eclectic-empire
@Eclectic-empire 6 ай бұрын
Indeed that is how is supposed to be done, 👍
@sp_ahmed8997
@sp_ahmed8997 7 ай бұрын
why didn't you just ln the both sides from the first ? it would've been much easier.
@llll-lk2mm
@llll-lk2mm 7 ай бұрын
im so happy that i could figure this one out in the thumbnail itself heh yay
@abhirupkundu2778
@abhirupkundu2778 2 ай бұрын
Bring Einstein level questions from now on
@Tmwyl
@Tmwyl 6 ай бұрын
Because we have 10 fingers! 😂
@tunneloflight
@tunneloflight 6 ай бұрын
if you apply significant digits - the answers are the same
@segluk69
@segluk69 7 ай бұрын
You could have done a 2nd level unknown equation to get it without a calculator
@mashhudaparveen6475
@mashhudaparveen6475 6 ай бұрын
It took a minute for me to slove. Aaah.....
@Emilia333g
@Emilia333g 7 ай бұрын
Doing this myself before watching the video was weird, it didn't feel right to get such a nice result.
@sstttz
@sstttz Ай бұрын
I prefer to use logs from the beginning lol
@sietsevanderhorst8144
@sietsevanderhorst8144 7 ай бұрын
''its because we have 10 fingers''
@ArnaldoMandel
@ArnaldoMandel 7 ай бұрын
Quite silly, could have applied log base 2 at the outset and just solved thelinear equation.
@peace0173
@peace0173 7 ай бұрын
Without using log i some how by unitary method only i got two values of x which are 1 and 4 and this not possible and my method was also not wrong.
@Shankar-o5o
@Shankar-o5o 6 ай бұрын
much exiting
@konstevs
@konstevs 6 ай бұрын
How exciting.
@anonymouscheesepie3768
@anonymouscheesepie3768 2 ай бұрын
40^x / 40 = 2*4^x 40^x = 80*4^x (40/4)^x = 80 10^x = 80 x = log(80)
@ananasanimator6049
@ananasanimator6049 7 ай бұрын
Решил по формуле Пика за 0,000000002 секунды
@smallgamer7881
@smallgamer7881 6 ай бұрын
just introduce logs to both sides in the beginning 40^x-1=2^2x+1 log 40^x-1= log 2^2x+1 power law of logs, the power of the log can become the coefficient of the log (x-1) log 40 = (2x+1) log 2 x log40 - log40 = 2x log2 + log2 move the x terms to the left, and the log40 to the right x log40 - 2x log2 = log 2 + log 40 factorise x from the right x(log 40 -2log2) = log2 + log40 x= (log2 + log40) / (log40 -2log2) = 1.903089987
@suhaibalkhaldi
@suhaibalkhaldi 6 ай бұрын
i used the natural log from the first step
@aram5642
@aram5642 7 ай бұрын
I thought it was because we have 10 toes
@thinkeightsix
@thinkeightsix 7 ай бұрын
Can you give me an example of how this is useful outside of math?
@satyadas4751
@satyadas4751 7 ай бұрын
problem solving is a very important transferable skill. Being good at solving any math problem means your likely a good problem solver in any setting. Yes, you won't need to solve this specific equation or anything like this in a practical setting, but it trains your brain to think outside the box
@frankstrawnation
@frankstrawnation 7 ай бұрын
​@@satyadas4751Your comment looks important, let's put a box around it.
@stephenbeck7222
@stephenbeck7222 7 ай бұрын
It’s an exponential function. You can google the purpose and application of those. This is a problem solving channel, not an application and vague question answering channel.
@jan_Masilijun
@jan_Masilijun 7 ай бұрын
it's exciting
@y00t00b3r
@y00t00b3r 7 ай бұрын
that's like asking how is breathing useful outside of respiration.
@Fuzierka
@Fuzierka 7 ай бұрын
in the USSR, children solved such examples in nurseries
@samir2zk135
@samir2zk135 7 ай бұрын
IMO childrens thinking capabilities way more powerful. Age won't matter, IG time does.
@francoismusic_
@francoismusic_ 7 ай бұрын
Can I send you a problem?
@user-lynKx
@user-lynKx 7 ай бұрын
wolfram here we come
@Latif1287
@Latif1287 7 ай бұрын
I solved it in another way and i found the same result as yours, i am more happy to send it to you if you want to see how
@aaditnag7960
@aaditnag7960 7 ай бұрын
beautiful maths andy. truly beautiful 🥹🥹
@allayhok
@allayhok 7 ай бұрын
Nice
@Anurag_2.0
@Anurag_2.0 3 ай бұрын
x=1.9 => (x-1)log40 = (2x+1)log2
@irmabecx4758
@irmabecx4758 7 ай бұрын
iIs the reason for that really that we have ten fingers??
@dow_wob
@dow_wob 7 ай бұрын
so simple you just know about log 5on2 =2.3 and done and solve it but you can do it simple you should change this log to log5 /log2 => 0.7/0.3 =2.3 (rounded ) and you dont wana calculator or somthing this question was standard for student
@adityamodi4965
@adityamodi4965 6 ай бұрын
Why i always want to take log😂
@user09832
@user09832 7 ай бұрын
Take log in the first step; (x-1)(2log 2 + log 10) = (2x+1) log 2 => 2x log 2 - 2log 2 + x -1 = 2x log 2 + log 2 => x - 1 = 3(log 2) => x - 1 = 3(0.30103) => x = 1.90309
@samir2zk135
@samir2zk135 7 ай бұрын
That's more what I was thinking lol, how they show us in school. xd
@nabil4389
@nabil4389 7 ай бұрын
Andy!!
@purnashreechatterjee5691
@purnashreechatterjee5691 7 ай бұрын
I got it right somehow 💀
@chitreshbhati9882
@chitreshbhati9882 7 ай бұрын
why don't you apply LOGARITHM on both sides
@irvindalacourt7178
@irvindalacourt7178 7 ай бұрын
amazing thank you
@Voiceistic-kl3ki
@Voiceistic-kl3ki 6 ай бұрын
I'm in 10th class from imdia and solved it very easily
@maincoasters
@maincoasters 6 ай бұрын
i’m in 6th from the usa and solved it really easily
@epsilonthetalambda
@epsilonthetalambda 2 ай бұрын
How i would solve: 40^(x-1)=2^(2x+1) log2(40^(x-1))=log2(2^(2x+1)) (x-1)log2(40)=2x+1 log2(40)x-log2(40)=2x+1 (log2(40)-2)x=(log2(40)+1) x=(log2(40)+1)/(log2(40)-2) =(3+log2(5)+1)/(3+log2(5)-2) =(log2(5)+4)/(log2(5)+1) ≈1.9
@englishsong8399
@englishsong8399 7 ай бұрын
Is nobody going to say how easily it could have been solved by using log
@martinb.3997
@martinb.3997 7 ай бұрын
How tf did I get ln40/2ln2
@martinb.3997
@martinb.3997 7 ай бұрын
Now I got ln40/ln2 how tf am I gonna get through university man
@martinb.3997
@martinb.3997 7 ай бұрын
Well now I got the answer but in negative, I guess I'll leave the logarithmic method for a while now
@NurbekJummayev-p9t
@NurbekJummayev-p9t 7 ай бұрын
Thank you bro
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