Aromatic Side Chain Oxidation to Carboxylic Acid

[@jonathanfong9140]

That last example was a gift brought down from heaven during my time of need

[@Leah4sci]

Awww, thanks!

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@georgiana-js12]

this saved my life and dried my tears when I finally understood it with your help,thankyou so much!

[@Leah4sci]

You're so welcome! Happy to hear it helped.

[@naturesgift9429]

Your Videos clear my doubts which I get during question solving. Thanks a lot!👍

[@Leah4sci]

You're very welcome! glad to help

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@arnavpandita9092]

why does she hold only 155K subs ..... I am pretty sure she deserves more Please share ....... everyone needs to know about such beautiful channel

[@Leah4sci]

Awww, thanks so much!

[@arnavpandita9092]

@@Leah4sci :)

[@AishSiid]

Oh my God! I don't know how to thank you but you're literally a savior. I'm shocked how our teachers never taught us these basics and thought we could do it on our own. Thank you sooo much

[@Leah4sci]

Aww you are so very welcome! I'm happy to help fill on those gaps for you!

[@annisanh8085]

I fall in love with how you explain it ❤️❤️❤️🥰🥰🥰

[@Leah4sci]

Thank you so much 😀

[@amitsongadkar5152]

Got to say...your videos really help.IIT-JEE is a very difficult examination here in India which gives us admission to higher tier colleges.Cheers and keep up the good work.Hope you reach 100k soon though:)

[@Leah4sci]

wow! that's great! You're welcome and glad to help!

[@Silly_cat-_-0]

Hello! I'm also preparing for jee, got any tips for me? It would be very helpful

[@yukisempai4386]

THANK YOU 😍 you gave us all the possibilities!!

[@Leah4sci]

You're very welcome!

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@Silly_cat-_-0]

The way you explain it is the root basis which can make you tackle any problem if you understand it correctly.That's the reason i like your videos there aren't many teachers out there.

[@Leah4sci]

Thank you so much for the kind words, yes this is exactly what I strive to do with my videos

[@lucasmarquezin]

a huge shout-out to you! the best video explaining this topic in an easy way! Thanks a lot!

[@Leah4sci]

Aww thanks! Glad you found it helpful!

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@szshz]

I wanted to understand the reaction that gives us COOH but I guess we don't really need to, thanks for the clear explanation Professor!

[@Leah4sci]

Glad it was helpful! You're welcome.

[@samuelchan5195]

This video explains EVERYTHING so well. thanks so much

[@Leah4sci]

You're so very welcome!

[@Gg55-n7x]

I am from Iraq, and I would like to thank you for your beautiful explanation. My exam is tomorrow and I am grateful that you saved my life.🤣😂🩷 (I apologize if there are errors in writing the sentence, I use Google Translate )​@@Leah4sci

[@srianitha3142]

Thank you ... It helps me to understand this reaction much better than before. Thanks a lot for your help.

[@Leah4sci]

Glad it helped! You're welcome!

[@inshamanowar360]

Interesting, loved it leah!

[@Leah4sci]

Thank you

[@gamingaccount7936]

Wonderful, loved it

[@Leah4sci]

Glad you loved it!

[@justinfrank3552]

You just answered my assignment questions. Thank you

[@Leah4sci]

Awesome, so glad I could help!

[@keraicaptain1247]

thank you so much! may God always bless you........ your lessons are always straight to the point and much understandable.

[@Leah4sci]

Awww, thanks for your kind words!

[@subliminal9144]

thank you, very attractively explained

[@Leah4sci]

Glad it was helpful!

[@silverphoenix_1756]

This was super helpful!

[@Leah4sci]

I'm so happy to hear it!

[@urlanajyothi8980]

thank you... It helped me alot!!

[@Leah4sci]

Glad to hear that!

[@ariannejoybeluan6172]

Thank you for the video 😊💕 it really helps a lot especially that you have explained it well. 💞

[@Leah4sci]

You're welcome 😊 Glad it was helpful!

[@__-xh3uw]

Absolutely beautiful! Thank you very much!

[@Leah4sci]

You're very welcome!

[@__-xh3uw]

@@Leah4sci I would like to see more such videos! Keep up the good work!

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@adityaprakash4110]

Thanks. That's exactly what I was looking for.

[@Leah4sci]

Happy to help!

[@bekky834]

This was so beautiful

[@Leah4sci]

Thanks!

[@metalheadofrock]

Thanks for the clarification.

[@Leah4sci]

You're very welcome!

[@singing.winnie]

thank you so much. you are amazingly talented in teaching. had to say this. 👍👍

[@Leah4sci]

You are very much welcome and thank you for the kind words :)

[@jonathansanchez8802]

This is great content. Thank you for the time and effort!

[@Leah4sci]

You're welcome!

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@jillcamillexo]

You are a lifesaver.

[@Leah4sci]

Awww. you're welcome!

[@chaudharyvedantapurva6343]

Love from India thank you so much mam🎊

[@Leah4sci]

You're welcome!

[@reemaa6564]

amazing explaination!

[@Leah4sci]

Thanks!

[@mennayasser5404]

Thank You this was really helpful with a lot of training examples that is well explained 👏

[@Leah4sci]

Glad it was helpful!

[@vaibhavisistla1008]

Nice explanation

[@Leah4sci]

Thanks!

[@GhadaKhalid-dw6xi]

You're a life saver! Thank you! But where can I find the reduction of alkyl side chains video (if there's one)?

[@Leah4sci]

I'm not quite sure which reaction you're referring to. This video is showing reduction of alkyl side chains on an aromatic ring. To watch my full series on Redox Reactions, make sure to visit Leah4sci.com/Redox For even more on this topic and other organic reactions, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@paolariano4252]

Thank you so much for that excelent video.

[@Leah4sci]

You're very welcome!

[@arunkumars6257]

You are an ANGEL!

[@Leah4sci]

Aww, thank you!

[@noel5544]

Thanks a lot , you are indeed a life saver

[@Leah4sci]

You're so welcome!

[@sandeepanchowdhury5859]

Thanks for the upload 🤘🏾

[@Leah4sci]

You're very welcome

[@sandeepanchowdhury5859]

@@Leah4sci God bless keep shining 🤘🏾

[@aditya_kashyap-bathroom-singer]

Alot of love from India thankyou so much ma'am 🙇🏻‍♂️🙇🏻‍♂️🙇🏻‍♂️

[@Leah4sci]

You're so welcome!

[@madhudeogharia5607]

Thanks mam .It will be very helpful for my iit jee exam.

[@Leah4sci]

Most welcome 😊

[@FoliaFACTZ]

Thanks, good explanation and nice voice 😊😊

[@Leah4sci]

Thanks for your kind words, and you're so welcome!

[@charangandham7802]

Thanks for clarifying my doubt

[@Leah4sci]

You're welcome!

[@breslabahnan8944]

Thank you , that was really helpful

[@Leah4sci]

You're very welcome

[@arwahassn8320]

That was very helpful thank you

[@Leah4sci]

You're welcome!

[@rawan2051]

Amazing 🤩♥️

[@Leah4sci]

Thank you, so glad you like it!

[@sarascravings]

LIFE SAVER❤❤❤😩

[@Leah4sci]

Always glad to save a life ;)

[@onuwabuezemarvelous1242]

Thank you very much ❤️

[@Leah4sci]

you're welcome

[@Itsrage-i4j]

I liked ur Explaination

[@Leah4sci]

Glad to hear it!

[@maryamkausar9820]

helped me alot ... thank you

[@Leah4sci]

You're welcome!

[@siddharthkaduskar4619]

that was really cool the way u explained.......love frm India!!!!!

[@Leah4sci]

Glad you liked it!

[@rodyadel4476]

thank you so much 😍

[@Leah4sci]

You're welcome 😊

[@quxdros7703]

Really helpful

[@Leah4sci]

Glad to hear that!

[@jasonngwa9151]

Thank you so much ❤‼️

[@Leah4sci]

You are so welcome

[@user-zr3zx5ez5w]

I’d like to ask you, 0:55 Is it Methyl benzene? Then we make [O] under special condition to give banzoic acid, Is this correct ?

[@Leah4sci]

Yes, that is correct. The specific reaction you are referencing is the oxidation of methyl benzene (common name: toluene) to make benzoic acid.

[@ramsmoorthy1097]

Fan of u from india loved the video tqs a load

[@Leah4sci]

You're welcome!

[@rachid12117]

Thank you

[@Leah4sci]

You're welcome! :)

[@tanimadil5888]

Nice and helpful...

[@Leah4sci]

Glad you liked it

[@BroBytesBhai]

I guess its very long since this video wasade but I was wondering, is this oxidation classified as an example of subsitution in the benzene ring? Nice clear and concise video btw!

[@Leah4sci]

Even though it appears to create a new group on the ring, I would not classify this as a substitution reaction, as it does not follow the traditional mechanism for an electrophilic or nucleophilic aromatic substitution. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@royalchalengersbengaluru]

I needed mechanism with cro3, but it also helped me

[@Leah4sci]

Glad it helped!

[@paingsoekhant8731]

Can you also upload a mechanism for that ?

[@Leah4sci]

that being?

[@EmptyyCups]

Thank You Miss. For this vid.. 🙏 ~ India

[@Leah4sci]

You're welcome!

[@YouMockMe]

That was a good little vid. Understood this concept quick! ...we'll see if it sticks haha

[@Leah4sci]

FIngers crossed (after I finish typing) that it does!

[@tanmayjana6297]

Thanks 👍👍

[@Leah4sci]

You're welcome!

[@shivangiyadav383]

Thanku you clear my doubt😊

[@Leah4sci]

Glad to help!

[@MUSICWITHMEGH]

Miss I have one doubt, what if the carbon has no benzylic H but has triple bond ? Will it form benzoic acid?

[@Leah4sci]

If you have a question about the example in this video, I'd be glad to answer. However, since I don't offer tutoring over social media, for help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@sugondhesenuts838]

what happens to the molecule that gets cut off? would it be the second product of the reaction? if not, where does it go to?

[@Leah4sci]

Yes, it would be a side product in solution (Unless CO2 then it bubbles out as gas). Most professors focus on just the ring but if you have to show a complete reaction, make sure to account for the side product as well

[@talkotlovker8226]

Will it work the same with h2cro4?

[@Leah4sci]

I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@munirah836]

Ma'am THANK YOUUUUU

[@Leah4sci]

You're welcome 😊

[@shanthala1345]

Thank you ma'am

[@Leah4sci]

You're welcome!

[@izharalam2775]

Kmno4 is acidified or alkaline?

[@Leah4sci]

For which reaction exactly? Please email me at [e-mail] with your question and a time stamp.

[@nishantsen6820]

For oxidation of benzyl acholol by kmno4 also the same mechanism?

[@Leah4sci]

Yes, it would produce the exact same product as seen here in this video.

[@okukuduncan1089]

so my question is , is there colour change in the case of KMnO4

[@Leah4sci]

This video doesn't address that particular question. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@kinzazafar336]

excellent

[@Leah4sci]

Thanks!

[@vanessatravieso8775]

i am BEGGING for anyone on the internet to actually write out the mechanism! this is infuriating! everyone skips over it

[@Leah4sci]

I'm so sorry. For in-depth help with questions like this and more, I always recommend joining my organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@kuntalkoley3107]

Mam, please make a vedio on selective oxidation and selective reduction

[@Leah4sci]

I have one like it in the LiAlH4 vs NaBH4 video

[@Shikhu813]

Love from India😍

[@Leah4sci]

Thanks!

[@harnoorsingh3631]

In the last question, there were 3 carbons, why did we oxidise only 2 of them? Due to steric hindrance or what? Good video tho! Keep It up!

[@harnoorsingh3631]

And will it make hydrogen bonding in the last question?

[@Leah4sci]

There were only two benzylic carbons, directly substituted on to the benzene ring. Only those two carbons are oxidized to carboxylic acids (because of the high reactivity of their benzylic protons), and the third carbon that joined them together is cleaved in the process.

[@Leah4sci]

And yes, carboxylic acid groups are great at participating in hydrogen bonding interactions.

[@harnoorsingh3631]

@@Leah4sci thank you so much!!!!! I hope you have a great day! 🫡🤍

[@shauryashrestha2582]

thanks

[@Leah4sci]

You're welcome!

[@cristiangarciaperez3537]

What if it has alcohols after the benzylic H

[@Leah4sci]

Usually, we see this reaction happen when there is strictly an alkyl chain attached to a benzene ring. Meaning, a branched or unbranched carbon chain with a benzylic hydrogen. For further questions, feel free to follow up with me through my website at Leah4sci.com/contact

[@kcocrekcus8760]

Why in products I have benzoic acid rather than c6h5cook??

[@Leah4sci]

I don't know which exact reaction you're referencing in this video. But I understand the question. Technically, a second step of an acid workup is required to convert the benzoate to benzoic acid. Which form of the molecule predominates is largely dependent on the pH of the final solution.

[@kcocrekcus8760]

@@Leah4sci thank you so much for answer ♥️ yeah my question wasn't strictly about reaction in this video.I asked because i had in my textbook reaction : ethylbenzene+ KMnO4 ---> MnO2 +KOH + CO2 +C6H5COOH For me is should be rather ---> MnO2 +K2CO3+KOH + H2O + C6H5COOK And that's why i started looking for video which maybe explain this situation more

[@madhavipasupula2767]

all examples were not covered

[@Leah4sci]

Which example ,specifically, are you referring to?

[@varshasathe5191]

ty

[@Leah4sci]

You're welcome!

[@godsonantony5228]

Plz make a video explaining oxidation and reduction in Nitrogen groups in organic chemistry☺☺ sister....

[@Leah4sci]

The free videos are what I do as I have time. For more help with this topic, feel free to contact me through my website: leah4sci.com/contact

[@muhammadhassan540]

Good

[@Leah4sci]

Thanks

[@muhammadhassan540]

@@Leah4sci thank you very much mam for guidance

[@ansh9318]

I want to know the mechanism because without it I will fell empty on concept.

[@Leah4sci]

I don't have any videos covering the mechanism. most professors do not require you to know it

[@jcvn8915]

I just love you

[@Leah4sci]

Thanks

[@ushaushlu9662]

Thanks of giving this knowledge but I want know exact mechanism involved in oxidation of kmno4 with alkylbenzene ..

[@Leah4sci]

You're very welcome. I'm sorry, but I don't offer tutoring over KZbin comments. For help with this and more, I recommend joining the orgo study hall. Full details: leah4sci.com/join

[@chaithanyashyam3373]

What happens to the cut off groups?

[@Leah4sci]

Side products

[@DrMa7sheye]

@@Leah4sci Yeah... he asked what happens to them?

[@user-tg1en3gk7k]

Thanks alot! اسال الله ان يهديك يا اختي

[@Leah4sci]

You're welcome!

[@investorbrains5863]

🙏🏼🙏🏼 🇮🇳 thanks mam

[@Leah4sci]

You're very welcome!

[@investorbrains5863]

@@Leah4sci mam are u indian...??

[@americanboy7040]

Two weeks lectures in 5 minutes!!!! 🤣😂😅😂😂🤣🤣👍👍👍👍

[@Leah4sci]

oh wow! Glad to help!

[@wadkarjurez6890]

Love ❤️ from India 12th science student give me your best wishes to pass me in 12 with 80% Inshallah 👍

[@Leah4sci]

Best wishes, happy my videos are helping you!

[@wadkarjurez6890]

@@Leah4sci Thank you ❤️

[@abha9155]

Love u mam

[@Leah4sci]

Thanks!

[@TheGrowBros]

Anyone else using this to help with hydroxylation of mitragynine?? 😁

[@Leah4sci]

I'm unsure. For help with topics like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@michaelb5767]

I gave up on med school months ago but i dont have the heart to unsubscribe

[@Leah4sci]

awwww...thank you.

[@sosomaged6583]

Thank you so much 💛

[@Leah4sci]

You’re welcome 😊

[@krishnachoudhary7792]

Thank you

[@Leah4sci]

You're welcome

[@alishathasildar2104]

Thank you mam love from India❤

[@Leah4sci]

You're welcome!

[@ruklanidesilva8337]

Thank you

[@Leah4sci]

You're welcome