Aromatic Side Chain Oxidation to Carboxylic Acid

[@jonathanfong9140]

That last example was a gift brought down from heaven during my time of need

[@Leah4sci]

Awww, thanks!

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@georgiana-js12]

this saved my life and dried my tears when I finally understood it with your help,thankyou so much!

[@Leah4sci]

You're so welcome! Happy to hear it helped.

[@naturesgift9429]

Your Videos clear my doubts which I get during question solving. Thanks a lot!👍

[@Leah4sci]

You're very welcome! glad to help

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@AishSiid]

Oh my God! I don't know how to thank you but you're literally a savior. I'm shocked how our teachers never taught us these basics and thought we could do it on our own. Thank you sooo much

[@Leah4sci]

Aww you are so very welcome! I'm happy to help fill on those gaps for you!

[@arnavpandita9092]

why does she hold only 155K subs ..... I am pretty sure she deserves more Please share ....... everyone needs to know about such beautiful channel

[@Leah4sci]

Awww, thanks so much!

[@arnavpandita9092]

@@Leah4sci :)

[@yukisempai4386]

THANK YOU 😍 you gave us all the possibilities!!

[@Leah4sci]

You're very welcome!

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@samuelchan5195]

This video explains EVERYTHING so well. thanks so much

[@Leah4sci]

You're so very welcome!

[@girlotaku7242]

I am from Iraq, and I would like to thank you for your beautiful explanation. My exam is tomorrow and I am grateful that you saved my life.🤣😂🩷 (I apologize if there are errors in writing the sentence, I use Google Translate )​@@Leah4sci

[@annisanh8085]

I fall in love with how you explain it ❤️❤️❤️🥰🥰🥰

[@Leah4sci]

Thank you so much 😀

[@amitsongadkar5152]

Got to say...your videos really help.IIT-JEE is a very difficult examination here in India which gives us admission to higher tier colleges.Cheers and keep up the good work.Hope you reach 100k soon though:)

[@Leah4sci]

wow! that's great! You're welcome and glad to help!

[@szshz]

I wanted to understand the reaction that gives us COOH but I guess we don't really need to, thanks for the clear explanation Professor!

[@Leah4sci]

Glad it was helpful! You're welcome.

[@lucasmarquezin]

a huge shout-out to you! the best video explaining this topic in an easy way! Thanks a lot!

[@Leah4sci]

Aww thanks! Glad you found it helpful!

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@srianitha3142]

Thank you ... It helps me to understand this reaction much better than before. Thanks a lot for your help.

[@Leah4sci]

Glad it helped! You're welcome!

[@keraicaptain1247]

thank you so much! may God always bless you........ your lessons are always straight to the point and much understandable.

[@Leah4sci]

Awww, thanks for your kind words!

[@justinfrank3552]

You just answered my assignment questions. Thank you

[@Leah4sci]

Awesome, so glad I could help!

[@ariannejoybeluan6172]

Thank you for the video 😊💕 it really helps a lot especially that you have explained it well. 💞

[@Leah4sci]

You're welcome 😊 Glad it was helpful!

[@aditya_kashyap-bathroom-singer]

Alot of love from India thankyou so much ma'am 🙇🏻‍♂️🙇🏻‍♂️🙇🏻‍♂️

[@Leah4sci]

You're so welcome!

[@GhadaKhalid-dw6xi]

You're a life saver! Thank you! But where can I find the reduction of alkyl side chains video (if there's one)?

[@Leah4sci]

I'm not quite sure which reaction you're referring to. This video is showing reduction of alkyl side chains on an aromatic ring. To watch my full series on Redox Reactions, make sure to visit Leah4sci.com/Redox For even more on this topic and other organic reactions, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@chaudharyvedantapurva6343]

Love from India thank you so much mam🎊

[@Leah4sci]

You're welcome!

[@subliminal9144]

thank you, very attractively explained

[@Leah4sci]

Glad it was helpful!

[@charangandham7802]

Thanks for clarifying my doubt

[@Leah4sci]

You're welcome!

[@madhudeogharia5607]

Thanks mam .It will be very helpful for my iit jee exam.

[@Leah4sci]

Most welcome 😊

[@adityaprakash4110]

Thanks. That's exactly what I was looking for.

[@Leah4sci]

Happy to help!

[@urlanajyothi8980]

thank you... It helped me alot!!

[@Leah4sci]

Glad to hear that!

[@singing.winnie]

thank you so much. you are amazingly talented in teaching. had to say this. 👍👍

[@Leah4sci]

You are very much welcome and thank you for the kind words :)

[@royalchalengersbengaluru]

I needed mechanism with cro3, but it also helped me

[@Leah4sci]

Glad it helped!

[@mennayasser5404]

Thank You this was really helpful with a lot of training examples that is well explained 👏

[@Leah4sci]

Glad it was helpful!

[@FoliaFACTZ]

Thanks, good explanation and nice voice 😊😊

[@Leah4sci]

Thanks for your kind words, and you're so welcome!

[@gamingaccount7936]

Wonderful, loved it

[@Leah4sci]

Glad you loved it!

[@jillcamillexo]

You are a lifesaver.

[@Leah4sci]

Awww. you're welcome!

[@bekky834]

This was so beautiful

[@Leah4sci]

Thanks!

[@arunkumars6257]

You are an ANGEL!

[@Leah4sci]

Aww, thank you!

[@silverphoenix_1756]

This was super helpful!

[@Leah4sci]

I'm so happy to hear it!

[@inshamanowar360]

Interesting, loved it leah!

[@Leah4sci]

Thank you

[@BroBytesBhai]

I guess its very long since this video wasade but I was wondering, is this oxidation classified as an example of subsitution in the benzene ring? Nice clear and concise video btw!

[@Leah4sci]

Even though it appears to create a new group on the ring, I would not classify this as a substitution reaction, as it does not follow the traditional mechanism for an electrophilic or nucleophilic aromatic substitution. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@vaibhavisistla1008]

Nice explanation

[@Leah4sci]

Thanks!

[@noel5544]

Thanks a lot , you are indeed a life saver

[@Leah4sci]

You're so welcome!

[@jonathansanchez8802]

This is great content. Thank you for the time and effort!

[@Leah4sci]

You're welcome!

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@EmptyyCups]

Thank You Miss. For this vid.. 🙏 ~ India

[@Leah4sci]

You're welcome!

[@metalheadofrock]

Thanks for the clarification.

[@Leah4sci]

You're very welcome!

[@nadiaechegoyen9164]

Wow you explained this so easily thank you !!!!

[@Leah4sci]

Glad to help!

[@siddharthkaduskar4619]

that was really cool the way u explained.......love frm India!!!!!

[@Leah4sci]

Glad you liked it!

[@__-xh3uw]

Absolutely beautiful! Thank you very much!

[@Leah4sci]

You're very welcome!

[@__-xh3uw]

@@Leah4sci I would like to see more such videos! Keep up the good work!

[@Muhammadislahmedia]

kzbin.info/www/bejne/sIWonY2Ph6qopJI

[@ramsmoorthy1097]

Fan of u from india loved the video tqs a load

[@Leah4sci]

You're welcome!

[@Itsrage-i4j]

I liked ur Explaination

[@Leah4sci]

Glad to hear it!

[@paolariano4252]

Thank you so much for that excelent video.

[@Leah4sci]

You're very welcome!

[@sarascravings]

LIFE SAVER❤❤❤😩

[@Leah4sci]

Always glad to save a life ;)

[@quxdros7703]

Really helpful

[@Leah4sci]

Glad to hear that!

[@reemaa6564]

amazing explaination!

[@Leah4sci]

Thanks!

[@MUSICWITHMEGH]

Miss I have one doubt, what if the carbon has no benzylic H but has triple bond ? Will it form benzoic acid?

[@Leah4sci]

If you have a question about the example in this video, I'd be glad to answer. However, since I don't offer tutoring over social media, for help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@YouMockMe]

That was a good little vid. Understood this concept quick! ...we'll see if it sticks haha

[@Leah4sci]

FIngers crossed (after I finish typing) that it does!

[@shivangiyadav383]

Thanku you clear my doubt😊

[@Leah4sci]

Glad to help!

[@harnoorsingh3631]

In the last question, there were 3 carbons, why did we oxidise only 2 of them? Due to steric hindrance or what? Good video tho! Keep It up!

[@harnoorsingh3631]

And will it make hydrogen bonding in the last question?

[@Leah4sci]

There were only two benzylic carbons, directly substituted on to the benzene ring. Only those two carbons are oxidized to carboxylic acids (because of the high reactivity of their benzylic protons), and the third carbon that joined them together is cleaved in the process.

[@Leah4sci]

And yes, carboxylic acid groups are great at participating in hydrogen bonding interactions.

[@harnoorsingh3631]

@@Leah4sci thank you so much!!!!! I hope you have a great day! 🫡🤍

[@arwahassn8320]

That was very helpful thank you

[@Leah4sci]

You're welcome!

[@sosomaged6583]

Thank you so much 💛

[@Leah4sci]

You’re welcome 😊

[@user-zr3zx5ez5w]

I’d like to ask you, 0:55 Is it Methyl benzene? Then we make [O] under special condition to give banzoic acid, Is this correct ?

[@Leah4sci]

Yes, that is correct. The specific reaction you are referencing is the oxidation of methyl benzene (common name: toluene) to make benzoic acid.

[@onuwabuezemarvelous1242]

Thank you very much ❤️

[@Leah4sci]

you're welcome

[@krishnachoudhary7792]

Thank you

[@Leah4sci]

You're welcome

[@sugondhesenuts838]

what happens to the molecule that gets cut off? would it be the second product of the reaction? if not, where does it go to?

[@Leah4sci]

Yes, it would be a side product in solution (Unless CO2 then it bubbles out as gas). Most professors focus on just the ring but if you have to show a complete reaction, make sure to account for the side product as well

[@sandeepanchowdhury5859]

Thanks for the upload 🤘🏾

[@Leah4sci]

You're very welcome

[@sandeepanchowdhury5859]

@@Leah4sci God bless keep shining 🤘🏾

[@maryamkausar9820]

helped me alot ... thank you

[@Leah4sci]

You're welcome!

[@breslabahnan8944]

Thank you , that was really helpful

[@Leah4sci]

You're very welcome

[@rawan2051]

Amazing 🤩♥️

[@Leah4sci]

Thank you, so glad you like it!

[@munirah836]

Ma'am THANK YOUUUUU

[@Leah4sci]

You're welcome 😊

[@shanthala1345]

Thank you ma'am

[@Leah4sci]

You're welcome!

[@jasonngwa9151]

Thank you so much ❤‼️

[@Leah4sci]

You are so welcome

[@paingsoekhant8731]

Can you also upload a mechanism for that ?

[@Leah4sci]

that being?

[@tanimadil5888]

Nice and helpful...

[@Leah4sci]

Glad you liked it

[@godsonantony5228]

Plz make a video explaining oxidation and reduction in Nitrogen groups in organic chemistry☺☺ sister....

[@Leah4sci]

The free videos are what I do as I have time. For more help with this topic, feel free to contact me through my website: leah4sci.com/contact

[@tanmayjana6297]

Thanks 👍👍

[@Leah4sci]

You're welcome!

[@Shikhu813]

Love from India😍

[@Leah4sci]

Thanks!

[@shauryashrestha2582]

thanks

[@Leah4sci]

You're welcome!

[@kuntalkoley3107]

Mam, please make a vedio on selective oxidation and selective reduction

[@Leah4sci]

I have one like it in the LiAlH4 vs NaBH4 video

[@kinzazafar336]

excellent

[@Leah4sci]

Thanks!

[@okukuduncan1089]

so my question is , is there colour change in the case of KMnO4

[@Leah4sci]

This video doesn't address that particular question. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@nishantsen6820]

For oxidation of benzyl acholol by kmno4 also the same mechanism?

[@Leah4sci]

Yes, it would produce the exact same product as seen here in this video.

[@talkotlovker8226]

Will it work the same with h2cro4?

[@Leah4sci]

I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@ushaushlu9662]

Thanks of giving this knowledge but I want know exact mechanism involved in oxidation of kmno4 with alkylbenzene ..

[@Leah4sci]

You're very welcome. I'm sorry, but I don't offer tutoring over KZbin comments. For help with this and more, I recommend joining the orgo study hall. Full details: leah4sci.com/join

[@americanboy7040]

Two weeks lectures in 5 minutes!!!! 🤣😂😅😂😂🤣🤣👍👍👍👍

[@Leah4sci]

oh wow! Glad to help!

[@izharalam2775]

Kmno4 is acidified or alkaline?

[@Leah4sci]

For which reaction exactly? Please email me at [e-mail] with your question and a time stamp.

[@vanessatravieso8775]

i am BEGGING for anyone on the internet to actually write out the mechanism! this is infuriating! everyone skips over it

[@Leah4sci]

I'm so sorry. For in-depth help with questions like this and more, I always recommend joining my organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@cristiangarciaperez3537]

What if it has alcohols after the benzylic H

[@Leah4sci]

Usually, we see this reaction happen when there is strictly an alkyl chain attached to a benzene ring. Meaning, a branched or unbranched carbon chain with a benzylic hydrogen. For further questions, feel free to follow up with me through my website at Leah4sci.com/contact

[@varshasathe5191]

ty

[@Leah4sci]

You're welcome!

[@muhammadhassan540]

Good

[@Leah4sci]

Thanks

[@muhammadhassan540]

@@Leah4sci thank you very much mam for guidance

[@kcocrekcus8760]

Why in products I have benzoic acid rather than c6h5cook??

[@Leah4sci]

I don't know which exact reaction you're referencing in this video. But I understand the question. Technically, a second step of an acid workup is required to convert the benzoate to benzoic acid. Which form of the molecule predominates is largely dependent on the pH of the final solution.

[@kcocrekcus8760]

@@Leah4sci thank you so much for answer ♥️ yeah my question wasn't strictly about reaction in this video.I asked because i had in my textbook reaction : ethylbenzene+ KMnO4 ---> MnO2 +KOH + CO2 +C6H5COOH For me is should be rather ---> MnO2 +K2CO3+KOH + H2O + C6H5COOK And that's why i started looking for video which maybe explain this situation more

[@jcvn8915]

I just love you

[@Leah4sci]

Thanks

[@ansh9318]

I want to know the mechanism because without it I will fell empty on concept.

[@Leah4sci]

I don't have any videos covering the mechanism. most professors do not require you to know it

[@wadkarjurez6890]

Love ❤️ from India 12th science student give me your best wishes to pass me in 12 with 80% Inshallah 👍

[@Leah4sci]

Best wishes, happy my videos are helping you!

[@wadkarjurez6890]

@@Leah4sci Thank you ❤️

[@madhavipasupula2767]

all examples were not covered

[@Leah4sci]

Which example ,specifically, are you referring to?

[@user-tg1en3gk7k]

Thanks alot! اسال الله ان يهديك يا اختي

[@Leah4sci]

You're welcome!

[@TheGrowBros]

Anyone else using this to help with hydroxylation of mitragynine?? 😁

[@Leah4sci]

I'm unsure. For help with topics like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

[@chaithanyashyam3373]

What happens to the cut off groups?

[@Leah4sci]

Side products

[@DrMa7sheye]

@@Leah4sci Yeah... he asked what happens to them?

[@abha9155]

Love u mam

[@Leah4sci]

Thanks!

[@michaelb5767]

I gave up on med school months ago but i dont have the heart to unsubscribe

[@Leah4sci]

awwww...thank you.

[@investorbrains5863]

🙏🏼🙏🏼 🇮🇳 thanks mam

[@Leah4sci]

You're very welcome!

[@investorbrains5863]

@@Leah4sci mam are u indian...??

[@alishathasildar2104]

Thank you mam love from India❤

[@Leah4sci]

You're welcome!

[@rodyadel4476]

thank you so much 😍

[@Leah4sci]

You're welcome 😊

[@ruklanidesilva8337]

Thank you

[@Leah4sci]

You're welcome

[@rachid12117]

Thank you

[@Leah4sci]

You're welcome! :)