Arrhenius Equation

[@Sheena1234ization]

Battle of the century Allery vs Eliot Rintoul

[@spencerhackwell4299]

Rintoul hasn't done Arrhenius though he is great for loads of other things.

[@qasimkhan34]

rintoul a gangster fr

[@jackthickett6825]

Got a Chemistry exam tomorrow and you are so much better at explaining things than my University Lecturer. Keep up the good work!!!

[@AlleryChemistry]

Hope the exam went well

[@kaj9565]

Allery Chemistry v

[@TheSniper9752]

Same here mate, doing some cleanup revision on tricky topics but hopefully I’ll be fine by 2:30pm GMT

[@swiftietay99]

I got my teacher to show this in our lesson because even she was struggling having never taught it and half of my class don't do maths and have never come across logs! So thank you!

[@AlleryChemistry]

You're very welcome! Using buttons on your calculator you never thought you would use!

[@bonniexwony]

you’re literally the BEST chem KZbin channel THANK YOU FOR THE USEFUL CONCISE VIDEOS

[@AlleryChemistry]

You're very welcome!

[@PhoenixVert]

Brilliant video, massively helped me as maths is not my strong point! Thank you so much for putting the effort into making this, keep going!

[@AlleryChemistry]

Cheers! Please share this channel with your friends. The more people that use it the better! 😀

[@amyadamson4285]

the Mr.Bruff of stem.... thankyou for saving my a level

[@AlleryChemistry]

You're welcome!

[@user-ll7gr2um4s]

@@AlleryChemistry replying 4 years later what a top lad

[@benmillbourne2549]

Excellent! I've been waiting to see this appear in my sub box, thank you!

[@AlleryChemistry]

You're welcome!

[@jackletree4300]

Just covered this topic and for the life of me I could not figure out where to start with that equation. This video has really helped pace it out in my head though, thank you! I'm off to watch the second part and hope I can understand the graphs too.

[@sineadquirke9431]

Excellent videos, they are all so clear and helpful. Can you explain how you do the whole equation on a scientific calculator, I keep getting a different answer to what you have. Thank you!

[@blushlushgirl]

Was havin’ a proper meltdown down about this, but now I don’t feel like an idiot, tah luv

[@darcy4522]

God, I swear this has got harder. Previously, I did my alevels in my sciences over ten years ago, and my dad died, so it just did not work out. I'm 32 and trying again, and I am determined to get the grades I need, but omg, it's really hard. But I'm just going to keep trying, set an example for my daughter. Thank you for all the effort you put into your videos.

[@AlleryChemistry]

Thanks for your kind words and I hope your studying goes well. Makes it a lot harder when balancing family life too. Yeh, was a while ago since I did mine and I couldn't remember Arrhenius Equation being on the syllabus.... it's not an easy addition to the spec either.

[@Dangerousbros1]

This video was a great help to me thanks! One question, my textbook (OCR Chemistry) has a different simplified equation to yours their's being lnK = -Ea/RT +lnA with the explanation being that the logarithm of two numbers that are multiplied together is equal to the sum of their logs. This has confused me can you explain? Edit: may be a mistake in text book in the rates summary at the end of the section the rate summary there is the same as the version in your video.

[@AlleryChemistry]

Yes it's the same they just swapped some the terms around. Don't worry about it. I can see why you may be confused!

[@yeifing4223]

if you do as level maths you learn the rules of logs if you add or minus logs you can write it in one log with it multiplying or dividing it assuming they had the same base. example: ln(k)-ln(A) = ln(k/A) or ln(k)+lnA= ln(kA)

[@tomfitzsimmons7263]

Absolute legend, thank you for this!

[@AlleryChemistry]

You're welcome 😊

[@funnyviralespn5878]

Thanks so much for the video as you said...came back to watch it :)

[@AlleryChemistry]

Brilliant! So pleased it helped you!

[@funnyviralespn5878]

Hey, when you have time can you please make a video on a simultaneous Arrhenius question...Thank you.

[@AlleryChemistry]

I will add this to my list

[@elanijey]

Why are the units kj/mol not just kj ? I thought the units for activation energy was just jules or kj

[@BliiiiBlaaaaBluuuub]

i think u missed showing us how to work out half life using k equals ln2 divided by 0.5t for 1st order reactions

[@sincj96]

@allerychemistry Is the value for [A] always 4.55x10^(13) or does it change? If so, why?

[@nichecritter]

This was super helpful and concise, thank you!!

[@AlleryChemistry]

Glad it was helpful! 👍

[@Hank_the_tank101]

Brilliant video! Explained it so well thank you!!

[@AlleryChemistry]

You're very welcome!

[@Letik3x]

When talking about collisions, what do you mean by particles being on the correct orientation?

[@Myst3q]

How do you find the activation energy?

[@lilygarnett5073]

I want to marry you! Thanks so much! All your chemistry vids are so useful particularly the longer ones that focus on particular specifications. You have taught me more than any teacher! No shade to my teachers- they're great but you're better.

[@samiultr]

pls marry me instead

[@theopticalmaoam4938]

@@samiultrno me

[@maroofkhan5332]

In the exam is it fine if we always only use lnk = lnA - Ea/rt. as in the log version of the equation not the normal version cos it’s easier?

[@Rhodah_Musonda]

Can the arrhenius equation be used to calculate the shelf life of a drug?if not what equation can be used

[@amal.i38]

Thank you! Very clear and easy to understand video! =D

[@AlleryChemistry]

You're welcome!

[@amal.i38]

Allery Chemistry :D

[@ronieu1]

I want to draw the arrhenius plot for graphene oxide membrane. I have different values for conductivity data according to temperature and relative humidity. So, my question is what is the values of PRE EXPONENTIAL FACTOR A OF GRAPHENE OXIDE? Could you please help me?Thanks

[@samiultr]

idk mate, why you asking me

[@AndyFilmsUK]

What a legend you are!

[@breezyprabahar8041]

This was brilliant! Thank you so much! :)

[@nusulax3952]

is Ea the only thing they could ask about in the exam?

[@katiecor8553]

Thankyou this has helped me so much

[@-Pollux-]

Is there any reason why the temperature is in Kelvin and not Celsius?

[@hoorias4842]

absolutely adore you

[@madelinechamberlain7212]

When I was doing the calculations along side this video I typed in the numbers EXACTLY as they appear in the video, but got the answer 24569.48362 Does anyone know if there's a mode issue with my calculator or something else? I was so confused Despite now knowing HOW to calculate the answer (thanks to the great video) I don't want to get the wrong answer come the exam cause the mode or whatever was screwed up Any suggestions?

[@flawedvex408]

I got the same value when I copied it exactly, I’ve repeated it multiple times and get the same value, he must’ve miss calculated or we’re stupid

[@darkhacker8747]

@@flawedvex408 nah thats because hes written it wrong. try and do lnA-lnK first in your calculator and then use your Ans (approx 40) and multiply by RT and you get 110779, it took me a while to figure out.

[@flawedvex408]

@@darkhacker8747 yeah I just did it now without using his video and using the way me teacher said to, you’re right it’s 110779.89, he should probably get to amending the video because I could imagine people will have the same issue

[@sagrikaarun9428]

@@darkhacker8747 i did that but i got 110833.2203??

[@MohidPvE]

Thanks !

[@bucwildsfightclub9941]

can it be simplefied to just be lnk/A = -Ea/RT?

[@leonlevell5359]

Why is it when I try the calculation I always get 53.4KJ???

[@darthtoaster6368]

Thank you very much 😊

[@mustafakhan131]

Rajib likes your videos

[@harsevsingh6596]

great video!

[@jamjar342]

made this look easy thanks a million

[@abmis_]

great vid

[@AlleryChemistry]

Thanks

[@nadine-xi3hn]

thank you!!

[@AG-ql1sy]

please help, i really dont understand how an increase in activation energy causes the rate to decrease. i thought, if you increase the activation energy then more particles have enough energy to react so the rate increases?

[@NoorFarouq]

Higher Activation Energy, less particles have enough energy to collide successfully, they do not meet the activation energy, so if less can collide successfully, there won't be as much reacting so the the rate of reaction will be lower. Hope you get it :)

[@AG-ql1sy]

@@NoorFarouq wow lol. i decided to retake my chemistry a levels 3 years later and now i realised i watched this video previously. it's almost funny to me how i knew the answer to my own question 3 years later. thank you for your detailed reply though)

[@SciVerse-k9x]

Lol this thread😂

[@ameliecrevel7710]

unsung hero ^

[@Nick23003]

thanks for the video

[@isaacagordome287]

Exactly helpful

[@thatskykidfreya]

I did exactly what you did but got 24569

[@12345shipreck]

I have an exam on rates coming up, and I couldn't find any videos you have made that cover the A2 rates stuff. Do they exist?

[@AlleryChemistry]

Yes. Here is the kinetics playlist kzbin.info/aero/PLX4e2DxFRGQKXmk0NKKxQfDeKVTTAXf05

[@samistrawberry1]

Is the playlist for the OCR spec?

[@12345shipreck]

Allery Chemistry Thanks

[@AlleryChemistry]

No but this one has all the vids suitable for OCR A - kzbin.info/door/PtWS4fCi25YHw5SPGdPz0gplaylists?shelf_id=3&view=50&sort=dd

[@samistrawberry1]

Cheers! Got an exam coming up as well.

[@veri9350]

Literal lifesaver 😅🎉

[@AlleryChemistry]

Thanks 😊

[@nosir1479]

the fact that u didnt combine the logs is killing me

[@morganroper9643]

Life saver

[@highlander6573]

cheers

[@kadaryousof4823]

The reason he doesn't get more subs is that he dosent do exam questions

[@ramaboy10]

legend

[@huda613]

CHRIS URE SO CUTE THANK U SO MUCH

[@mani-jx7nb]

legend