Physics, Torque (11 of 13) Static Equilibrium, Hanging Sign No. 5

[@danzul1849]

My lecturer suggested two of your videos for our upcoming quiz ! She said the video was very comprehensible as well as my class, good job !

[@stepbystepscience]

Awesome, tell her I said thanks and thank you for watching and commenting.

[@ponongkhoo23]

Crash Course: Teaches me the intro to static equilibrium. Step-by-step science: Brings me into doing exercises in reality. Crash Course + Step-by-step science= Tremendous combo :)

[@stepbystepscience]

Thanks for the great comment and that is a good combination. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@theobirkholz]

Good stuff. You are one of the few people who use printed notes as opposed to handwritten notes successfully. thanks!

[@stepbystepscience]

Thanks for the comment, It takes a while to put them together, space is usually and issue. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@luigianchondo7241]

I suck at physics and struggle with physics class, until I took engineering mechanics class (statics and dynamics combined). After going back to this video, I used the engineering mechanics method instead of traditional physics method and my answers match yours. I’m glad that I understand this topic now

[@stepbystepscience]

I'm glad too!

[@Northumbriaosrs]

Really been struggling on this topic and i've watched this video a few times now and it's finally starting to sink in. Thank you step-by-step science :) really appreciate your video's

[@stepbystepscience]

There are several steps to get through. Hope you get it figured out.

[@KJKP]

Note for newbies: At 3:20, when he says the forces do not create a moment "because they are at 90 degree", he could have been more descriptive to say that those two vectors pass through the chosen center of rotation (the hinge.) This basically means the distance part of F*d is zero, and the moment is therefore also zero. This is why you want to chose a point of rotation strategically so that more components zero out. Peace.

[@lakendallbrown3971]

You are awesome sir! I have been struggling in physics due to recovering from Bacterial Spinal Meningitis, which caused hearing loss and short term memory loss. This step by step explanation has explained everything I couldn't understand. Thank you, you have gained another subscriber..👍

[@stepbystepscience]

Happy to help and best wishes for your full recovery!

[@SamvitAgarwal]

Hey, great video! Can you please explain how you know the direction of the force from the hinge though? Is there any intuitive way to figure that out?

[@vismutti1656]

If anyone is struggling with this one, I think it's a combination of normal force since the shelf doesn't go through the wall and some upward force supporting the shelf on that end/frictional force since 2 surfaces are touching

[@edgarfranco367]

I am so happy and feel so blessed to have subscribed to your channel. Whenever I feel so frustrated and beat myself down for not understanding something people like you renew and refresh my love for math and physics. Thank you for helping me see the logic in the solution process. Physics is so beautiful :)

[@stepbystepscience]

Thanks for taking the time to let me know that my videos have helped you. I wish you all the best in your studies.

[@Flynn1411]

Thanks for the review!!! I have a physics final tomorrow and I needed to review this!!!

[@stepbystepscience]

You are very welcome, hope the final goes/went well.

[@ordinarythings9864]

This really helped. AP Physics test today!

[@stepbystepscience]

Hope it went well!

[@saitmag]

Give this man a medal

[@stepbystepscience]

All I want is a subscription!

[@saitmag]

@@stepbystepscience you got one

[@abebesamuel8931]

Thank you, sir. A thorough explanation.

[@stepbystepscience]

So nice of you, thanks for your comment

[@BruceWayne-us3kw]

this torque stuff is killing me. I'm glad I came across this channel.

[@stepbystepscience]

Glad you found me!

[@samanthalora3453]

you explained this better than my professor…thank you

[@stepbystepscience]

Glad to hear that, my pleasure!

[@Shackled]

Excellent. Def need to go over episode 10-13 again to make sur eI have this foundation down. Thank you!

[@stepbystepscience]

Please do! And thanks for the great comment.

[@bluevelvet7233]

Thank you very much for the lesson. With the current pandemic, I'm forced to self-study and this is really helpful!

[@stepbystepscience]

The pandemic has motivated me to keep making videos. Thanks for your comment.

[@G109938]

Thank You! The step by step was really helpful.

[@stepbystepscience]

Thanks for watching and commenting.

[@Kennamorphosis]

very good thorough explanation saved my life god bless thumbs up

[@stepbystepscience]

Happy to be help out. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@hanatekletekle7121]

Youre a really good teacher, Thank you.

[@stepbystepscience]

Thank you very much for saying so!

[@samuelkelly3863]

Brilliant video, very easy to understand and follow!

[@christopherthomas7262]

This really helped me understand. Just wanted to say you put the forces of tension as force of tension times cos(35) for both of them. But I still understood it so all good. Thanks.

[@stepbystepscience]

I'll check that, thanks!

[@kylebinondo5251]

Thanks to this video it really helps me a lot!

[@stepbystepscience]

You're welcome. Glad to hear that!

[@i1250hsan]

thnak you sir, you describe step by step and explain very well, your video is unique one. thanks again.

[@stitchwitch70]

This was incredibly helpful - thank you very much!

[@stepbystepscience]

You're very welcome!

[@franciscorosario2709]

Great explanation; I wasn't getting this, but this video explained it all very well. Thanks!

[@stepbystepscience]

You are very welcome and thanks for commenting.

[@jstroner]

Thank you some of the best videos out there!!!!

[@farishafazli8526]

may god bless you soul IM BEYOND THANKFUL

[@stepbystepscience]

You are very welcome and thanks for commenting.

[@zonkerzamethyst9224]

very well explained sir and thanks for making my life easier

[@stepbystepscience]

You are very welcome.

[@fedethefurious]

Learned more in 11 minutes than I have in 3 weeks

[@stepbystepscience]

Glad you're learning, thanks for watching!

[@scottgayyrison8401]

Lmao same my physics teachers fucking shit

[@GuruR97]

This video is amazing. Thank you. Taught me in 10 min what my physics teacher couldn't do in a week. However, I did notice one mistake. Starting from 6:57, you set both FTx and FTy as cos35FT, but FTy is equal to sin35FT.

[@GuruR97]

I just noticed that you noticed this mistake. Annotations don't appear on mobile, so I didn't know. My apologies.

[@stepbystepscience]

+GuruR97 Thanks for the comment. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@zecchinoroni]

Thank you so much! I have a physics final tomorrow and this helps a lot.

[@stepbystepscience]

+Groovy Satan Hope the final went well, thanks for commenting.

[@zecchinoroni]

@Luckylucc lol no fucking idea. probably ok tho i got A's in all my classes

[@anilsharma-ev2my]

Changes it into gravitational battery by using spring and load swings and yatch types system

[@eugenechoi9146]

Why is the force of the hinge pointed diagonally?

[@anthonywong7879]

thanks for helping with my homework assignment

[@stepbystepscience]

It's my pleasure and thank for commenting.

[@VALR1able]

Than you for these awesome videos. Your torque and equilibrium are the best available. I didn't have a clue how to solve these questions and you helped me through this topic. I am wondering if you have calculus videos available. I would like to find one that explains limits continuity.

[@stepbystepscience]

Glad you like them!

[@elevenking4584]

Thank you so muchhhh it really helps my physics homework ❤

[@stepbystepscience]

I'm so glad the video was helpful. Thanks for your comment.

[@polarbearanne]

I don't know who you are or why you made this video, but I'd like to thank you! I really needed this breakdown of the forces to understand this concept. Also I like your notation a lot better than my textbook's. In my textbook instead of Fhy, they had Fv. I was staring at it at least 15 minutes just thinking WTH is Fv!?! THANK YOU!!

[@stepbystepscience]

+polarbearanne You are very welcome. I am just a teacher trying to help others be successful in school. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@jimmyharkin9169]

Helped me a lot, thanks! But please slow down, you already understand how it's solved but the people watching this dont. We need time to absorb the info!

[@carmenymigue2010]

Best professor!!!

[@stepbystepscience]

Best comment, thanks.

[@paulinjosepha2336]

Thank you so very much for doing a such helpful video.

[@noramelia6904]

Thank you so much! It is very helpful :)

[@stepbystepscience]

Glad it was helpful and thanks for the positive comment.

[@ronaldpuran4271]

Thanks for the explanation in this video. Only if you can change from cos to sin of FTy in 6:56 it would be great. Besides this, thanks once again for the video and God Bless.

[@matthewissac7963]

I know i'm a couple years late but at 7:00 shouldn't those torques be measured in Newton Meters, because you end up solving for Fty you end up getting N/m. Regardless thank you so much for this video you did a great job explaining this otherwise convoluted problem.

[@myaps1859]

I got FTx and FTy using the Component method of Vectors

[@ajitvarma7906]

From India 🇮🇳 🎉😊😊Excellent vedio

[@stepbystepscience]

Thank you!

[@GodsOfMW2]

at 2:54, don't you mean 0 degrees? Since the tension and hinge force in the x direction are both parallel to the axis of rotation? If it were 90 degrees, i.e perpendicular, then there would be torque no?

[@excellinkus]

What would be the tension along the cable and the the beam if the mass of the beam was zero?

[@sandovstv6515]

How do you know that the value of angle from FT and FTy is 35 also ? when the FTx and FTy is Perpendicular that should be 90 , and the angle between FTx and FT is 35, and the angle between FT and FTY is 35 also ? or the angle between FT and FTy should be 55 ? pls enlighten me ?

[@tommiecommie6863]

Thanks a lot, but what if the sign is centered on the beam and not off to the side?

[@Jake-yv8nw]

Awesome stuff! Thanks, liked and subscribed.

[@stepbystepscience]

Great and thank you very much!

[@farissaamanda2295]

It was indeed very helpful 👍👍

[@davidmojica4520]

I was solving a very similar problem but I got stuck because of this doubt: isn't the hinge supposed to produce an added torque to the system? Therefore, the sum of torque would be: Th+Tty-Tb-Ts=0, where Th is the torque added by the hinge. Could you please explain me why that hinge related torque is not considered in the sum?

[@stepbystepscience]

If I understand your question correctly......if you take the hinge to be the pivot point then the lever arm at that point is zero and therefore the torque would also be zero at that point. Does that help?

[@ralffabulafiedalino691]

thank you really, thank you

[@stepbystepscience]

My pleasure, thanks for watching!

[@peace7784]

you can actually solve this problem without the beam lenght since it cancels out in the torque expression.

[@stepbystepscience]

I don't think so.

[@steffanokorafor1543]

I think there's a mistake in your video. At 6:57 you wrote that Fty = cos35Ft when it should be sin, if I'm not mistaken

[@stepbystepscience]

Thank you.

[@brunodavide92]

Thank you so much, that was a great lesson. Cheers

[@stepbystepscience]

+brunodavide92 Thank you for the great comment. You can see a listing of all my videos from my website at www.stepbystepscience.com

[@xexpo]

Please use Nm for moments.

[@wozzere1]

warren leighfieldThanks for the video . How would you do a sdf and a bmd for this . Any help would be much appreciated

[@stepbystepscience]

What is sdf and bmd?

[@Shridhar_Thorat]

hey, why is the force from the hinge diagonal; at 1:15 ?

[@stepbystepscience]

Actually at first we really don't know the angle, but it depends on how the cable pulls on the bar.

[@Shridhar_Thorat]

@@stepbystepscience Ahh, I see. Thanks mate :D

[@ali92m]

Many Thanks you are a star

[@michaelzavala7871]

thank you very much, very helpful

[@windthorpe9628]

Why does the x component of the hinge force act away from the wall? Isn't it holding the beam against the wall and should therefore be acting into the wall (be in the negative x direction given your coordinate system)?

[@hhaniy]

what if we looking for the mass of the object hanging there?

[@Nono-e4b7b]

Hello, thanks for your great video! Great way of teaching. But I have a question does the hinge always exert a force? And if yes how can we tell its direction?

[@stepbystepscience]

No, it could be zero, but if there is a force the angle has to calculated based on the other forces.

[@Nono-e4b7b]

@@stepbystepscience so can we say that the direction of the hinge force is in the same direction that keeps the object in static equilibrium?

[@StuffWriter]

I would have thought it would have been easier to solve for Tbeam & Tsign as you showed and, then, plug the total of those two into T = rFsinΘ, solving for Fcable. Then, finding the individual components through simple trig.

[@stepbystepscience]

Yes, there is more then one way to solve this problem. I like doing it this way.

[@s_eliza]

Thank you, this was really helpful! My question here though also says to "find the tension in the cable when it has been shortened so that the beam makes an angle of 60 degrees to the horizontal." There's also no hanging mass. Do you know what to do? I'm stuck.

[@scrappydoo69]

Thank you

[@stepbystepscience]

Welcome!

[@fishertech]

Why would the hinge force not be 35 degrees as well?

[@esthercinzah]

Thank you for your videos, but I have a question regarding FHx - FTx, I can not understand how could FHx be positive direction and FTx be negative direction. because FHx is CW and FTx is CCw.

[@tabz6778]

why does the hinge produce a force in that direction (perpendicular to the cable)

[@nurbalqishezlynibrahim5363]

Thank youuuuuu!!!! 💖💘

[@stepbystepscience]

You are very welcome.

[@ikevolley5137]

What if there’s no force of sign given with the same problem

[@joshuac9142]

amazing

[@stepbystepscience]

Thank you! Cheers!

[@Freedomboy006]

way harder.. just do torque total=0.... and use trig to find distance of the rope to the pivot

[@aff4869]

Same opinion , it's still good tho

[@emmanuelmakubabha5109]

thank you so much

[@deeps474]

U are awesomely smart!!! Head off

[@stepbystepscience]

Thanks

[@davidstevens9025]

Could please just explain the method of converting your initial tangent value of 0.286 to 16 degrees? The rest was great, Thank you!

[@thehoff37]

You take the inverse tangent of .286 to cancel out the tangent and just be left with theta, the angle.

[@binyammamo707]

how could we solve the same problem if the sign was hang up on two points of the beam?

[@angieazurill]

is there a way to find an estimate of the angle of Fh with no specific known values?

[@yarakitty2738]

Excuse me sir, isn’t there any contact force from the beam ?

[@davidxguitar]

Way to go video rocks

[@stepbystepscience]

You are very welcome, thank you very much for watching and commenting.

[@faisal8815]

for the angel. why didn't you use tan^-1(Fy/Fx)? pls help I got confused.

[@ivyagustin4337]

Where did you get the 9.8 m/s^2?

[@trieudope]

wonderful bruv

[@alexanderconiff8909]

I could kiss you.. thank you for a really helpful video! Saved my life.... you sir have a new subscriber!

[@florencehashaka4339]

If you use Acceleration due to gravity of 9.81, T = 521.4 N and F = 444.5 N

[@jeffbrigatee9368]

THANK YOU

[@adellafi8173]

Hello Sir , Can I add you on facebook because I have a question about equilibrium , but i cant put it here because it has a photo???

[@stepbystepscience]

Probably not.

[@saitmag]

@@stepbystepscience lmao

[@haicamichung6477]

About FTx=cos35°FT and FTy=sin35°FT Is it really not used? 🤔

[@yawboateng9524]

Thank you sooo much

[@stepbystepscience]

Welcome 😊

[@dawitteferatefera3256]

Why counter clockwise torque =FTyLsin teta

[@enelesnsamila7626]

what ever will be will be

[@stepbystepscience]

+Eneles Nsamila Good question. You can see a listing of all my videos at my website,www.stepbystepscience.com

[@enelesnsamila7626]

+Eneles Nsamila ;ok

[@zhenwei4584]

Great

[@stepbystepscience]

Excellent

[@hetroscodra9210]

Struggling with making the shear body diagram with similar task.

[@Newbport849]

Subbed.

[@stepbystepscience]

+Newbport Subbed what?

[@Newbport849]

To your channel! (Subscribed)

[@stepbystepscience]

+Newbport OK I get it.

[@ranashurrab8344]

helpfull ♡ thanx alot 😘

[@stepbystepscience]

you are very welcome, You can see a listing of all my videos at my website, www.stepbystepscience.com

[@michaeldoherty5086]

This is very nicely done and put across extremely well. But I guess your background is in engineering like me, as you have made a few errors regarding intermediate units. We tech types can be sloppy regarding units. (By the way, I fear mechanics, which is why I'm here.). N/m does not equal newtons. The units of torques are newton metres, so if you write the m like that then the forces will cancel to units of N. The maths, the logic, and the result is perfect as well as being a timely bit of tuition for me, but the unit error threw me - for a bit. Having said that, you know your stuff and sure know how to put it across. You can be my tutor any day. Regards, M.

[@michaeldoherty5086]

Oops, if you write the torque (Nm) like that, then the forces will cancel to newtons, N. This is no criticism. I love your instruction and will happily follow you anywhere in mechanics.

[@gelyvergeaily5547]

thank u !!!

[@matinkeivanloo]

For torque, I got 521, T= (mbg/2 + msg) / sin35* this is how my teacher told us to do. Which one is correct?? Thank you