Bisection Method | Example 2 | Numerical Computation

[@bharatinaikodi01]

Thankyou For this Video, It was really informative and easy to understand and it really helped me to complete my assignment 😅

[@theinfinitemath11]

Thank you for the cheer… And you are most welcome…

[@maskertravel8189]

can you do for the question i. im stil stuck how to solve when the interval was 0

[@ppsasi3694]

thank you so much for this wonderfull video

[@theinfinitemath11]

You are most welcome…

[@aestheticart4955]

Why did you take the values to 4 decimal places?

[@nthabisengmokoena5473]

Why is it F(a) changing when f(x) is a positive? Shouldn't A change when f(x) is negative and B change when f(x) is positive?

[@theinfinitemath11]

Thank you for the comment! The root is where the graph is crossing the x-axis. So, it will always lie in an interval where the graph is going from positive to negative or negative to positive, y coordinates. When f(x) is positive it replaces the positive value on the y-axis, so that we still have both positive and negative values in the interval. Therefore: The positive value between f(a) and f(b) changes when f(x) is positive. And the negative value between f(a) and f(b) changes when f(x) is negative. Hope this helps…

[@adoptedshrek6655]

Thank u mam'

[@theinfinitemath11]

Most Welcome…

[@wagayeweno54]

It is not seen perfectly

[@theinfinitemath11]

Increase the picture quality of the video.

[@maxima4116]

what i dont pick the (1, 3.2) interval, would it still yield the same result if i were to pick (0,1)?