Bisection method - an example

In this video, we look at an example of how the bisection method is used to solve an equation.

[@fredokoth5232]

Thank you from Nairobi- Kenya

[@omnibrain8]

The midpoint formula that you gave is a+((b-a)/2)=(a+b)/2.I don't know you prefer the former over the latter,could you please tell me why?

[@the-Math-guy]

They are the same in fact. No preference

[@thabangselebe4650]

i agree that they are the same.if you peform the arithmetic you will notice tha a-a/2=a/2.so it is indeed the same thing

[@linguafranca7834]

It's simply x=a+b/2

[@bro...5849]

3 years late but a+((b-a)/2) is used since the a+b in the other method can lead to overflow (a and b are very large) if you are attempting to program this.

[@doniellabenaid2796]

can the roots used have a negative sign? like for example, a = -1, b = 2 ?

[@bunersportsandmobilegaming8967]

not we didn't use -ve values

[@joniebech]

what if its both positive? no change of sign?

[@sonofjohn721]

Then there is no root on that interval