Boats and Streams - Concepts and Tricks - Part 2

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This online Aptitude lecture is the 2nd part of Boats and Streams which is important for CAT, MAT, SBI -PO, RBI and other competitive exams and also campus placement tests.
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[@abumoallim]

Your each and every Lectures are awesome . But just a suggestion that in competitive exams we need to solve it much faster , as in problem 3 it is given that upstream is thrice downstream. So Downstream= 3(Upstream) .. Replacing the formula given by you (u+v)=3(u-v) implies u+v = 3u-3v . SO we have equation 2v=u (where v is rate of stream and u=18kmph as Given in Question) . v=18/2 that is 9 kmph . :) . I hope You dont mind. It was a just a suggetion.

[@shafeeqahmedcheeka]

this video was very helpful. Finally got my boats and steam concept cleared which I kept pending probably for a very long time

[@uzairaslam6856]

Hey ..I like your videos very much . Can u please make a video on the questions like a man is crossing a river with boat in still water etc. Thanks

[@bodolocal5914]

thank you very much for sharing your ideas ! ! Now i have the understood the concept.

[@AvadhutManisha]

Really helpful bro .....m doing preparation for MBA ... very hardly I get time to do study ... but your video helping me more to rewis .... thanks

[@snehaltidke7521]

Thank you so much sir..... ❤❤❤❤❤❤❤❤❤❤❤🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🍂🌸🌸🌸🌸🌸🌸🌸🌸🌸🌸🌸🌸🌸🌺🌺🌺🌺🌺🌺🌺🌺🌺🌺🌺🌺🌺🌺🌺🌻🌻🌻🌻🌻🌻🌻🌻🌻🌻🌻🌻🌻🌻🌻🌻🌻🌻🌻

[@surendharv340]

Thankz For The Video With Examples...It Covers Both The Basics And Tricks...Thankz Again...

[@surekhatiwari9856]

very nice, understood completely all the basics, and cleared my all the confusion about this topic. hope for the more number of questions as soon as possible, which can be helpful in our exms as well. thnxx alot .

[@rafiyudin007]

Hi Dani, I like your way of narration and the presentation as a whole..thumbs up!

[@renukalivelife]

very nice explanation.. good going... we appreciate ur efforts & worth watching ur videos.. keep it up.. carry on...

[@sayalibhagat5782]

thank u for ur videos.. the videos are really helpful ...easily understand and explaination is very good... .

[@JangirJayesh]

thank u sir. these viedoes are very helpful to me.

[@SumanDas-yu4tb]

I love teaching style very much

[@swatisingh6607]

Well explained!! But I was looking for a short cut method which will consume less time.

[@aptitudeacademy]

swati singh Hey Swati :) Thanks ... these videos are basicalyl aimed to get you so well rooted in the basics of the concepts that you eventually dont need to mug up shortcuts :)

[@meghjitmajumder3468]

If you first calculate the speed of the current for 6 hrs.,which is just (32-14)=18,then find it for an hr.,which is (18/6)=3kmph & finally (3/2)=1.5kmph.I think this is faster approach,not sure for others..

[@anupammiglani3849]

Please upload more chapters from Quantitative Aptitude section ...finding ur way of explaining more helpful in understanding the concepts ....Thanks.....

[@aishwargupta9991]

Superb explaination and easily undertood.

[@pratikbg]

You can solve this by considering he row the same distance. So, the eq. would be (18+V)T1 = (18-V)T2. While T2 = 3T1. T1 is downstram time and T2 the other

[@yashoda7840]

Well explained...thanks keep uploading more videos...

[@paulraj9961]

simly its awasome teaching

[@bubunmazumder]

ooo!! I think the last problem can be solved in much quicker way...and hope most of us will agree with me...

[@kinngjayesh]

Actually 😃

[@zikraiqbal5409]

Well Explained...Keep it Up..and upload more videos..

[@pallavigarg5061]

Thnx a lot for ur videos... Can u plz upload videos on area

[@aptitudeacademy]

Pallavi Garg You're Welcome Pallavi :) Will do a lecture on Areas soon :)

[@dasariarun9618]

Superb problem 2 explian mircleeee sir.... i need many videos on si@ci plg uplode

[@yakinemon8863]

sir,....ur videos r really helpful and amazing....plz keep making videos...respect from Bangladesh

[@aptitudeacademy]

yakin emon Wow :) Thanks Yakin :) Probably my first comment from Bangladesh :) Do tell your friends as well :) Keep watching! :)

[@ashikpatil1289]

in part 2 of streams and boats, first problem we have to find velocity of current. which means velocity of the stream so it should be 1/2x(a-b) to find right.....

[@milindsk007]

i like this video. please give some video on percentage and probability

[@maheshmorge845]

Good teaching. But do you have any short cut to solve this kind of problem?. i think its bit lengthy. But if v practice on this then can solve fast.

[@deepk2025]

Hi Daniel I didn't get one thing in this Video in problem No. 2 that ....he can also row 30km upstream and 44km downstream in thatwhy u didnt just simply put a=44/13 and b=30/10......why making two equation. simply a=downstream speed=D/t=55/13 and b=upstream=40/13. what is the use of second values in statemtn also he can row .....Pls Explain.

[@starlord035]

First of all thanks for the concept clarification... Dont mind but if only you could give examples besides the ones (and that too from the 1st page itself) from rs aggarwal

[@sangeethetikala]

excellent videos

[@durgachandu3840]

it was really good . but can u make it short

[@devikaasingh3234]

hi , what is the speed of the stream ? 1. the ratio of the speed upstream to the speed downstream of a boat is 2:3 2. The distance travelled upstream in 2 hr by the boat is more than the distance travelled by it downstream in 1 hr by 4 km

[@satishjj]

+Devikaa Singh its 2 kms

[@soujanyav8443]

Last example which u gave is too lengthy to solve in a min. Whatever the explanation was too good!! Good job..keep going :)

[@aptitudeacademy]

soujanya v Yes Soujanya :) My aim is to explain the problem in its entirety so that the person can understand the concept :) Hope you keep supporting the channel :)

[@soujanyav8443]

Ya sure :)

[@shekarsoma4068]

hiiiiiiiiiiii bro.................thanks a lot ....wonderful explaination

[@archanadhakad870]

Hello sir, would you please upload a video on pie chart?

[@ninjav281]

awesome video :) loved the session

[@aptitudeacademy]

Niranjan Venkatesan thanks Niranjan :) Do tell your friends about it as well :)

[@chhatrasal1985]

Good work... Thank you..!! :) :)

[@omkarsurve1994]

thanks a lot buddy'

[@anujdhikle8928]

Great work man😁😁👍🏼👍🏼

[@yeshavantmahantare5565]

thank u , Daniel :)

[@ijajmujawar899]

plz solve this for me i had this questiion in one of the exms A boat can travel from X-Y AND Y-X IN 2 HRS,speed of the boat is 12 km/hr, distance from X-Y is 9 km find the speed of the current ?

[@bodolocal5914]

+IJAJ MUJAWAR is it 3.75 km/h ???

[@bodolocal5914]

+IJAJ MUJAWAR a= x-y/2, since x-y = 9 a= 9/2 now b= y-x/2 but we dont know the value of y-x so lets calculate y-x first. we know distance/time = speed, Since speed is given 12 km/hr, and time = 2 hour y-x/2 = 12 hence y-x = 24, now, b= y-x/2 = 24/2 Speed of current = 1/2 ( a- b) = 1/2( 9/2 - 24/2) after calculating we will get 3.75

[@vigneswarjeyaraj2708]

Hai thank you for the video :-) Is there only 2 parts in Boats and Streams?

[@aptitudeacademy]

Vigneswar J Hey man :) You're welcome! :) Yes unfortunately just 2 parts as of now :) Will make Part 3 soon :) Stay Tuned!

[@vigneswarjeyaraj2708]

Sweet... Thanks a lot dude :-)

[@sweetymadhu3]

ur videos are very help full but i couldnt understand the last problen

[@prabhusundararajinspired]

awesome ji!!!!

[@akshaymohite9122]

stream speed 2kmph,upstream distance 10km,boat return to starting point in 55min ,what is its speed in still water

[@swapnagonuguntla8981]

the speed of boat in still water is 15 km per hour if it can travel 30 km down streaming the same time has it can travel 24 km upstream then what is the speed of the stream

[@udaykiran1856]

hello daniel can u post me the link of trains concepts and tricks part4......i cant find this video on youtube

[@hazrasumanta]

U r great

[@sankarnarayananvenkatesh7726]

hey how did u derive the formulae 1/2(a-b) and 1/2(a+b)

[@ripulswati6814]

there's no tricks to reduce the steps! can you please check it out. It was as same as we have studied in class 10

[@Samfamily05]

1...A man's speed with current is 15 km/hr and speed of current is 2.5 km/hr .What is the man's speed against current ?

[@Samfamily05]

2...A motor boat whose speed is 15 km/hr in still water goes 30 km downstream and comes back in 4hr and 30 min .What is the speed of stream ?

[@varunkommuri7077]

let speed of stream be 'v kmph' 30/(15+v) + 30/(15-v) =9/2 hr 900/(15*15)-(v*v) =9/2 v*v=225-200 v=square root (25) v=5 kmph !

[@studydailylife_vlog3457]

ur videos are very helpful,,but in competitive exams time is important,,bt dose problems takes more time,,how to calculate dose within sec,,if anythng is der share,,

[@aptitudeacademy]

Neeharika Nihu I believe that if the basics are strong, you dont need shortcuts to improve your timing :) I hope you too agree :)

[@sakshikashyap8635]

where are u sir....?

[@turningpoints1810]

last problem not understood

[@anandkumarekbote8647]

good but do explain these problem in case of minutes

[@munmunpal1662]

u talk very fast.. n u r so cute.. i just luk at u. n frget abt the sums

[@ReenaPatel9]

very helpful video

[@swapnagonuguntla8981]

the speed of boat in still water is 15 km per hour if it can travel 30 km down streaming the same time has it can travel 24 km upstream then what is the speed of the stream

[@turningpoints1810]

last problem not understood