Boltzmann Distribution

  Рет қаралды 13,343

Physical Chemistry

Physical Chemistry

Күн бұрын

Пікірлер: 35
@uranium-h3o
@uranium-h3o 2 ай бұрын
I really don't know how would my life be without guys like you on youtube.
@PunmasterSTP
@PunmasterSTP Ай бұрын
What are/were you studying?
@PunmasterSTP
@PunmasterSTP Ай бұрын
Boltzmann? More like "Beautiful work, man!" Your explanation was amazing 👍
@PhysicalChemistry
@PhysicalChemistry Ай бұрын
@@PunmasterSTP Lol, thanks! I appreciate it
@PunmasterSTP
@PunmasterSTP Ай бұрын
@ I’m glad! Just let me know if you ever want to hear a pun on a particular topic.
@PhysicalChemistry
@PhysicalChemistry Ай бұрын
@PunmasterSTP Bon skills, man. Now do Schrodinger
@PunmasterSTP
@PunmasterSTP Ай бұрын
@@PhysicalChemistry Schro, schro, schro your boat, gently down the stream. Merrily, merrily, merrily, merrily, life may or may not be a dream.
@PhysicalChemistry
@PhysicalChemistry Ай бұрын
@@PunmasterSTP nicely done! 💯
@mortezakhoshbin
@mortezakhoshbin 4 жыл бұрын
How is it possible someone watch these amazing videos and dont like or comment!
@PhysicalChemistry
@PhysicalChemistry 4 жыл бұрын
Haha, I guess not everyone enjoys PChem as much as you and I do! I definitely enjoy the feedback and interaction, though. Thanks!
@PunmasterSTP
@PunmasterSTP Ай бұрын
There's probably a lot of people cramming right before an exam and trying to run through stuff real fast...
@puzzle2047
@puzzle2047 2 жыл бұрын
So THAT is the equation in your channel icon! So fascinating!
@PhysicalChemistry
@PhysicalChemistry 2 жыл бұрын
Yes! And that's the key to everything else, as you'll see if you watch more!
@PunmasterSTP
@PunmasterSTP Ай бұрын
@@PhysicalChemistry That sounds Q-uite intriguing!
@ΤηΞδ
@ΤηΞδ Ай бұрын
sorry for bothering, I'm wondering the limitations of boltzmann distribution. Does it apply to interacting system?
@PunmasterSTP
@PunmasterSTP Ай бұрын
What type of interacting system? I suppose it may or may not apply depending on the nature of the interactions.
@melevarck
@melevarck 11 ай бұрын
Thank you once again for your fantastic lectures! I have a question regarding the energy term: I sometimes see it being regarded as the potential energy of a system and sometimes as the hamiltonian of a system (encompassing the kinetic energy term). Which one is the right one? Or are both valid in different circumstances? This confuses me quite a bit, as for me it only makes sense to regard E_i as the potential energy, since the temperature term in beta already accounts for the kinetic energy of the system.
@kuppersrocky6834
@kuppersrocky6834 2 жыл бұрын
Superb explanation!! Could we theoretically include conservation of momentum as a third constraint? And if so, would we still be able to derive the Maxwell-Boltzmann distribution from there?
@PhysicalChemistry
@PhysicalChemistry 2 жыл бұрын
You can indeed use the Boltzmann distribution as a starting point to derive the Maxwell-Boltzmann distribution. You don't need to use conservation of momentum. Instead, the Boltzmann distribution can directly give you the distribution of velocities (kzbin.info/www/bejne/nqDRYWicr86qd7s) and then that can be converted to a distribution of speeds (kzbin.info/www/bejne/any1i4eQj7GBe68)
@lakshaymission548
@lakshaymission548 2 жыл бұрын
Sir Thanks for Uploading these wonderful lectures, also is there way to communicate with you occasionally, something like a discord channel.
@PhysicalChemistry
@PhysicalChemistry 2 жыл бұрын
You're welcome; I'm glad you appreciate them. I don't have a discord channel, but my email address is on the KZbin channel's about page.
@beasthunter3302
@beasthunter3302 2 жыл бұрын
I had a doubt . I am currently studying reaction kinetics .There ,I got to know of the Arrhenius equation .It is very closely linked with the Maxwell Boltzman distribution curve .However I am unable to understand the one thing regarding the pre exponential factor .looking at the exponential part we can say that as T approaches infinity the rate of reaction becomes equal to A (the pre exponential factor ) However we know that A itself is dependent on Temperature .It takes into account the collision frequency which itself increases with temperature .So how can we say ,based on this ,that the reaction constant reaches a finite limit ? Can you please explain .
@PhysicalChemistry
@PhysicalChemistry 2 жыл бұрын
You're definitely right that Arrhenius kinetics are closely related to Boltzmann distribution. We often use the approximation that the Arrhenius prefactor, A, is a constant. But that's not really true, as you point out. A does have some temperature dependence. But A doesn't increase without bound as the temperature increases. It depends not only on the collision frequency, but also on geometric factors and collision cross sections. When the temperature gets too high, the probability of a collision resulting in a productive reaction actually decreases. A full description of how the Arrhenius prefactor depends on temperature can get quite complex.
@rachealbrimberry8918
@rachealbrimberry8918 2 жыл бұрын
@@PhysicalChemistry so were looking for an ideal temperature to measure collision frequency.
@PhysicalChemistry
@PhysicalChemistry 2 жыл бұрын
@@rachealbrimberry8918 Not necessarily. The question is a little unclear. You can measure collision frequency at any temperature you like. There's not really an ideal temperature at which to measure it. The collision frequency does change with temperature, and the Boltzmann distribution can help us understand (in part) how that is true, as is discussed in some later videos on the kinetic theory of gases.
@psychemist
@psychemist Жыл бұрын
What the 'i' and 'j' indexes represt here Please help i am a newbie there but almost got it.
@psychemist
@psychemist Жыл бұрын
Please please anyone reply fast i got the exam coming ahead
@PhysicalChemistry
@PhysicalChemistry Жыл бұрын
The index represents the state of the system. This could be an energy level, or confirmational state, or anything that distinguishes the particular variation that you want to calculate the probability of.
@psychemist
@psychemist Жыл бұрын
@@PhysicalChemistry what purpose is 'i' and 'j' are they the same ?
@PhysicalChemistry
@PhysicalChemistry Жыл бұрын
@@psychemist They are just indices. I could have used any letter. But in this video I used j for a specific state and i inside summations where all possible states are being summed over
@hindh2451
@hindh2451 3 жыл бұрын
Amazing
@PhysicalChemistry
@PhysicalChemistry 3 жыл бұрын
Thanks
@rachealbrimberry8918
@rachealbrimberry8918 2 жыл бұрын
Why would you want to maximize the entropy.
@PhysicalChemistry
@PhysicalChemistry 2 жыл бұрын
That's actually the subject of the previous ~20 videos in the sequence. You've started with the punchline! The short version is that a system will be found most often in the state that has the highest multiplicity -- or the most different ways of existing. It turns out that entropy is a way of measuring the multiplicity. So we maximize the entropy in order to predict what state we will find a system in. For the full explanation, back up to around this video: kzbin.info/www/bejne/pWrJoqpoeLh-jNE and watch in sequence from there.
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