visit www.keleshev.com/ for structured list of tutorials on Boolean algebra and digital hardware design!
Пікірлер: 52
@teambacon5 жыл бұрын
thanks, you helped in 5 minutes with something I've been struggling to understand for a semester. Will recommend you
@Kever18355 жыл бұрын
Thanks alot! Found your website very useful, very clear explaination and it helped me alot! Thanks for taking the time spread your knowledge in such a simplified and understandable form.
@boganza51403 жыл бұрын
Man I'm coming to this video after 10 years of upload date and still there is no video better than this on youtube since 10 yrs....the man who made this video might be dead till now😂
@keleshevCOM12 жыл бұрын
@mwoddo, @00Gravity, There are two ways of simplifying (C' + (CD)')' [mind that it's (CD)' and not C'D']. First way to apply DeMorgans for the whole expression first: (C' + (CD)')' = C'' * (CD)'' = CCD = CD [as I did in the video], The other way is to apply DeMorgans on (CD)' first [as you, guys, propose]: (C' + (CD)')' = (C' + C' + D')' = CCD = CD In both case the result is the same.
@UnseenOct2 жыл бұрын
THANK YOU! I was almost in tears trying to figure this out from my textbook lmao
@keleshevCOM13 жыл бұрын
@Morelloo1 To represent your function with only use of complement (negation) and OR (+ sign) but without AND (multiplication sign) I would double-negated every term and applied DeMorgan's theorem to them: ABC' + BC + C'D = (negate twice every term) ((ABC')')' + ((BC)')' + ((C'D)')' = (applying DeMorgans thorem) (A' + B' + C)' + (B' + C')' + (C +D')' no multiplication in this one! Hope I explained ok.
@RajKumarrajkuttie10 жыл бұрын
thanks sir
@mimimi34405 жыл бұрын
thank you another really usefull video for de morgans theorem , i solved them all for boolean simplification really usefull for me
@dinel61767 ай бұрын
Svaka cast braca
@smalltugz10 жыл бұрын
break the line then change the sign
@moazelsawaf20005 жыл бұрын
I liked it ❤👍
@abualasif3 жыл бұрын
Hey there, are you still alive?
@GiDoRu9011 жыл бұрын
hi, I watched til now every video til 25 ; ) and first of all! You are awesome! Without you I probably wouldn't pass my Computer Science examination. But I have one question: In the second line you "add brackets" to (A'+B)*(B'(C'+(CD)')'). How do you define these Brackets? I did the task before I finished the video to practise and I got exactly the same result, but I did't have brackets, so I couldn't open them! Best Gio from Germany!
@abualasif3 жыл бұрын
Hey there, are you still alive?
@MrAloke712 жыл бұрын
can u tell me that which operation perform first in the boolean expression A + ( B.C ) { there is a bar above B.C ] ? the option i got in the question are a ) AND b ) OR c ) NOT d ) All of them .
@karelminichbauer84834 жыл бұрын
Thanks very helpfull. Good job
@mimimi34405 жыл бұрын
break the line and change from or to and gate remember double negetion is the initial literal
@geetamohanty56575 жыл бұрын
thanks a lot sir......
@033293076798 жыл бұрын
A` + b = 1 , can we put 1 in place of A`+Bin Theorm
@martha-is4du6 жыл бұрын
how would you simplify this using de morgans Y= A'BC'D'+ABCD+AB'CD'+ABC'D'+A'BCD'+AB'CD+ABCD' ?
@moazelsawaf20005 жыл бұрын
Thanks sir ❤
@Morelloo113 жыл бұрын
I like the video it is very helpful. But I have a question. If we are given a function F = ABC' + BC + C'D (where the ' after the letter is bar) and we need to express the function with only OR and compliment operation and then again with only AND and compliment operation how do we figure out the OR and compliment operation because isn't the original equation already in sum of products form?
@abualasif3 жыл бұрын
Hey there, are you still alive?
@Morelloo13 жыл бұрын
@@abualasif yup im alive
@abualasif3 жыл бұрын
@@Morelloo1 Wow, great to know. this is a historic moment. 9 years... crazy lol
@MrsZqiizfiaesy10 жыл бұрын
All of your tutorial is very2 good.. u explain very well and detailed. thanks a lot. i really appreciate on what you did.thank you so much.. i watched all your video.
@abualasif3 жыл бұрын
Hey there, are you still alive?
@user-bw4lv6zj5b3 ай бұрын
thanks arigato gosaimasi oppa mwa mwa chup chup
@00Gravity12 жыл бұрын
hello, by (A´+B)(B´+(C´+C´D´)´), why does (C´D´) not become C+D? Is that because of the doble negation whereas by (AB´)´ there´s only one negation of the sign in between? Thank you very much!
@abualasif3 жыл бұрын
Hey there, are you still alive?
@Karma-mk2ne7 жыл бұрын
thanks i have an exam in an hour
@JabbaDG5 жыл бұрын
did you get through?
@uninor19283 жыл бұрын
(A+(B)'+C+D)-(A+(B)'+(C)'-(D)')'=Y please solve it
@searodrig11 жыл бұрын
(A'+B) is not the same as A'+A)=1. Perform a truth table on (A'+B) there is a case where the output is not always 1.
@JOSHWASOG12 жыл бұрын
u made a mistake in the 3rd to last line where u have (not A+B) = not(A.B) it should be ( A.not B)
@Chokoia6 жыл бұрын
WRONG!
@Chokoia6 жыл бұрын
lol j/k
@awuakate375712 жыл бұрын
@keleshevCOM , in your example in this tutorial (A'B')+A'CD+BCD, could be simplify as (A'B')+CD(A'+B) //(A'+B) is the same as A'+A=1 ? if is so... the the simplify expression will be (A'+B) + CD is it right? thanks for the tutorial
@Chokoia6 жыл бұрын
I got the same thing
@MrAloke712 жыл бұрын
what is word in computer terminology ?
@Chokoia6 жыл бұрын
string
@pradipbhattacharya99726 жыл бұрын
MrAloke7 a group of bits
@angelfernandez55855 жыл бұрын
I think the answer is B+ACD+BCD cause it can still simplify the AB +B B (1+A) So the answer is B +ACD +BCD
@cykatytuberkolsis37615 жыл бұрын
He use demorgans theorm in this example
@abarth08007 жыл бұрын
Something happens when you click. I listen to a big bump.