Limiting Reactants and Percent Yield

Mr. Andersen explains the concept of a limiting reactant (or a limiting reagent) in a chemical reaction. He also shows you how to calculate the limiting reactant and the percent yield in a chemical reaction.
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[@Dirtfarm23]

I'm so glad that you exist

[@paulkirstein2358]

Thanks. This is way simpler than khan academy's video.

[@Dnttashme]

omg better than damn khan academy

[@AndrewMaksymBrainNectar]

+Little Bird yeah I wish they'd add more visuals to kahn academy instead of just writing on the chalk board ):

[@madelinebade2086]

Khan Academy doesnt help at all, this does

[@cookiemoncook]

8 years ago this vid was made and I just learned how I am gonna pass my chem quiz, thank you sooo much 🙏

[@fallingwithoutfear1]

THANK YOU! been struggling with this concept. and you always seem to know how to word it for me to understand, yet again, thank you so much Mr Anderson!!

[@jessebeso8143]

OK, I love you. I spent 3 hours on a limiting reactant problem. It happened to be the same one that I have come across on your video. Thank you! I now know how to work it out. Your the best.

[@iffatjahan5305]

I usually watch Khan Academy videos, but the ones on limiting reagents are REALLY confusing. Thank you so much!!

[@jsy788]

Priceless. Great. Concise. Excellent.

[@invnn]

I have been looking up a lot of these types of examples here on youtube. your example has the best presentation by FAR

[@toadsagesev]

Thank you so much. This is definitely waaaay better than Khan Academy's confusing videos.

[@guitarwizard2000]

Thank you so much for making this. This clarified so many things!

[@JoeKavana]

Thank you Mr. Anderson.

[@rebecarauda120]

Thanks so much! The explanation is very clear so this was very useful for a lab I had today.

[@alliewade509]

Where did the 6.19 come from?

[@akyaford]

Great video! Thank you for your help. Will definitely be watching again. You make it seem so easy:)

[@MehDragon99]

This video is so helpful thank you so much! :)

[@nightfox380]

Your videos are sooo much better thank Khan Academy's. I can't thank you enough for all the videos you make.

[@MultiBattleblader]

I was wondering where you got the actual yield from, but then I realized that it would be given in the question. Thanks for the help!

[@liavbar9218]

You helped me just as much as the video did, thank you!

[@TheFatbaboon]

This guy explained finding the percent yield and limiting reagents better in a 9 minute video than they do in several hours of school.

[@spav95]

You're really saving me the hassle of reading old notes. I attribute any sort of positive grade to you, sir.

[@TheBuffalodiver]

Thank you for your insightful presentations

[@roykilof5204]

This helped me a lot! Thank you

[@jadenw4727]

You are amazing, thanks for helping me pass chemistry

[@954bballer]

this was magical. thank you

[@bethanywilms8913]

super helpful!! Thank you!

[@claireboo5779]

THANK YOU I looked up so many videos

[@TTKarlheins]

Seriously! great work! the visuals help ALOT as well :) THANK YOU AGAIN. P.s. Are you serious about wanting someone to remix this video (as you 'remix this video' button suggests?) Cause i'll do it! I'm not even scared!!!!

[@bluedevilsacc]

thanks Mr Andersen

[@parkjnine]

please make more videos on general chemistry! you explain it better than my college professor

[@RealChemistryVideos]

Great videos!

[@KabooM1067]

Please someone answer this question, I got a problem where the actual yield isn't mentioned.. is there a way to calculate it or is it always given? Is it a mistake in the question?

[@gotsomejams9540]

Thank you, this helps.

[@merrionrabbit3528]

your amazing!!!!!!!! i understandthis now!!!!!!!!!! (after weeks of struggle)

[@bishnughorasaine5544]

its reall helpful u know so helpful

[@IcyXcandi411]

Extremely helpful!!!

[@TheDeltaexpeiment]

I would just like to quickly thank you for this. I am so tired by the time chemistry comes around that I do not retain any thing my teacher says.

[@aksmith2001]

This was extremely helpful until the ending. So how exactly do I get the actual yield?

[@SplosionMovies]

shoutout to Mrs. A for reccomending this channel

[@lalisaluhme]

where did 6.19 come from ? :(

[@Whaheyyy]

He is just using 6.19 as a random number to create the example. Even though 6.88 grams is the actual yield, or rather the maximum yield achievable; in real life this perfect 100% yield will never occur and it is more common for something like 6.19 grams to actually yield. Thinking in another way, if a chemist was particularly bad...they might get something like 3.90 grams yield where the percentage yield would be 57%...as compared to the 90% from 6.19grams

[@DogeFrom2014]

Darwin Peczek Or maybe he actually did a real lab experiment involving the chemical reaction and got actual results. That's how we did it at school.

[@gerbil7red327]

well how the fuck do you even find the actual yield, didnt really help

[@adrianpham8429]

say I have 2 Au and 2 is the coefficient, do i multiply Au twice by it's atomic mass?

[@VSAngelForever]

Amazing!

[@RosaLopez-cw8me]

Why do you multiply by moles and grams of CO2? Why not multiply by 2H2o? I don't understand that part.

[@mamba28874]

How do you find the Excess Reactant? I have a question after finding the LR, it asks, How much excess reactant remains after the reaction has stopped?

[@chriswhitmire4167]

The excess reactant is the other reactant that is not the limiting reactant. In his example the limiting reactant was oxygen, so the excess reactant is methane. It is called the excess reactant because there is some of it left over after all of the limiting reactant has been used up

[@2kAllDay144]

basically what hes saying is that you have to subtract the limiting reactant to the excess reactant.. which in this case would be 27.4g - 6.88g = 20.52g of excess left over.. hoped it helped.

[@mamba28874]

Chris Whitmire Thank You! :)

[@mamba28874]

The Beast14444 Thank You! I understand it now :)

[@KD-vu7om]

Wow. you are amazing.

[@kamylleconsebido376]

How did you get the actual yield? Is it already given?

[@MrMexicanPunker]

where did you get the 6.19g of CO2 of the actual yield? Will you be given that in a question or do you have to solve that some other way?

[@icemanzoom954]

Very Helpful.

[@nxd1141]

you are the man!

[@monaycoon6698]

How do you find the actual yield of 6.19g of CO2?

[@christineaustria7771]

Thanks❤

[@exzisd]

I'm guessing you rounded 3 significant figures at the end for percentage yield. My raw data was approximately 89.97% so rounding 3 SF would be 90%.

[@46562jlarson]

Yes, I understand now...my college prof. went way too fast, and I didn't understand...thank you. :)

[@gustafson2016]

I wish you were my chemistry teacher!

[@ericmaz78]

thank you matt damon

[@kerrywisher8745]

Regarding your limiting reactants video. I followed the 4 blocks format you had shown. but it didn't work. My problem was-" P4 + 6 CL2 ----) 4 PCL3. How many grams of PCL3 could be obtained from 5.62g of P4 & 15.2g of CL2? I got 24.9g PCL3 for the P4 sample and 118g PCL3 for the CL2 sample. The correct answer was, there was not enough Cl...and it was 19.6g PCL3. I think I may have added a step...grams to moles step perhaps...im not sure. But it was certainly wrong. Any help? thanks.

[@kathrynnolan1907]

It was 19.5g PCL3, you rounded your significant figures wrong.

[@henrg]

The GOAT

[@jessisingh862]

Cue the school bell woke me up real fast

[@amitgodara6985]

limiting reagent was understood but i don't get the predicted yield and actual yield

[@buildbearworks8396]

I like the way he explained the limiting reactants but how you found the actual yeild was quite unclear.

[@jackbennett2269]

I'm here bcuz mr hale

[@gracelee3561]

I LUV U UR THE BEST BOZEMAN

[@katewhitacre2617]

I'm confused because he said that methane was the limiting react ant but then he said that oxygen was?

[@briantrek]

thumbs up if this is the best graphical representation of the concept

[@NewTub3r1]

Always

[@xy274]

i get it, and my chem class isn't even up to this yet.

[@johnatkins1484]

This guy looks like crash course guy

[@atreyuXx2]

this increased my knowledge. and my hunger. *sighs*

[@summergurlie97]

so I now understand this

[@RpkRunningfox]

and i am screwed

[@unruly_kween3651]

why can't you be my BIO and CHE professor

[@beanzaru]

but oh well that was in the past so i guess it doesnt really matter

[@johnkevin1104]

his voice makes me sleepy...

[@davidlxxiv]

Yessss dude

[@fruittart3730]

Oh god idk why but I'm so lost

[@MagentaFerret]

1:41 should be thrust, not lift.

[@ronaqsahni5343]

Irrevelevant to the topic in question. So who cares?

[@beanzaru]

this still was sort of confusing to me

[@iknowmewhoareyou2615]

cue school bell?

[@Izeezus]

Usually when Chemistry teachers are at that point during the LR lesson, the bell rings in the middle of the lesson, causing the students to leave class, and leaving the lesson while it's still being taught. It implies that Limiting Reactions take a while to calculate.

[@DogeFrom2014]

***** Lol doesn't really seem true, but still a nice analogy.

[@augurelite]

Coolio

[@NLaw-uo5uk]

what is that "cue school bell?" it is horribly distracting and annoying. very nice video outside of that.thank you

[@nataliedavidson4389]

yummy

[@nataliedavidson4389]

does he offer private lessons????

[@fedyakot]

Haha- reagent

[@nightmindr]

great video, great help; get rid of the bell and the huge popup; it distracting and totaly anoying.

[@paulmckenzie6008]

I'm paying for a class that I have to go on the internet and find people that can teach it BETTER for free... college logic?

[@swiftielife2206]

the schoolbell was annoying