Calculate Concentration and pH ICE Table

Given the initial concentration and equilibrium constant (Ka ionization constant), how to calculate the equilibrium concentrations and final pH.
There is a miscalculation. X = 0.0033 not 0.012. I am sorry for the inconvenience. Thanks!

[@baraskparas9559]

Best chemistry channel on KZbin.

[@OldSchoolChemistry]

Hi Barask, I hope you are well! You are always so generous. Thank you for your comment:)

[@Priyanshu.G]

so if it was 2 mol of h20, it would be 2x right?

[@Memo-py3eu]

does the ionization constant for a weak acid change by the ph of the medium that the acid in ?

[@OldSchoolChemistry]

Hi Memo, No, the ionization constant (Ka) for a weak acid does not change with the pH of the medium. The ionization constant is a characteristic property of the acid itself and is determined by the equilibrium between the ionized and unionized forms of the acid. It is a constant value at a given temperature. However, the extent of ionization of a weak acid can change with pH. In a solution with a lower pH (more acidic), there are more hydrogen ions (H+) present. This can shift the equilibrium towards the unionized form of the acid, reducing its ionization. Conversely, in a solution with a higher pH (more basic), there are fewer hydrogen ions, which can shift the equilibrium towards the ionized form of the acid, increasing its ionization.

[@OldSchoolChemistry]

I got this from Gemini. Here is another place you can ask questions. Thanks:)

[@Memo-py3eu]

@@OldSchoolChemistry thank you so much i was a chemist but didn't practice chemistry for more than 10 years and you really helping me a lot keep the good work please, you have a beautiful smile

[@OldSchoolChemistry]

@@Memo-py3eu Very cool! I understand. I stayed at home for 15 years raising children between working as a chemist and then teaching. I had to relearn a lot! Way to go revisiting it:)

[@salamaalteneiji6062]

thank youuuuuuuuu this is helpful!!!!!!!

[@OldSchoolChemistry]

Hi Salama, I am soooooooo glad:) I hope your class goes well!

[@mohfa1806]

Wow....thanks alot

[@OldSchoolChemistry]

Hi Mohamad, thank you for watching and commenting!

[@chrissydizon8922]

When I input the sqrt of 0.015*7.2x10^-4, I get the answer 0.0033 and not 0.012, what did I do wrong?

[@OldSchoolChemistry]

Hi Chrissy, I recalculated the problem and also got 0.0033. Good catch! Thanks:)

[@callistersmaifwani413]

❤️ thank you I also did get confused 🤔 now it's clear

[@callistersmaifwani413]

And madam so can we also find for HF given that we now have our value of x as 0.0033?

[@OldSchoolChemistry]

@@callistersmaifwani413 Yes:)

[@monafinlayson4637]

How did you get 0.012? I did it like 3 times and everytime I got 3.3×10^-3

[@OldSchoolChemistry]

Hi Mona, There is a miscalculation. X = 0.0033 not 0.012. I am sorry for the inconvenience. Thanks!

[@monafinlayson4637]

@Old School Chemistry took my test passes definitely didn't cheat.

[@OldSchoolChemistry]

@@monafinlayson4637 Way to go!! :)