Calculate Range, Final Speed and Direction of a Projectile Shot Horizontally off a Cliff

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INTEGRAL PHYSICS

INTEGRAL PHYSICS

Күн бұрын

Пікірлер: 12
@Max.Makes.Musics
@Max.Makes.Musics 3 ай бұрын
2:04 best physics quotes ever 😂
@INTEGRALPHYSICS
@INTEGRALPHYSICS Жыл бұрын
@5:55 the value of -24.2 should have gone into the data table as Vfy... Whoops!
@Imagine_Beyond
@Imagine_Beyond Жыл бұрын
I was trying to find out the speed at any point on a trajectory, but I wanted to find it out with an object in an highly elliptical orbit around the Earth. I watched your hohmann transfer orbit video and it really helped, but it only showed how I can calculate the speed at the periapsis and the apoapsis. I was wondering if you could make a video where you show how to calculate the speed at any point on the trajectory. This video does help a bit, but you cannot always use 9,81m/s² since the gravitational acceleration changes depending on the distance between you and Earth.
@INTEGRALPHYSICS
@INTEGRALPHYSICS Жыл бұрын
The easiest way to work that problem is to use the conservation of energy. If you know the height and velocity at any one point, you can then find the velocity at any other height / point along the orbit.
@Imagine_Beyond
@Imagine_Beyond Жыл бұрын
@@INTEGRALPHYSICS Clever, I haven't thought of that.
@INTEGRALPHYSICS
@INTEGRALPHYSICS Жыл бұрын
ME at any point = KE + U which makes it easy. Using angular momentum is a bit harder because you have to know the angle between the velocity vector and the radius vector.
@Imagine_Beyond
@Imagine_Beyond Жыл бұрын
@@INTEGRALPHYSICS Ah, so you are saying that the potential energy + the kinetic energy = the total energy. So I need to calculate the 2 things so that I get ME. Then I can use that to calculate the velocity of the object
@TanishkBairagi-nx1le
@TanishkBairagi-nx1le 8 ай бұрын
Very thank to you sir keep uploading video like that ❤
@INTEGRALPHYSICS
@INTEGRALPHYSICS 8 ай бұрын
Always welcome
@jakechem
@jakechem Жыл бұрын
this video is so good 😭
@INTEGRALPHYSICS
@INTEGRALPHYSICS Жыл бұрын
Thanks! That's sorta what I was going for.
@Imagine_Beyond
@Imagine_Beyond Жыл бұрын
first
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