Calculus - Lesson 10 | When does the Derivative Not Exist? | Don't Memorise

🎯NEET 2024 Paper Solutions with NEET Answer Key: • NEET Answer Key 2024 |...
📅🆓NEET Rank & College Predictor 2024: infinitylearn.com/neet-rank-p... What happens when the function changes abruptly or rapidly? Does the derivative of a function exist in such cases? Watch this video to find the answer to these questions?
To learn more about Calculus, enrol in our full course now: bit.ly/CalculusBasics_DM
In this video, we will learn:
0:00 Introduction
0:59 derivative at x=0
4:31 geometrical representation of derivative at x=0
5:53 slope of a vertical straight line
7:12 derivative at the cusp of graph
7:48 derivative at a combination of corner and cusp
8:42 slope of the vertical tangent line
To watch more videos related to Calculus, click here: bit.ly/CalculusBasics
Don’t Memorise brings learning to life through its captivating educational videos. To Know More, visit DontMemorise.com
New videos every week. To stay updated, subscribe to our KZbin channel : bit.ly/DontMemoriseKZbin
Register on our website to gain access to all videos and quizzes:
bit.ly/DontMemoriseRegister
Join us on Facebook: bit.ly/DontMemoriseFacebook
Follow us on Twitter: / dontmemorise
Follow us : bit.ly/DontMemoriseBlog
#Calculus #Derivative #neet2024 #infinityLearnNEET #neetsyllabus #neet2025

[@InfinityLearn_NEET]

Calculus is used to describe things that change, like how waves move. Waves are very important in the natural world. For example, sound and light can be thought of as waves. To learn more about Calculus, enrol in our full course now: bit.ly/CalculusBasics_DM To watch more videos related to Calculus, click here: bit.ly/CalculusBasics

[@papg8283]

Please see my comments and reply about it

[@codecatt]

Mam, Want Some videos on Trigonometry.... 💙💙

[@jitendrasharma1200]

Upload vdo based on solving questions as for calculus

[@Krishnan172]

At 2:27 how h2/3 came to being? It was simply said it is h > 0. So how come its this fraction only?

[@mandeepkularia]

Yes the derivative of a function is also a function ❤️

[@adisanketpatel2671]

Great explanation we need more teacher like you👍👍👍

[@EddieYu]

A great set of videos for someone like me who wants to refresh the knowledge about calculus. Thank you.

[@atharvbhange687]

Hello DontMemorize, If you are reading this just want to let you know that I'm in 12TH GRADE, it seems there are very few videos of 11TH AND 12TH SCIENCE CONCEPTS , Its a request that if you start posting concept videos for JEE and NEET it would be very very very helpful. Your videos are amazing, hope to see a positive response.

[@ViratKohli-jj3wj]

Please go to a coaching institute for studying for JEE and NEET.

[@boldwrecker4515]

Yes its true.

[@stuartsandskill270]

Hey did you make it through jee

[@arshiyafidyan9155]

Very Helpful Video... Thank You.

[@chadwick2005]

Excellent video for tommorrow's presentation

[@VibingMath]

A very good video for differentiation class

[@akshaykale6388]

Thank you. this is the real concept maker vedios

[@fahadaman8330]

Great one.

[@snapshots-onepagenotesandm1643]

Really groundbreaking simple

[@ArjunIsBoring]

Excellent video. Thank you mam and whole don't memorise team.💓

[@InfinityLearn_NEET]

Thank you so much. Happy Learning :)

[@ngm_4092]

Just want to check at 9:36 is the equation to be 1/h^(2/3), I may be doing something wrong

[@whatifitisandwhatifitisnot1272]

You are right, I have noticed it too, I think it was overlooked as the derivative is supposedly to be (-h)^(1/3)/ -h

[@ritajitpal3323]

Yes I was confused too...

[@ShellYoung]

Exactly right. Here's why: Let's add a power of 1 or 3/3 to a divider. h^(1/3) / h^(3/3) = h^(1/3)*1 / h^(1/3+1/3+1/3)*1 = 1 / h^(1/3+1/3) = 1 / h^(2/3)

[@josephgithinji1490]

@Frank frank supposed to be-h

[@soufianeyes4278]

I think the derivative of a function became a function , because it has a domain of solutions and a range. and think you ,you're amazing

[@AlessandroZir]

thanks!!! very nice explanation; ❤️❤️

[@riddhimaranjan2753]

9.14 can someone show the calculations leading upto positive infinities? The slide shown isnt enough to understand thr calc.

[@JayantBB78]

Where were you when I was in Jr. College? Thanks a million for your efforts in making these videos. Though I am poor in maths (actualy in most of the subjects), after physics, maths is the subject I love.

[@Randomstuff-wx2ku]

Same

[@sudarshanreddyp776]

Mam 9:41 why both are equal?

[@jsprasad9110]

Thanks a lot

[@saiprasadchintakindi7596]

Mam please make a video on how formula of differentiation are derived

[@AmitKumar-er6fz]

So much thank you

[@VishalGupta_1829]

Finally I understand the meaning of cusp🤩🤩

[@shwetasingh165]

Best series for understanding calculus

[@InfinityLearn_NEET]

Glad you liked it! Please subscribe to our channel: bit.ly/DontMemoriseKZbin Happy Learning :)

[@vsalukir7019]

I can see that negative infinity and positive infinity are not the same, but while approaching a negatively infinite slope and a positively infinite slope, it seems to me that they are the same at the limit - namely they are vertical.

[@kushalm4392]

But they are in opposite directions

[@teen_python_go9947]

10:50 not always, for e.g. the derivative of 2x^2 is 4x, this is also a function in x but say f(x) = 5x. Here, the derivative of this function is 5 which is a constant and is not a function of x. Hence, it is not always possible that the derivative of a function is a function itself as well.

[@howlu9086]

That's still a function...

[@curiousminds1029]

please let me know the pricing plans for the courses of your websites.

[@joshsebastian7209]

It depends on what the function is given. If the function is applied to vertical-line test and the line meet at most one point, then it is a function. But if the function have at least 2 points which are collinear vertically, then it isn't a function.

[@aminnima6145]

Trigonometry plaise ❤️❤️❤️ your work is gorgeous

[@Krishnan172]

At 6:42, should it the tanget direction be same as 1st case as the graph is getting generated in 1st and 4th quadrant?

[@curiousminds1029]

as mentioned earlier the derivative is the rate of change of y with respect to x at delta x and it was also equal to slope and slope of a function is the ratio of rise over run so derivative( slope of function) is not the function itself.

[@gardening_vibes]

Nice. But whats the answer to the question at the ending?

[@topiado2073]

could you please explain me, at 3:10,, how does del(x)=h is tenses to zero,, since here x only zero value here

[@nandkishorugale2993]

You are awesome

[@r.malleshpeddapalli3151]

Please , please, please !!! make a video on permutations and combinations

[@disableblue883]

Best videos for differentiation. One question, does the tangent have direction? is it a vector? as one was approaching -Infinity other +Infinity

[@nothingspecial7399]

its scaler

[@crickettrendzz5477]

@@nothingspecial7399 Ooh

[@curiousminds1029]

yeah exactly it is a scaler quantity not vector so it doesnot have a particular direction so it isn't a vector.

[@usama57926]

9:48 I think you forgot to put (-h) in 2nd case where Δx → negative 0

[@virtualmagic5489]

h is in the denominator. so it will just be the opposite.

[@virtualmagic5489]

sorry, that I typed it here.

[@unknownguy2092]

butt. lol

[@snipesnipe6198]

Awesome

[@paulmadmonkeyman2822]

If f of x does not exist at 0 wat happens to a straight line that at any angle greater than 0 degrees goes through a value of zero. There is no slope at that point only greater or less than zero?

[@stimulantdaimamld2099]

great

[@eduardocontreras3878]

The derivate of a function would not be a function itself, I mean, we can define it as a function but it would not be a function related to the graph of the problem. The derivative is the rate of change in a specific point in the graph so it is the SLOPE of a line, and that line IS a function. Therefore the derivative is the slope of the tangent line´s function. Plz, correct me if I am wrong. The derivative of y=x(squr)2 is 2x. So using the y2-y1 = m(x2-x1) formula with any given point, would give us the tangent line to that point.

[@user-ur6vz5ue5r]

I all ready understand in class ,but nice🤓🤓

[@golumandal4836]

At 9:19 , 1/h^1/3 should be 1/h^2/3 according to the calculations . Please check ???

[@MrMarkgyuro]

no way, because you divide by h^3/3. after simplification remains h^0 / h^1/3 = 1 / h^1/3

[@moazamkhan]

​@@MrMarkgyuro wtf are you talking about?

[@zorak0044]

10:46 I don`t know why but Yes !!

[@akshyatshah5345]

when h tends to zero the average rate should approach a smaller postive number right? please clear my doubt at 3:22

[@virtualmagic5489]

h is in the denominator. so it will just be the opposite.

[@akshyatshah5345]

@@virtualmagic5489 can u explain me the two conditions specified in part 9:37

[@mordecairugag9873]

In 2:42 is the -h^2/3 /-h = -h^2/3-3/3 and therefore = -1/h^1/3? But isn't it suppose to be positive since -h^2/3 /-h will cancel out the negative sign.

[@user-uq5qm7ym5j]

My question exactly

[@pahandulanga1039]

If a the slope of a vertical line is dy/dx where dx = 0(which is undefined), then why don't we use limits to find the value of the slope?

[@daffysakura9069]

THE SLOPE OF VERTICAL LINE IS INFINITY not defined OK GOOD BUT,, Limits will give us approximate value of the slope and not the EXACT VALUE of it.AND the EXACT value is NOTdefined at the critical point therefore the derivative is undefined and hence we cant use limits to find exact values of slopes AT X=0 ON CURVES SHOWING VERTICAL LINES ON SHARP turns ,, and is not in the existence as it will either approach a very v v large/small no. AND U KNOW WHAT..........................................................................................................................................................................................................................................................BASICALLY I FORGOT THE PUNCH LINE AND TRYNNA RECALL......................................................................................BUT COULDN"t SRRY VRO ?

[@gannavarapumanikumar611]

Yes

[@juswanth.t133]

NiCE

[@kalidas996]

Am I wrong? At 6:53 to say tangent line doesn't exist will be wrong as we can draw a tangent at both Vertical Cusp and Vertical tangent...what we cannot evaluate is at what rate it is changing i.e that's what a differentiation at a point suppose to say...

[@mohammadbenrebia1078]

👌❤

[@kingonthego4359]

Yes it is a fuction

[@peoplemy9066]

Plz re check remainder videos

[@peoplemy9066]

Mistakes in videos

[@vimalkumarmanivannan1968]

Yes derivative of a fn is also a fn

[@yuxuanlin7882]

love your voice than your math

[@virtualmagic5489]

Yes as it passes the vertical line test......

[@12.devanshdixit6-c9]

Yes, the derivative of the function will also be a function

[@papg8283]

The last derivative formula is wrong because it is written that from the left the approaching limit of z(x)=x^(1/3) that is z(0-h)-x(0)/-h is equal to -h^(-2/3) and the positive side approaching limit derivative actual value is h^(-2/3) approaching both to 0 we get negative and positive infinity respectively

[@ad_cy6303]

👍👍👍👏👏👏👏👏

[@mdmia1526]

yes yes yes yes

[@user-wt2dq5yt9h]

Yes I think the derivative is another function

[@miteshmer7080]

May be yes I think that derivatives are also a function

[@periyavarchinnavar492]

I Think it's e^x

[@ranjitdiablo9110]

Why is you Merch so expensive? I wish I could buy one hoodie. But it costs more than 2000 rupees.

[@nirmalshah3718]

Yes, derivative of fn its a fn

[@HeartistMurali]

You lost grip on your teaching by lesson 9.......Now, you are teaching like any other mathematics teacher....

[@umaprajapati4692]

something is infinite does not mean that it do not exist ....in condition of cusp derivative exist which is infinite . Your concept is not correct 🙂

[@mugeshk5569]

L hospital rule ?

[@user-xd3ns4bz6t]

أعوذ بالله من الشيطان الرجيم ولله جنود السماوات والأرض وكان الله عزيزا حكيما

[@mohammadghanem2185]

I just want to say, that ending every sentence with a crescendo tone does not help the narrator and distracts the listener deeply.

[@theprogrammer8315]

1st comment real math lovers only

[@mintusaren895]

You are here. Do not reply.