Cambridge University Entrance Exam Tricks | Find (a,b)=?

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Super Academy

Super Academy

Күн бұрын

Пікірлер: 15
@KeyserTheRedBeard
@KeyserTheRedBeard 26 күн бұрын
Great video, Super Academy. Looking forward to seeing your next upload from you. I smashed the thumbs up button on your content. Keep up the fantastic work! Your breakdown of the quadratic equations was really clear. Could you elaborate on how you approach factoring in more complex scenarios?
@superacademy247
@superacademy247 26 күн бұрын
Thanks and sure. I'll work on factoring tough math questions 💡🥰😎😋😋💯
@raghvendrasingh1289
@raghvendrasingh1289 27 күн бұрын
a^2 - b^2 = b - a a+b = -1 because a and b are unequal now b = a^2 - 183 hence a^2+a -182 = 0 (a+14)(a-13) = 0 if a = - 14 then b= 13 if a = 13 then b = - 14
@tassiedevil2200
@tassiedevil2200 27 күн бұрын
This seems much more direct.
@superacademy247
@superacademy247 27 күн бұрын
Thanks for sharing 👏🙏🤩💕🙏
@FirstLast-n5b
@FirstLast-n5b 27 күн бұрын
Exactly what I did. What to do here for 14 minutes???????? NB to be complete you have missed one step. After a^2-b^2=b-a it is good to say => (a-b)(a+b)=-(a-b) => a+b=-1
@tassiedevil2200
@tassiedevil2200 27 күн бұрын
Since the initial equations are unchanged by exchanging a and b it is hardly surprising the two roots for your final quadratic are the solution pair.
@superacademy247
@superacademy247 27 күн бұрын
That's a great observation! 💯You're right - that's a key insight. 🙏
@nikolayplatnov5148
@nikolayplatnov5148 27 күн бұрын
If a is not equal to b, then a+b=-1. Then its,easy 7:55 to resolve a square equation.
@RyanLewis-Johnson-wq6xs
@RyanLewis-Johnson-wq6xs 27 күн бұрын
a^2=b+183 b^2=a+183 (a,b)=(13,-14) or (a,b)=(-14,13)
@sergiykanilo9848
@sergiykanilo9848 20 күн бұрын
a^2-b^2 =b-a => (a-b)(a+b) =-(a-b) => a+b=-1 => b = -a-1 a^2 - b - 183 =0 => a^2 + a - 182 =0 a = ( -1 (+/- ) 27 )/2 = { -14, 13 } b = -a -1 = { 13, -14 }
@cabasantbab
@cabasantbab 27 күн бұрын
A 14 B - 13
@RyanLewis-Johnson-wq6xs
@RyanLewis-Johnson-wq6xs 27 күн бұрын
It’s in my head
@elliotlambert3817
@elliotlambert3817 26 күн бұрын
A and B have to be = the equations are =
@prollysine
@prollysine 27 күн бұрын
(a-13)(a^3+13a^2-197a-2562)=0 , a=13 , b=a^2-183 , b=-14 , a^3+13a^2-197a-2562=0 , (a+14)(a^2-a-183)=0 , a= -14 , b=13 , sulu , (a,b) = (13 , -14) or (-14 , 13) , / a^2-a-183=0 , a= (1+/-V(1+4*183))/2 , a=(1+V733)/2 , b=(1+V733)/2 , ---- a=(1-V733)/2 , b=(1-V733)/2 , a=b , not a solu , / ,
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