4 lines is all it took, LHS=2 cos2X.cosX + 2 cos4XcosX =2cosX(cos2X+cos4X) =2cosX(2cos3XcosX) =4cos3Xcos^2 X =RHS
@jillian909817 сағат бұрын
Can you explain how you got ur first line of working pls
@peace286317 сағат бұрын
@@jillian9098 So basically what I did was just took 2cos 3X separately, so you get cosX + cos3X + cos3X + cos5X. The reason for that was I saw it had cosX in the answer , when we apply the addition rule we get a common 2cos X which we can take out
@Pramittt4 күн бұрын
15 mins for a question is crazy
@NeilDoesMaths3 күн бұрын
You guys have it easy rn
@KushagraSaxena-j3p3 күн бұрын
I got another solution Cosx + cos5x+ 2cos3x =2cos((5x+x)/2)cos((5x-x)/2)+ 2cos3x =2cos 3x cos2x+ 2cos3x =2cos3x(cos2x+1) =2cos3x((2(cosx)^2)-1+1) =4cosx^2.cos3x
@NeilDoesMaths3 күн бұрын
This is far quicker but unfortunately not in the A-Level specification anymore
@KushagraSaxena-j3p3 күн бұрын
But sir as we already got the solution,and there's no mistake in this so what's the need to worry about specifications?
@asterecho21193 күн бұрын
FYI take cosx +xos3x +cos3x+cos5x and solve it’ll be much easier
@Pramittt4 күн бұрын
clipped 7:24
@NeilDoesMaths3 күн бұрын
Oh hell nahhhhh 😂😂😂😂
@kealebogagalempoloke4 күн бұрын
Sir can you please do tutorial on the whole topic of trig identies
@NeilDoesMaths3 күн бұрын
Yep I'll be releasing over time
@kealebogagalempoloke2 күн бұрын
@NeilDoesMaths thank you sir coz l do add maths and its giving me quite a challenge
@SaarthShah-113 күн бұрын
I have a shorter soln, cud any1 guide me how to contact Mr.Neil?
@MuzammilMirza-cl8ys3 күн бұрын
Me also
@oscarandresdiazgonzalez69823 күн бұрын
Thank you bro, follow doing this bro, follow your dream