Centripetal Acceleration Derivation

[@tigersharma1443]

This channel offers best explanations on youtube. Thanks so much , Love respect from India

[@FlippingPhysics]

You are very welcome.

[@AyalaMrC]

Wonderful. Loved how you took it from AP1 up to APC by finding the value for the magnitude.

[@FlippingPhysics]

Thanks. I love being able to actually show this to students. I look forward to sharing it with my non-APPhysicsC students as well. I _always_ get asked about the direction of centripetal acceleration and now I have a video which shows exactly how it is derived. Quite happy about it. 😀

[@BoZhaoengineering]

This is the most missing part in my classic physics. Thank you!

[@abanoubgamieel32]

Thanks mr. P. You're fantastic teacher.

[@mr.ahlaguchiha2770]

god knows how much we are a part of or even at different continents but I still find that your explications are rather better than my college professors, Thank you so much also I really appreciate the other characters' questions it is really keeping me on track and asking the same question as what we might've asked. 😄

[@FlippingPhysics]

That is wonderful that I can help you learn physics from a different continent!

[@adityachauhan4895]

Sir you are the best

[@julielangenbrunner9212]

Great video! I expect that the animations in the diagrams are going to be really helpful for students.

[@julielangenbrunner9212]

Also I really appreciate the distinction between vectors and scalars here (and also the quick mention of why we still call it "v" even though it's now just speed).

[@FlippingPhysics]

Thanks. Your insistence has helped me to be more careful and clear like that!

[@richardgray8593]

Since I can't imagine how long it takes to produce one of these videos, I would ask you to tell me. It must be some sort of labor of love. Just your three alter egos alone must add hours to the process. I would never have the patience myself. I might be too ADHD.

[@FlippingPhysics]

Thanks for the love, my friend. And, rather than tell you how long it takes to make one of these videos, let me show you: www.flippingphysics.com/making-a-video.html

[@richardgray8593]

@@FlippingPhysics Thanks for the link. Two hours per minute. YIKES! And that's with you knowing what you are doing.

[@julielangenbrunner9212]

at 4:43, you say "radius of the chip" instead of "position." I think it should be "position," but the diagram makes it clear what you mean so it isn't too important to me.

[@julielangenbrunner9212]

Oh and you definitely say "position" shortly after, so now I really don't care.

[@FlippingPhysics]

I had noticed that as well in post, however, it also felt it was clear enough as is.

[@divyanshkhandal.8702]

Amazing

[@pictureking1958]

but why theta is same. is there any theorem for that, please explain this. everyone explains the derivation but no one explains this theorem.

[@siddhantrane3334]

That’s because the v initial and v final are both tangent to the circle and the triangle formed is isosceles. If the angle subtended at the centre is theta then the remaining ones are (pi-theta)/2 now because the tangent line is at pi/2 or 90 degrees to the radius you subtract pi-theta)/2 from pi/2 to get the angle we want which is theta!

[@MohammadAlshahrani]

Those group of students ruined the explanation

[@djwilliams8]

You know it's all him, right?